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### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the count of employees for each religion with the designation "Network Engineer" at the Pune branch?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Network Engineer' AND e.BranchName = 'Pune' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees based on religion with the designation "Process Coordinator" in the Finance department?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Process Coordinator' AND e.DeptName = 'Finance' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you share the count of employees for each religion with the designation "Programming Engineer" at the Bangalore branch?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Programming Engineer' AND e.BranchName = 'Bangalore' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the breakdown of employees based on religion with the designation "Sales Manager" in the Software Development department at the Haridwar location?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Sales Manager' AND e.DeptName = 'Software Development' AND e.BranchName = 'Haridwar' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion, designated as "BA," have a CTC greater than 5 Lakh?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'BA' AND e.CTC > 500000 GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the employee count for each religion among "HR Heads" in the IT department at the Germany location.
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'HR Head' AND e.DeptName = 'IT' AND e.BranchName = 'Germany' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you disclose the number of employees for each religion holding the designation "Clerk" in the Customer Service department at the Noida branch with a CTC less than 7 Lakh?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Clerk' AND e.DeptName = 'Customer Service' AND e.BranchName = 'Noida' AND e.CTC < 700000 GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion, designated as "Consultants," are currently single in the Product department at the Pune office?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Consultant' AND e.DeptName = 'Product' AND e.BranchName = 'Pune' AND e.MaritalStatusName = 'Single' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee distribution for each religion among "HR Recruiters" in the Creative Services department at the Haridwar location with a CTC between 5 Lakh and 10 Lakh?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'HR Recruiter' AND e.DeptName = 'Creative Services' AND e.BranchName = 'Haridwar' AND e.CTC BETWEEN 500000 AND 1000000 GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the count of employees for each religion who are "Process Coordinators" in the Operations department at the Bangalore branch with a CTC equal to 8 Lakh.
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Process Coordinator' AND e.DeptName = 'Operations' AND e.BranchName = 'Bangalore' AND e.CTC = 800000 GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee count for each religion among "Programming Engineers" in the Sales and Marketing department at the Pune office who are Indian?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Programming Engineer' AND e.DeptName = 'Sales and Marketing' AND e.BranchName = 'Pune' AND e.Nationality = 'Indian' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you disclose the number of employees for each religion holding the designation "Network Engineer" in the IT department at the Noida branch who are Indian and have a CTC greater than 10 Lakh?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Network Engineer' AND e.DeptName = 'IT' AND e.BranchName = 'Noida' AND e.Nationality = 'Indian' AND e.CTC > 1000000 GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion, designated as "Sales Managers," are currently single in the Finance department at the Haridwar location who are Indian?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Sales Manager' AND e.DeptName = 'Finance' AND e.BranchName = 'Haridwar' AND e.MaritalStatusName = 'Single' AND e.Nationality = 'Indian' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee distribution for each religion among "Consultants" in the HR-ADMIN department at the Germany location who are Indian and have a CTC less than 7 Lakh?
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Consultant' AND e.DeptName = 'HR-ADMIN' AND e.BranchName = 'Germany' AND e.CTC < 700000 AND e.Nationality = 'Indian' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the count of employees for each religion who are "BA" in the Customer Service department at the Bangalore branch with a CTC between 5 Lakh and 10 Lakh and are Indian.
### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'BA' AND e.DeptName = 'Customer Service' AND e.BranchName = 'Bangalore' AND e.CTC BETWEEN 500000 AND 1000000 AND e.Nationality = 'Indian' GROUP BY Religion'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job title who are Indian?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.Nationality = 'Indian' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total count of employees for each job title who are Indian and have a CTC greater than 8 Lakh?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.Nationality = 'Indian' AND e.CTC > 800000 GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job title who are Indian and work in the Sales and Marketing department at the Pune office?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.Nationality = 'Indian' AND e.DeptName = 'Sales and Marketing' AND e.BranchName = 'Pune' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the employee count for each job title who are Indian and currently single in the Finance department at the Haridwar location.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.Nationality = 'Indian' AND e.MaritalStatusName = 'Single' AND e.DeptName = 'Finance' AND e.BranchName = 'Haridwar' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job title who are Indian and work in the IT department at the Bangalore branch with a CTC between 6 Lakh and 12 Lakh?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.Nationality = 'Indian' AND e.DeptName = 'IT' AND e.BranchName = 'Bangalore' AND e.CTC BETWEEN 600000 AND 1200000 GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee count for each job title at the Haridwar branch with the designation "Consultant"?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName = 'Consultant' AND e.Status = 1 AND e.BranchName = 'Haridwar' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job title at the Bangalore branch in the Sales and Marketing department?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Sales and Marketing' AND e.BranchName = 'Bangalore' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the employee count for each job title at the Noida branch in the Product department.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Product' AND e.BranchName = 'Noida' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of employees for each job title at the Germany branch who are designated as "HR Head"?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName = 'HR Head' AND e.Status = 1 AND e.BranchName = 'Germany' GROUP |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job title at the Pune branch in the Sales and Marketing department?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Sales and Marketing' AND e.BranchName = 'Pune' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the employee count for each job title at the Noida branch in the IT department.