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bike_share_1 | How many subscribers have ended their trip at MLK Library and how many docks does that station have? | subscribers refers to subscription_type = 'subscribers'; ended their trip at refers to end_station_name; end_station_name = 'MLK Library'; number of docks a station have refers to dock_count; | SELECT COUNT(T1.id), T2.dock_count FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.end_station_name = 'MLK Library' AND T1.subscription_type = 'Subscriber' AND T2.dock_count = 19 | 9,100 | |
bike_share_1 | What is the average coldest temperature for the zip code of 94301 and what stations are within the zip code? Include the latitude and longitude as well. | coldest temperature refers to min_temperature_f; average coldest temperature refers = AVG(min_temperature_f); stations refers to name; latitude refers to lat; longitude refers to long; | SELECT AVG(T3.min_temperature_f), T1.long, T1.lat FROM station AS T1 INNER JOIN trip AS T2 ON T2.start_station_name = T1.name INNER JOIN weather AS T3 ON T3.zip_code = T2.zip_code WHERE T3.zip_code = 94301 | 9,101 | |
bike_share_1 | Calculate the average duration travelled by subscribers that both started and ended their trip in Mountain View City Hall and indicate the date when the station was first installed. | average duration = DIVIDE(SUM(duration), COUNT(id)); subscribers refers to subscription_type = 'subscriptions'; started and ended their trip at Mountain View City Hall refers to start_station_name = 'Mountain View City Hall' and end_station_name = 'Mountain View City Hall'; when the station was first installed refers to installation_date; | SELECT AVG(T1.duration), T2.installation_date FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.start_station_name = 'Mountain View City Hall' AND T1.subscription_type = 'Subscriber' AND T1.end_station_name = 'Mountain View City Hall' | 9,102 | |
movie_3 | What is the description of the film ACADEMY DINOSAUR? | "ACADEMY DINOSAUR" is the title of film | SELECT description FROM film WHERE title = 'ACADEMY DINOSAUR' | 9,103 | |
movie_3 | How many films have a rental duration of over 6 days? | rental duration of over 6 days refers to rental_duration > 6 | SELECT COUNT(film_id) FROM film WHERE rental_duration > 6 | 9,104 | |
movie_3 | Please list the titles of the films that are released in 2006 and have a rental rate of $2.99. | released in 2006 refers to release_year = 2006; rental rate of $2.99 refers to rental_rate = 2.99 | SELECT title FROM film WHERE release_year = 2006 AND rental_rate = 2.99 | 9,105 | |
movie_3 | Which film has the longest duration of film screening? Please give its title. | longest duration of film refers to Max(length) | SELECT title FROM film ORDER BY length DESC LIMIT 1 | 9,106 | |
movie_3 | Which film has a higher replacement cost, ACE GOLDFINGER or ACADEMY DINOSAUR? | higher replacement cost refers to Max(replacement_cost); 'ACE GOLDFIINGER' and 'ACADEMY DINOSAUR' are both the title of film | SELECT title FROM film WHERE title IN ('ACE GOLDFINGER', 'ACADEMY DINOSAUR') ORDER BY replacement_cost DESC LIMIT 1 | 9,107 | |
movie_3 | Among the films that are released in 2006, how many of them are rated Adults Only in the Motion Picture Association Film Rating? | released in 2006 refers to release_year = 2006; rated Adults Only refers to rating = 'NC-17' | SELECT COUNT(film_id) FROM film WHERE rating = 'NC-17' AND release_year = 2006 | 9,108 | |
movie_3 | How many films with the rental rate of $2.99 have the special feature of "Deleted Scenes"? | rental rate of $2.99 refers to rental_rate = 2.99; film refers to title | SELECT COUNT(film_id) FROM film WHERE rental_rate = 2.99 AND special_features = 'Deleted Scenes' | 9,109 | |
movie_3 | Please list the titles of all the films that have more than 2 special features. | more than 2 special features refers to Count(special_features) > 2 | SELECT title FROM ( SELECT title, COUNT(special_features) AS num FROM film GROUP BY title ) AS T ORDER BY T.num > 2 | 9,110 | |
movie_3 | What is the email address of the staff Jon Stephens? | SELECT email FROM staff WHERE first_name = 'Jon' AND last_name = 'Stephens' | 9,111 | ||
movie_3 | Please give the full names of all the active staff. | full name refers to first_name, last_name; active staff refers to active = 1 | SELECT first_name, last_name FROM staff WHERE active = 1 | 9,112 | |
movie_3 | In which year was the film with the highest replacement cost released? | highest replacement_cost refers to Max (replacement_cost); year refers to release_year | SELECT DISTINCT release_year FROM film WHERE replacement_cost = ( SELECT MAX(replacement_cost) FROM film ) | 9,113 | |
