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HRMS_SQL

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### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the number of individuals with a gender classification of male and currently single in Noida? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the overall count of individuals whose gender is identified as male and married in Germany? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many individuals in your database are categorized as males and currently single in Bangalore? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total number of individuals with a male gender classification and currently married in Pune? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of single male individuals in Noida? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the total number of married male individuals in Haridwar? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Haridwar' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many male employees are actively engaged in their roles and are single at the Bangalore branch? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you share the count of married male professionals in Germany? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the real-time number of single male staff members at the Pune branch? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you disclose the total count of married male workers in Haridwar? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Haridwar' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current staffing level of single male contributors in Noida? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many married male employees are presently working in Bangalore? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the count of single male contributors in Pune? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Single' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many married male team members are presently working in Germany? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many individuals are classified as male and currently single at the Pune branch in the IT department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Single' and e.DeptName='IT' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total count of individuals identified as males and married in Haridwar in the Sales and Marketing department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Haridwar' and e.MaritalStatusName='Married' and e.DeptName='Sales and Marketing' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the number of individuals with a gender classification of male and currently single in Noida in the Operations department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' and e.DeptName='Operations' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the overall count of individuals whose gender is identified as male and married in Germany in the HR-ADMIN department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' and e.DeptName=' HR-ADMIN' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many individuals in your database are categorized as males and currently single in Bangalore in the Software Development department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Single' and e.DeptName=' Software Development' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total number of individuals with a male gender classification and currently married in Pune in the Finance department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Married' and e.DeptName=' Finance' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of single male individuals in Noida in the Product department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' and e.DeptName=' Product' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the total number of married male individuals in Haridwar in the Creative Services department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Haridwar' and e.MaritalStatusName='Married' and e.DeptName=' Creative Services' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many male employees are actively engaged in their roles and are single at the Bangalore branch in the Customer Service department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Single' and e.DeptName=' Customer Service' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you share the count of married male professionals in Germany in the IT department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' and e.DeptName=' IT' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the real-time number of single male staff members at the Pune branch in the Operations department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Single' and e.DeptName='Operations' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you disclose the total count of married male workers in Haridwar in the Sales and Marketing department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Haridwar' and e.MaritalStatusName='Married' and e.DeptName='Sales and Marketing' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current staffing level of single male contributors in Noida in the Software Development department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Noida' and e.MaritalStatusName='Single' and e.DeptName='Software Development' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many married male employees are presently working in Bangalore in the Product department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Bangalore' and e.MaritalStatusName='Married' and e.DeptName='Product' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the count of single male contributors in Pune in the Customer Service department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Pune' and e.MaritalStatusName='Single' and e.DeptName='Customer Service' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many married male team members are presently working in Germany in the Creative Services department? ### Response: select Gender, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.status=1 and e.Gender is not null and e.Gender = 'Male' and e.BranchName='Germany' and e.MaritalStatusName='Married' and e.DeptName='Creative Services' group by Gender

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee count for each branch in the IT department? ### Response: select BranchName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.BranchName is not null and e.status=1 and e.DeptName = 'IT' group by BranchName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees does each branch have in the Sales and Marketing department? ### Response: select BranchName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.BranchName is not null and e.status=1 and e.DeptName = 'Sales and Marketing' group by BranchName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee distribution for each branch in the Finance department? ### Response: select BranchName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.BranchName is not null and e.status=1 and e.DeptName = 'Finance' group by BranchName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the counts of employees for each branch in the HR-ADMIN department? ### Response: select BranchName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.BranchName is not null and e.status=1 and e.DeptName = 'HR- ADMIN' group by BranchName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee breakdown for each branch in the Customer Service department? ### Response: select BranchName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.BranchName is not null and e.status=1 and e.DeptName = 'Customer Service' group by BranchName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee count for each branch in the IT