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'IT' AND e.BranchName = 'Noida' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the male employee counts for each job title at the Germany branch in the HR-ADMIN department?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'HR-ADMIN' AND e.BranchName = 'Germany' AND e.Gender = 'Male' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of female employees for each job title at the Bangalore branch in the Software Development department?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Software Development' AND e.BranchName = 'Bangalore' AND e.Gender = 'Female' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job title at the Pune branch who have a CTC greater than 10 Lakh?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.CTC > 1000000 GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide me with the count of employees for each job title at the Noida branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the employee count for each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of employees for each job title at the Haridwar branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide me with the employee count for each job title at the Germany branch.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job title at the Bangalore branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide me with the count of male employees who are married for each job title at the Noida branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.Gender = 'Male' AND e.MaritalStatusName = 'Married' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the count of female employees who are single for each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.Gender = 'Female' AND e.MaritalStatusName = 'Single' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of married male employees for each job title at the Haridwar branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.Gender = 'Male' AND e.MaritalStatusName = 'Married' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide me with the count of married female employees for each job title at the Germany branch.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.Gender = 'Female' AND e.MaritalStatusName = 'Married' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many single male employees hold each job title at the Bangalore branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.Gender = 'Male' AND e.MaritalStatusName = 'Single' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you disclose the number of single female employees for each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.Gender = 'Female' AND e.MaritalStatusName = 'Single' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of single male employees for each job title at the Noida branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.Gender = 'Male' AND e.MaritalStatusName = 'Single' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the total number of married male employees for each job title at the Germany branch.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.Gender = 'Male' AND e.MaritalStatusName = 'Married' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of married female employees for each job title at the Bangalore branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.Gender = 'Female' AND e.MaritalStatusName = 'Married' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the current count of single female employees for each job title at the Haridwar branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.Gender = 'Female' AND e.MaritalStatusName = 'Single' GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you disclose the number of single employees (male or female) for each job title at the Pune branch?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND (e.Gender = 'Male' OR e.Gender = 'Female') AND (e.MaritalStatusName = 'Single' OR e.MaritalStatusName = 'Married') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of employees (male or female) for each job title at the Noida branch, regardless of their marital status?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND (e.Gender = 'Male' OR e.Gender = 'Female') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the total number of employees (male or female) for each job title at the Germany branch, irrespective of their marital status.
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND (e.Gender = 'Male' OR e.Gender = 'Female') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees (male or female) for each job title at the Bangalore branch without considering their marital status?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND (e.Gender = 'Male' OR e.Gender = 'Female') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the current count of employees (male or female) for each job title at the Haridwar branch, regardless of their marital status?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND (e.Gender = 'Male' OR e.Gender = 'Female') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the current count of employees (male or female) for each job title at the Haridwar branch, regardless of their marital status?
### Response: SELECT DesignationName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.DesignationName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND (e.Gender = 'Male' OR e.Gender = 'Female') GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide me with the number of employees in each departmental group at Bangalore, Germany, Haridwar, Noida, and Pune branches.
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS employeecount
FROM employeeDetails e
WHERE e.DeptName IS NOT NULL AND e.Status = 1 AND e.BranchName IN ('Bangalore', 'Germany', 'Haridwar', 'Noida', 'Pune')
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the total number of employees in the IT department at Noida and Pune branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Noida', 'Pune') AND status = 1
AND DeptName = 'IT'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the overall count of employees in the Sales and Marketing department at Haridwar and Germany branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Haridwar', 'Germany') AND status = 1
AND DeptName = 'Sales and Marketing'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there in the HR-ADMIN department at the Noida and Pune branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Noida', 'Pune') AND status = 1
AND DeptName = 'HR-ADMIN'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total number of employees in the Operations department in Germany and Haridwar branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Germany', 'Haridwar') AND status = 1
AND DeptName = 'Operations'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the combined count of employees in the Software Development department at Bangalore, Germany, and Noida branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Bangalore', 'Germany', 'Noida') AND status = 1
AND DeptName = 'Software Development'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are actively engaged in the Customer Service department at Haridwar and Pune branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Haridwar', 'Pune') AND status = 1
AND DeptName = 'Customer Service'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the total number of employees in the Finance department at each branch.