movie_3 | Please list the titles of the top 3 films with the highest replacement cost. | highest replacement_cost refers to Max (replacement_cost); film refers to title | SELECT title FROM film WHERE replacement_cost = ( SELECT MAX(replacement_cost) FROM film ) LIMIT 3 | 9,114 | |
movie_3 | What is the language of the film ACADEMY DINOSAUR? | "ACADEMY DINOSAUR" is the title of film; language refers to language.name | SELECT T2.name FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'ACADEMY DINOSAUR' | 9,115 | |
movie_3 | How many films are in English? | "English" is the name of language | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English' | 9,116 | |
movie_3 | Please list the titles of all the films starring the actor PENELOPE GUINESS. | SELECT T2.title FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = 'PENELOPE' AND T3.last_name = 'GUINESS' | 9,117 | ||
movie_3 | How many actors have starred in the film ACADEMY DINOSAUR? | "ACADEMY DINOSAUR" is the title of film | SELECT COUNT(T1.actor_id) FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.title = 'ACADEMY DINOSAUR' | 9,118 | |
movie_3 | Please list the full names of all the actors that have starred in the film ACADEMY DINOSAUR. | full name refers to first_name, last_name; "ACADEMY DINOSAUR" is the title of film | SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'ACADEMY DINOSAUR' | 9,119 | |
movie_3 | Among the films starring PENELOPE GUINESS, how many of them are released in 2006? | release in 2006 refers to release_year = 2006; | SELECT COUNT(T2.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.release_year = 2006 AND T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' | 9,120 | |
movie_3 | Please give the title of the film starring PENELOPE GUINESS and has the highest replacement cost. | highest replacement cost refers to Max (replacement_cost) | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.replacement_cost DESC LIMIT 1 | 9,121 | |
movie_3 | Please list the full names of all the actors that have starred in the film with the highest replacement cost. | highest replacement cost refers to Max (replacement_cost); full name refers to first_name, last_name | SELECT first_name, last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id ORDER BY T3.replacement_cost DESC LIMIT 1 | 9,122 | |
movie_3 | Among the films starring PENELOPE GUINESS, how many of them are in English? | "English" is the name of language | SELECT COUNT(T3.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN language AS T4 ON T3.language_id = T4.language_id WHERE T4.name = 'English' AND T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' | 9,123 | |
movie_3 | What is the title of the film with the longest duration time and stars PENELOPE GUINESS? | longest duration of film refers to Max(length) | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.length DESC LIMIT 1 | 9,124 | |
movie_3 | Please list the titles of all the films in the category of "Horror". | "Horror" is the name of category | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' | 9,125 | |
movie_3 | How many films are there under the category of "Horror"? | "Horror" is the name of category | SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror' | 9,126 | |
movie_3 | Please list the titles of all the films under the category of "Horror" and has a rental rate of $2.99. | "Horror" is the name of category; rental rate of $2.99 refers to rental_rate = 2.99 | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' AND T1.rental_rate = 2.99 | 9,127 | |
movie_3 | For how many times has the customer RUTH MARTINEZ rented a film? | times of rented refers to Count(rental_id) | SELECT COUNT(T2.rental_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' | 9,128 | |
movie_3 | Please list the titles of all the films that the customer RUTH MARTINEZ has rented. | SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' | 9,129 | ||
movie_3 | Among the films that the customer RUTH MARTINEZ has rented, how many of them are released in 2006? | release in 2006 refers to release_year = 2006 | SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T4.release_year = 2006 AND T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' | 9,130 | |
movie_3 | Among the films that the customer RUTH MARTINEZ has rented, what is the title of the one with the highest replacement cost? | highest replacement cost refers to Max(replacement_cost) | SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' ORDER BY T4.replacement_cost DESC LIMIT 1 | 9,131 | |
movie_3 | Please list the full names of all the customers who have rented the film with the highest replacement cost. | full name refers to first_name, last_name; highest replacement cost refers to Max(replacement_cost) | SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id ORDER BY T4.replacement_cost DESC LIMIT 1 | 9,132 | |