department with the designation "BA"? ### Response: SELECT BranchName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.BranchName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'IT' AND e.DesignationName = 'BA' GROUP BY BranchName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees does each branch have in the Sales and Marketing department with the designation "Clerk"? ### Response: SELECT BranchName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.BranchName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Sales and Marketing' AND e.DesignationName = 'Clerk' GROUP BY BranchName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee distribution for each branch in the Finance department with the designation "Consultant"? ### Response: SELECT BranchName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.BranchName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Finance' AND e.DesignationName = 'Consultant' GROUP BY BranchName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the counts of employees for each branch in the HR-ADMIN department with the designation "HR Head"? ### Response: SELECT BranchName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.BranchName IS NOT NULL AND e.Status = 1 AND e.DeptName = ' HR-ADMIN' AND e.DesignationName = 'HR Head' GROUP BY BranchName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the employee breakdown for each branch in the Customer Service department with the designation "HR Recruiter"? ### Response: SELECT BranchName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.BranchName IS NOT NULL AND e.Status = 1 AND e.DeptName = 'Customer Service' AND e.DesignationName = 'HR Recruiter' GROUP BY BranchName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job level at the Noida branch? ### Response: select JobLevelName, count(distinct EmployeeId) as employeecount FROM employeeDetails e where e.JobLevelName is not null and e.status=1 AND e.BranchName = 'Noida' group by JobLevelName

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide a breakdown of employee counts based on job levels at the Haridwar branch. ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees across different job levels at the Bangalore branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you share the number of employees at each job level at the Pune branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of employees at each job level in the Software Development department at the Germany location? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.DeptName = 'Software Development' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee breakdown for each job level in the Operations department at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.DeptName = 'Operations' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are currently working in the HR-ADMIN department at each job level in the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.DeptName = 'HR-ADMIN' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Provide the employee counts for each job level in the Customer Service department at the Haridwar location. ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.DeptName = 'Customer Service' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you share the total number of employees at each job level in the Finance department at the Bangalore branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.DeptName = 'Finance' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are assigned to each job level in the Product department at the Germany location? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.DeptName = 'Product' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current staffing level for each job level in the Sales and Marketing department at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.DeptName = 'Sales and Marketing' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you disclose the number of employees for each job level in the IT department at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.DeptName = 'IT' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee count for each job level under Reporting Manager Abhijeet Sunil Bhavsar at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.ReportingManagerName = 'Abhijeet Sunil Bhavsar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job level under Reporting Manager Abhinav Nagesh at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Abhinav Nagesh' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job level under Reporting Manager Abhishek Kumar at the Haridwar branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.ReportingManagerName = 'Abhishek Kumar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the breakdown of employees for each job level under Reporting Manager Aditya at the Germany location? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.ReportingManagerName = 'Aditya' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of employees for each job level under Reporting Manager Abhijeet Sunil Bhavsar at the Haridwar location? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.ReportingManagerName = 'Abhijeet Sunil Bhavsar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are assigned to each job level under Reporting Manager Abhinav Nagesh at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.ReportingManagerName = 'Abhinav Nagesh' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee counts for each job level under Reporting Manager Abhishek Kumar at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Abhishek Kumar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job level under Reporting Manager Aditya Jha at the Bangalore branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.ReportingManagerName = 'Aditya Jha' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the breakdown of employees for each job level under Reporting Manager Albert at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Albert' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job level under Reporting Manager Alok Awasthi at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.ReportingManagerName = 'Alok Awasthi' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of employees for each job level under Reporting Manager Abhijeet Sunil Bhavsar at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Abhijeet Sunil Bhavsar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee counts for each job level under Reporting Manager Abhinav Nagesh at the Haridwar branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.ReportingManagerName = 'Abhinav Nagesh' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are assigned to each job level under Reporting Manager Abhishek Kumar at the Germany location? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.ReportingManagerName = 'Abhishek Kumar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee counts for each job level under Reporting Manager Aditya Jha at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Aditya Jha' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job level under Reporting Manager Albert at the Bangalore branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.ReportingManagerName = 'Albert' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the breakdown of employees for each job level under Reporting Manager Alok Awasthi at the Noida branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.ReportingManagerName = 'Alok Awasthi' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees are there for each job level under Reporting Manager Abhijeet Sunil Bhavsar at the Pune office? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.ReportingManagerName = 'Abhijeet Sunil Bhavsar' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee counts for each job level under Reporting Manager Abhinav Nagesh at the Haridwar branch? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.ReportingManagerName = 'Abhinav Nagesh' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the current count of employees for each job level with a CTC less than 5 Lakh? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC < '500000' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee counts for each job level with a CTC between 5 Lakh and 8 Lakh? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 500000 AND 800000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job level with a CTC between 8 Lakh and 10 Lakh? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 800000 AND 1000000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee counts for each job level with a CTC greater than 10 Lakh? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC > 1000000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job level with a CTC between 10 Lakh and 1 Crore? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 1000000 AND 10000000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job level with a CTC less than 5 Lakh and are currently single? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC < 500000 AND e.MaritalStatusName = 'Single' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee counts for each job level with a CTC between 5 Lakh and 8 Lakh, considering only married employees? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 500000 AND 800000 AND e.MaritalStatusName = 'Married' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job level with a CTC between 8 Lakh and 10 Lakh and are currently single? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 800000 AND 1000000 AND e.MaritalStatusName = 'Single' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee counts for each job level with a CTC greater than 10 Lakh, considering only married employees? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC > 1000000 AND e.MaritalStatusName = 'Married' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees for each job level with a CTC between 10 Lakh and 1 Crore, considering both single and married statuses? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 1000000 AND 10000000 AND (e.MaritalStatusName = 'Single' OR e.MaritalStatusName = 'Married') GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job level with a CTC greater than 1 Crore and are currently married? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC > 10000000 AND e.MaritalStatusName = 'Married' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the count of employees for each job level with a CTC less than 5 Lakh, irrespective of their marital status? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC < 500000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the employee counts for each job level with a CTC between 5 Lakh and 8 Lakh, considering both single and married statuses? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 500000 AND 800000 AND (e.MaritalStatusName = 'Single' OR e.MaritalStatusName = 'Married') GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees hold each job level with a CTC between 8 Lakh and 10 Lakh, irrespective of their marital status? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC BETWEEN 800000 AND 1000000 GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Can you provide the employee counts for each job level with a CTC greater than 10 Lakh and are currently single? ### Response: SELECT JobLevelName, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.JobLevelName IS NOT NULL AND e.Status = 1 AND e.CTC > 1000000 AND e.MaritalStatusName = 'Single' GROUP BY JobLevelName''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees belong to each religion at the Noida branch? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees based on religion at the Haridwar branch in the Operations department? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Haridwar' AND e.DeptName = 'Operations' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees follow each religion in the Sales and Marketing department at the Pune office? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' AND e.DeptName = 'Sales and Marketing' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the count of employees for each religion in the HR-ADMIN department at the Bangalore branch? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' AND e.DeptName = 'HR-ADMIN' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the breakdown of employees based on religion in the Software Development department at the Germany location? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' AND e.DeptName = 'Software Development' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion are currently working in the Product department at the Noida branch? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' AND e.DeptName = 'Product' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees based on religion at the Pune office? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Pune' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the count of employees for each religion at the Bangalore branch? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Bangalore' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the breakdown of employees based on religion at the Germany location? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Germany' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion are currently working at the Noida branch? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.BranchName = 'Noida' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion hold the designation "BA"? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'BA' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the distribution of employees based on religion with the designation "Clerk"? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Clerk' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- Could you provide the count of employees for each religion with the designation "Consultant"? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'Consultant' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- What is the breakdown of employees based on religion with the designation "HR Head"? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'HR Head' GROUP BY Religion''

### Instruction: CREATE TABLE employeedetails (EmployeeId numeric,UserId int,UserName varchar,EmpCode varchar,title varchar,FirstName nvarchar,MiddleName nvarchar,FatherName varchar,Phone nvarchar,CellPhone nvarchar, IsMobileNumberPublic bit,OfficePhone nvarchar,Extension varchar,Email nvarchar,IsEmailIdPublic bit,AlternateEmailId varchar,QuitDate datetime,DeptName varchar,DesignationName varchar,Religion varchar,Nationality varchar,PlaceOfBirth nvarchar,BirthDate datetime,JoiningDate datetime,Gender varchar,HousePhone nvarchar,MaritalStatusName varchar,BranchName varchar,ReportingManagerName nvarchar,EmployeeGrade int,IsEmployeeExit bit,ExitDate datetime,ReasonToLeave nvarchar,IsLeavedJob bit,SocialSecurityNo nvarchar,LeaveJobDate datetime,Status int,CreatedOn datetime,UpdatedOn datetime,PFNo nvarchar,ESINo nvarchar,CTC decimal,CreatedMachineIP varchar,UpdatedMachineIP varchar,IsTDSapplicable bit,GrossPay decimal,WorkerType int,EmpExitType nvarchar,JobLevelName varchar,companyid int,branchid int) --Using valid MS SQL Server, answer the following questions for the tables provided above. -- How many employees of each religion, designated as "HR Recruiter," are currently working? ### Response: SELECT Religion, COUNT(DISTINCT EmployeeId) AS employeecount FROM employeeDetails e WHERE e.Religion IS NOT NULL AND e.Status = 1 AND e.DesignationName = 'HR Recruiter' GROUP BY Religion''