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE status = 1 AND DeptName = 'Finance'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the overall employee counts for the Product department at Bangalore, Haridwar, and Pune branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Bangalore', 'Haridwar', 'Pune') AND status = 1
AND DeptName = 'Product'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current total count of employees in the Creative Services department at the Noida branch?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName = 'Noida' AND status = 1
AND DeptName = 'Creative Services'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you disclose the total staffing level for the Customer Service department in Pune and Noida branches?
### Response: SELECT DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Pune', 'Noida') AND status = 1
AND DeptName = 'Customer Service'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee count for each department at the Noida, Germany, and Pune branches?
### Response: SELECT BranchName, DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Noida', 'Germany', 'Pune') AND status = 1
GROUP BY BranchName, DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee count for each department at the Haridwar, Pune, and Noida branches?
### Response: SELECT BranchName, DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Haridwar', 'Pune', 'Noida') AND status = 1
GROUP BY BranchName, DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees does each department have at the Pune, Germany, and Noida branches?
### Response: SELECT BranchName, DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Pune', 'Germany', 'Noida') AND status = 1
GROUP BY BranchName, DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee distribution for each department at the Germany, Pune, and Noida branches?
### Response: SELECT BranchName, DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Germany', 'Pune', 'Noida') AND status = 1
GROUP BY BranchName, DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the counts of employees for each department at the Noida, Bangalore, and Haridwar branches?
### Response: SELECT BranchName, DeptName, COUNT(DISTINCT EmployeeId) AS EmployeeCount
FROM employeeDetails
WHERE BranchName IN ('Noida', 'Bangalore', 'Haridwar') AND status = 1
GROUP BY BranchName, DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees at the Noida branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Noida' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees at the Germany branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Germany' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees at the Haridwar branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Haridwar' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees at the Pune branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Pune' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees at the Bangalore branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Bangalore' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees at the Mumbai branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Mumbai' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees at the Chennai branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Chennai' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees at the Delhi branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Delhi' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees at the Hyderabad branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Hyderabad' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees at the Kolkata branch?
### Response: SELECT BranchName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE BranchName = 'Kolkata' AND status = 1
GROUP BY BranchName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees in the HR-ADMIN department?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'HR-ADMIN' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees in the Sales and Marketing department?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Sales and Marketing' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees in the Software Development department?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Software Development' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees with the designation "Consultant"?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Consultant' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees with the designation "Programming Engineer"?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Programming Engineer' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees with the designation "Sales Manager"?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Sales Manager' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees under Reporting Manager "Abhijeet Sunil Bhavsar"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Abhijeet Sunil Bhavsar' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees under Reporting Manager "Aditya Jha"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Aditya Jha' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees under Reporting Manager "Alok Awasthi"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Alok Awasthi' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees in the Customer Service department at the Noida branch?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Customer Service' AND BranchName = 'Noida' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees in the Finance department at the Haridwar location?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Finance' AND BranchName = 'Haridwar' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees in the IT department at the Pune office?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'IT' AND BranchName = 'Pune' AND status = 1
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees with the designation "Network Engineer" in Germany?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Network Engineer' AND BranchName = 'Germany' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees with the designation "Process Coordinator" in Bangalore?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Process Coordinator' AND BranchName = 'Bangalore' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees with the designation "HR Head" in Pune?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'HR Head' AND BranchName = 'Pune' AND status = 1
GROUP BY DesignationName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees under Reporting Manager "Aditya"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Aditya' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees under Reporting Manager "Albert"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Albert' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees under Reporting Manager "Abhinav Nagesh"?
### Response: SELECT ReportingManagerName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE ReportingManagerName = 'Abhinav Nagesh' AND status = 1
GROUP BY ReportingManagerName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees in the Customer Service department at the Noida branch who joined before 2019-01-01?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Customer Service' AND BranchName = 'Noida' AND status = 1 AND JoiningDate < '2019-01-01 00:00:00.000'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the highest CTC for employees in the Finance department at the Haridwar location who joined before 2018-01-01?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'Finance' AND BranchName = 'Haridwar' AND status = 1 AND JoiningDate < '2018-01-01 00:00:00.000'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the highest CTC for employees in the IT department at the Pune office who joined before 2020-01-01?
### Response: SELECT DeptName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DeptName = 'IT' AND BranchName = 'Pune' AND status = 1 AND JoiningDate < '2020-01-01 00:00:00.000'
GROUP BY DeptName'' |
### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar,
IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the highest CTC for employees with the designation "Network Engineer" in Germany who joined before 2017-01-01?
### Response: SELECT DesignationName, MAX(CTC) AS HighestCTC
FROM employeeDetails
WHERE DesignationName = 'Network Engineer' AND BranchName = 'Germany' AND status = 1 AND JoiningDate < '2017-01-01 00:00:00.000'
GROUP BY DesignationName'' |