movie_3 | How many films rented to the customer RUTH MARTINEZ were returned in August, 2005? | returned in August, 2005 refers to year(return_date) = 2005 and month (return_date) = 8 | SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' AND STRFTIME('%m',T2.return_date) = '8' AND STRFTIME('%Y', T2.return_date) = '2005' | 9,133 | |
movie_3 | Please give the full name of the customer that have rented the most films. | full name refers to first_name, last_name; customer who rented the most film refers to Max(count(rental_id)) | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.rental_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,134 | |
movie_3 | Among the customers who have rented the film ACADEMY DINOSAUR, how many of them are active? | "ACADEMY DINOSAUR" is the title of film; customer refers to customer_id; active refers to active = 1 | SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.active = 1 AND T4.title = 'ACADEMY DINOSAUR' | 9,135 | |
movie_3 | Which film is rented for the most times by the customers? Please give its title. | film refers to title; film rented the most times refers to title where Max(Count(rental_id)) | SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1 | 9,136 | |
movie_3 | Which customer has rented more movies, RUTH MARTINEZ or LINDA WILLIAMS? | rented more movie Max(Count(customer_id)); "RUTH MARTINEZ" and "LINDA WILLIAMS" are both full name of customer | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE (T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ') OR (T1.first_name = 'LINDA' AND T1.last_name = 'WILLIAMS') GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,137 | |
movie_3 | Among all the films starring PENELOPE GUINESS, what is the title of the one with the highest rental price per day? | highest rental price per day refers to Max(Divide(rental_rate, rental_duration)) | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.rental_rate / T3.rental_duration DESC LIMIT 1 | 9,138 | |
movie_3 | What is the average replacement cost of the films under the category of "Horror"? | "Horror" is the name of category; average replacement cost = Divide (Sum(replacement_cost), Count(film_id where name = Horror)) | SELECT AVG(T3.replacement_cost) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.name = 'Horror' | 9,139 | |
movie_3 | Among all films that the customer RUTH MARTINEZ has rented, what is the percentage of it being a Music film? | music film refers to name = 'Music'; percentage = Divide (Count(film_id where name = 'Music'), Count(film_id)) * 100 | SELECT CAST(SUM(IIF(T3.name = 'Music', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id INNER JOIN inventory AS T4 ON T1.film_id = T4.film_id INNER JOIN customer AS T5 ON T4.store_id = T5.store_id INNER JOIN rental AS T6 ON T4.inventory_id = T6.inventory_id WHERE T5.first_name = 'RUTH' AND T5.last_name = 'MARTINEZ' | 9,140 | |
movie_3 | What is the average duration time of the films starring PENELOPE GUINESS? | average duration time = AVG(length) | SELECT AVG(T3.length) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' | 9,141 | |
movie_3 | What is Diane Collins' email address? | SELECT email FROM customer WHERE first_name = 'DIANE' AND last_name = 'COLLINS' | 9,142 | ||
movie_3 | Give the number of inactive customers. | inactive refers to active = 0 | SELECT COUNT(customer_id) FROM customer WHERE active = 0 | 9,143 | |
movie_3 | Who is the owner of email address "[email protected]"? Give the full name. | "[email protected]" is the email; owner refers to customer; full name refers to first_name, last_name | SELECT first_name, last_name FROM customer WHERE email = '[email protected]' | 9,144 | |
movie_3 | Give the postal code for the address No.65. | address no. 65 refers to address_id = 65 | SELECT postal_code FROM address WHERE address_id = 65 | 9,145 | |
movie_3 | State the number of addresses in the Nordrhein-Westfalen district. | number of address refers to address_id | SELECT COUNT(address_id) FROM address WHERE district = 'Nordrhein-Westfalen' | 9,146 | |
movie_3 | What is the phone number of address No.72? | address no. 72 refers to address_id = 72; phone number refers to phone | SELECT phone FROM address WHERE address_id = '72' | 9,147 | |
movie_3 | State the number of films that are 178 minutes long. | 178 min long refers to length = '178' | SELECT COUNT(film_id) FROM film WHERE length = '178' | 9,148 | |
movie_3 | Tell the special features of the film Uprising Uptown. | "UPRISING UPTOWN" is the title of film | SELECT special_features FROM film WHERE title = 'UPRISING UPTOWN' | 9,149 | |
movie_3 | What is the description of the film Artist Coldblooded? | "ARTIST COLDBLOODED" is the title of film | SELECT description FROM film WHERE title = 'ARTIST COLDBLOODED' | 9,150 | |
movie_3 | Give the detailed address for store No.2. | store no. 22 refers to store_id = 2; detailed address refers to address, address2, district | SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 2 | 9,151 | |
movie_3 | Which continent is the mother country of Clarksville city in? | "Clarksville" is the city; | SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T2.city = 'Clarksville' | 9,152 | |
movie_3 | How many actors played a role in the 2006 film whose rental duration is 7 days, rental rate is 4.99 and is 98 minutes duration? | in 2006 refers to release_year = 2006; 98 min duration refers to length = 98; number of actors refers to count(actor_id) | SELECT COUNT(T1.actor_id) FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.release_year = 2006 AND T2.rental_duration = 7 AND T2.rental_duration = 4.99 AND T2.length = 98 | 9,153 | |
movie_3 | The actor Dan Harris played in a 77 minute film with replacement cost of 9.99, what was the rating for that film? | 77 min film refers to length = 77 | SELECT T3.rating FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'DAN' AND T1.last_name = 'HARRIS' AND T3.length = 77 AND T3.replacement_cost = '9.99' | 9,154 | |
movie_3 | How many films did actor Daryl Wahlberg appear in? | SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id WHERE T2.first_name = 'DARYL' AND T2.last_name = 'WAHLBERG' | 9,155 | ||
movie_3 | Sherri Rhodes rented a film at 12:27:27 on 2005/7/28, when did she/he return that film? | rented at 12:27:27 on 2005/7/28 refers to rental_date = '2005-07-28 12:27:27' | SELECT T2.return_date FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'SHERRI' AND T1.last_name = 'RHODES' AND T2.rental_date = '2005-07-28 12:27:27' | 9,156 | |
movie_3 | Give the name of the manager staff for store No.1. | store no. 1 refers to store_id = 1; name refers to first_name, last_name | SELECT T1.first_name, T1.last_name FROM staff AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id WHERE T2.store_id = 1 | 9,157 | |
movie_3 | State the address location of store No.1. | store no. 1 refers to store_id = 1; address location refers to address, address2, district | SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 1 | 9,158 | |
movie_3 | Where does the staff Jon Stephens live? | location refers to address, address2, district | SELECT T1.address, T1.address2 FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'Jon' AND T2.last_name = 'Stephens' | 9,159 | |
movie_3 | How many addresses are there in Woodridge city? | "Woodridge" is the city | SELECT COUNT(T1.address_id) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id WHERE T2.city = 'Woodridge' | 9,160 | |
movie_3 | How many films are in English? | "English" is the name of language | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English' | 9,161 | |
movie_3 | Give the address location of Heather Morris. | address location refers to address | SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'HEATHER' AND T2.last_name = 'MORRIS' | 9,162 | |
movie_3 | Give the email address of the person who lives in "1411 Lillydale Drive". | "1411 Lillydate Drive" is the address | SELECT T2.email FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T1.address = '1411 Lillydale Drive' | 9,163 | |
movie_3 | How much money did the customer No.297 pay for the rental which happened at 12:27:27 on 2005/7/28? | customer no. 297 refers to customer_id = 297; at 12:27:27 on 2005/7/28 refers to rental_date = '2005-07-28 12:27:27'; money pay for rent refers to amount | SELECT T1.amount FROM payment AS T1 INNER JOIN rental AS T2 ON T1.rental_id = T2.rental_id WHERE T2.rental_date = '2005-07-28 12:27:27' AND T2.customer_id = 297 | 9,164 | |
movie_3 | Which category does the film Working Microcosmos belong to? | "WORKING MICROCOSMOS" is the title of film; category refers to name | SELECT T3.name FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.title = 'WORKING MICROCOSMOS' | 9,165 | |
movie_3 | Give the number of documentary films. | "Documentary" is the name of category; number of film refers to Count(film_id) | SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Documentary' | 9,166 | |
movie_3 | State the name of the category which has the most number of films. | category refers to name; most number of films refers to Max(Count(film_id)) | SELECT T.name FROM ( SELECT T2.name, COUNT(T1.film_id) AS num FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T2.name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,167 | |
movie_3 | Give the name of the film for inventory No.3479. | inventory no. 3479 refers to inventory_id = '3479'; name of film refers to title | SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.inventory_id = 3479 | 9,168 | |
movie_3 | What is the percentage more for the rental payment for store No.2 than store No.1? | store no. 1 refers to store_id = 1; store no.2 refers to store_id = 2; rental payment refers to amount; percent more = Divide (Subtract(amount where store_id = 2, amount where store_id = 1), amount where store_id = 1) *100 | SELECT CAST((SUM(IIF(T2.store_id = 2, T1.amount, 0)) - SUM(IIF(T2.store_id = 1, T1.amount, 0))) AS REAL) * 100 / SUM(IIF(T2.store_id = 1, T1.amount, 0)) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id INNER JOIN store AS T3 ON T2.store_id = T3.store_id | 9,169 | |
movie_3 | How many times is the number of Indian cities than Italian cities? | indian refers to country = 'India'; Italian refers to country = 'Italy'; times = Divide(Count(city where country = 'India), Count(city where country = 'Italy')) | SELECT CAST(SUM(IIF(T1.country = 'India', 1, 0)) AS REAL) / SUM(IIF(T1.country = 'Italy', 1, 0)) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id | 9,170 | |
movie_3 | How many times is the number of films Gina DeGeneres acted in than Penelope Guinness? | "Gina DeGeneres" and "Penelope Guinness" are both full name of actor; times number of film = Divide (Count (film_id where first_name = 'GINA' and last_name = 'DEGENERES'), Count(film_id where first_name = 'PENELOPE' and last_name = 'GUINESS')) | SELECT CAST(SUM(IIF(T2.first_name = 'GINA' AND T2.last_name = 'DEGENERES', 1, 0)) AS REAL) * 100 / SUM(IIF(T2.first_name = 'PENELOPE' AND T2.last_name = 'GUINESS', 1, 0)) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id | 9,171 | |
movie_3 | In 2006, how many restricted films were released? | restricted refers to rating = 'R'; release refers to release_year; in 2006 refers to release_year = 2006; film refers to title | SELECT COUNT(film_id) FROM film WHERE rating = 'R' AND release_year = 2006 | 9,172 | |
movie_3 | How many actors starred in the film id 508? | SELECT COUNT(actor_id) FROM film_actor WHERE film_id = 508 | 9,173 | ||
movie_3 | What are the special features for the film "Smoochy Control"? | "SMOOCHY CONTROL" is the title of film | SELECT special_features FROM film WHERE title = 'SMOOCHY CONTROL' | 9,174 | |
movie_3 | How many customers paid over the amount of 10 on August 2005? | over the amount of 10 refers to amount > 10; paid on August 2005 refers to payment_date like '2005_08%'; customer refers to customer_id | SELECT COUNT(customer_id) FROM payment WHERE SUBSTR(payment_date, 1, 7) LIKE '2005-08' | 9,175 | |
movie_3 | List the names of the films that are more than 180 minutes long. | more than 180 min long refers to length > 180; name of film refers to title | SELECT title FROM film WHERE length > 180 | 9,176 | |
movie_3 | How much is the total rental payment for the first 10 rentals? | first 10 rental refers to rental id between 1 and 10; total rental payment refers to sum(amount) | SELECT SUM(amount) FROM payment WHERE rental_id BETWEEN 1 AND 10 | 9,177 | |
movie_3 | What are the full names of all the active employees? | active employee refers to active = 1; full name refers to first_name, last_name | SELECT first_name, last_name FROM staff WHERE active = 1 | 9,178 | |
movie_3 | Who is the staff manager in store id 2? | staff manager refers to manager_staff_id | SELECT manager_staff_id FROM store WHERE store_id = 2 | 9,179 | |
movie_3 | How many rentals were returned on 5/27/2005? | return on 5/27/2005 refers to return_date = '2005-05-27'; rental refers to rental_id | SELECT COUNT(rental_id) FROM rental WHERE rental_date = '2005-05-27' | 9,180 | |
movie_3 | What are the names of the movies which Laura Brody starred in? | name of movie refers to title | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Laura' AND T1.last_name = 'Brody' | 9,181 | |
movie_3 | List the name of the films that can only be found in store id 2. | name of film refers to title | SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2 | 9,182 | |
movie_3 | What is the full name of the customer who rented movies for 7 consecutive days? | rented for 7 consecutive days refers to Subtract(return_date, rental_date) = 7; full name refers to first_name, last_name | SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN ( SELECT customer_id, COUNT(*) AS num_days FROM ( SELECT *, date(days, '-' || rn || ' day') AS results FROM ( SELECT customer_id, days, row_number() OVER (PARTITION BY customer_id ORDER BY days) AS rn FROM ( SELECT DISTINCT customer_id, date(rental_date) AS days FROM rental ) ) ) GROUP BY customer_id, results HAVING num_days = 7 ) AS T2 ON T1.customer_id = T2.customer_id | 9,183 | |
movie_3 | How many films are categorized as horror? | "Horror" is the name of category | SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror' | 9,184 | |
movie_3 | What is the name of the most rented movie? | most rented movie refers to title where Max(Count(rental_id)) | SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1 | 9,185 | |
movie_3 | What is the most common special features of science-fiction movies? | "science fiction" is the name of category; most common special features refers to Max(frequency(special_features)) | SELECT T1.special_features FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'sci-fi' ORDER BY T1.special_features DESC LIMIT 1 | 9,186 | |
movie_3 | What is the full name of the actor who starred in most movies? | full name refers to first_name, last_name; actor who starred in the most movies refers to actor_id where Max(Count(film_id)) | SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,187 | |
movie_3 | Among the films with a rental duration of 7 days, how many are comedies? | rental duration of 7 refers to rental_duration = 7; comedies refers to name = 'Comedy' | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.rental_duration = 7 AND T3.name = 'Comedy' | 9,188 | |
movie_3 | Who is the staff manager of the store with the most non-active customers? | most non-active customer refers to Max(Count(active = 0)) | SELECT T.first_name, T.last_name FROM ( SELECT T3.first_name, T3.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.store_id = T3.store_id WHERE T1.active = 0 GROUP BY T3.first_name, T3.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,189 | |
movie_3 | What is the rental price per day of the most expensive children's film? | children's film refers to name = 'Children'; average price per day of most expensive film = Max(Divide(rental_rate, rental_duration)) | SELECT T1.rental_rate FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Children' ORDER BY T1.rental_rate / T1.rental_duration DESC LIMIT 1 | 9,190 | |
movie_3 | What is the complete address of store id 1? | complete address refers to address, address2, district | SELECT T3.address, T3.address2, T3.district FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN store AS T4 ON T3.address_id = T4.address_id WHERE T4.store_id = 1 | 9,191 | |
movie_3 | How many customers are from the city of Lethbridge? | customer refers to customer_id | SELECT COUNT(T3.customer_id) FROM city AS T1 INNER JOIN address AS T2 ON T1.city_id = T2.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.city = 'Lethbridge' | 9,192 | |
movie_3 | How many cities are there in the United States? | "United States" is the country | SELECT COUNT(T2.city) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T1.country = 'United States' | 9,193 | |
movie_3 | List the names of the customers from India. | "India" is the country; name refers to first_name, last_name | SELECT T4.first_name, T4.last_name FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN customer AS T4 ON T3.address_id = T4.address_id WHERE T1.country = 'India' | 9,194 | |
movie_3 | Among the classic movies, how many movies have a rental rate of less than 1? | classic movie refers to name = 'Classics'; rental rate of less than 1 refers to rental_rate < 1; movie refers to film_id | SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T3.rental_rate < 1 AND T2.name = 'Classics' | 9,195 | |
movie_3 | What is the full name of the customer who rented the highest number of movies of all time? | full name refers to first_name, last_name; customer who rented the most film refers to Max(count(rental_id)) | SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.rental_id) AS num FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,196 | |
movie_3 | How many times was "Blanket Beverly" rented? | "BLANKET BEVERLY" is the title of film; rented times refers to count(rental_id) | SELECT COUNT(T3.rental_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id WHERE T1.title = 'Blanket Beverly' | 9,197 | |
movie_3 | What is the full name of the actor who has the highest number of restricted films? | restricted refers to rating = 'R'; highest number of film refers to Max(Count(film_id)); full name refers to first_name, last_name | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'R' GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,198 | |
movie_3 | Who are the top 5 actors with the highest number of films? List their full names and calculate the average number of films for each of the actors. | actors with highest number of films refers to actor_id with Max(Count(film_id)); full name refers to first_name, last_name; average number of film = Divide (Count(film_id), 5) | SELECT T.first_name, T.last_name, num FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 5 | 9,199 |
Subsets and Splits