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cookbook | How many servings does the recipe with the highest unsaturated fat have? | with the highest unsaturated fat refers MAX(SUBTRACT(total_fat, sat_fat)) | SELECT COUNT(T1.title) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.total_fat - T2.sat_fat DESC LIMIT 1 | 8,900 | |
cookbook | Among the recipes whose source is the National Potato Board, which recipe has the highest calories? | the National Potato Board is a source; the highest calories refers to MAX(calories) | SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.source = 'National Potato Board' ORDER BY T2.calories DESC LIMIT 1 | 8,901 | |
cookbook | Which recipe has the highest number of ingredients? Calculate the said recipe's total time of cooking. | the highest number of ingredients refers to MAX(ingredient_id); total time refers to recipe_id, total time of cooking refers to TOTAL(prep_min, cook_min, stnd_min) | SELECT T2.recipe_id, T1.prep_min + T1.cook_min + T1.stnd_min FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id GROUP BY T2.recipe_id ORDER BY COUNT(T2.ingredient_id) DESC LIMIT 1 | 8,902 | |
cookbook | Which ingredient appeared the most in recipes? Calculate its amount of appearance in percentage. | ingredient appeared the most in recipes refers to MAX(COUNT(ingredient_id)); calculation = MULTIPLY(DIVIDE(COUNT(MAX(ingredient_id)), COUNT(ingredient_id)), 100) | SELECT T1.name, CAST(COUNT(T2.ingredient_id) AS FLOAT) * 100 / ( SELECT COUNT(T2.ingredient_id) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id ) AS "percentage" FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id GROUP BY T2.ingredient_id ORDER BY COUNT(T2.ingredient_id) DESC LIMIT 1 | 8,903 | |
cookbook | Provide the title and total time of the recipe which has the highest possibility of gaining weight. | the highest possibility of gaining weight refers to MAX(total_fat); total time refers to recipe_id, total time refers to TOTAL(prep_min, cook_min, stnd_min) | SELECT T1.title, T1.prep_min + T1.cook_min + T1.stnd_min FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.total_fat DESC LIMIT 1 | 8,904 | |
cookbook | Which recipes contain almond extract? | almond extract is a name of an ingredient | SELECT T1.title FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.name = 'almond extract' | 8,905 | |
cookbook | List the ingredients in Tomato-Cucumber Relish. | Tomato-Cucumber Relish refers to title | SELECT T3.name FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Tomato-Cucumber Relish' | 8,906 | |
cookbook | How many ingredients are needed to prepare Idaho Potato Supreme? | Idaho Potato Supreme refers to title | SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Idaho Potato Supreme' | 8,907 | |
cookbook | Provide the ingredients that are rationed in the recipe with the highest carbohydrate content. | the highest carbohydrate content refers to MAX(carbo) | SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id INNER JOIN Nutrition AS T3 ON T3.recipe_id = T2.recipe_id WHERE T2.max_qty = T2.min_qty ORDER BY T3.carbo DESC LIMIT 1 | 8,908 | |
cookbook | Name the recipes which can lead to constipation. | can lead to constipation refers to iron > 20 | SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.iron > 20 | 8,909 | |
cookbook | Describe the ingredients in the recipe with the highest vitamin that helps vision in dim light. | the highest vitamin that helps vision in dim light refers to MAX(vitamin_a) | SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id INNER JOIN Nutrition AS T3 ON T3.recipe_id = T2.recipe_id ORDER BY T3.vitamin_a DESC LIMIT 1 | 8,910 | |
cookbook | Provide the ingredients and maximum quantities of the recipe which can serve 7 people. | can serve 7 people refers to servings = 7 | SELECT T3.name, T2.max_qty FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.servings = 7 | 8,911 | |
cookbook | Among the recipes from The California Tree Fruit Agreement, calculate the percentage of sodium-free recipes. | The California Tree Fruit Agreement is a source; calculation = MULTIPLY(DIVIDE(COUNT(sodium BETWEEN 0 AND 5 THEN recipe_id), COUNT(recipe_id)), 100) | SELECT CAST(SUM(CASE WHEN T2.sodium < 5 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.source = 'The California Tree Fruit Agreement' | 8,912 | |
cookbook | List the ingredients which measure in slices. | slices refers to unit = 'slice(s)' | SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T2.unit = 'slice(s)' | 8,913 | |
cookbook | How many recipes can be made with canned dairy? | canned dairy is a category | SELECT COUNT(*) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T1.category = 'canned dairy' | 8,914 | |
cookbook | Provide the title and total time of the recipe which can be made with only lima beans. | total time refers to total time refers to TOTAL(prep_min, cook_min, stnd_min); lima beans is a name of an ingredient | SELECT T1.title, T1.prep_min + T1.cook_min + T1.stnd_min FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.name = 'lima beans' | 8,915 | |
cookbook | Among the recipes with sea bass, how many percent of recipes can serve 10 people and above? | sea bass is a name of an ingredient; can serve 10 people and above refers to servings > = 10; calculation = MULTIPLY(DIVIDE(COUNT(servings > = 10 THEN recipe_id)), COUNT(recipe_id), 100) | SELECT CAST(SUM(CASE WHEN T1.servings >= 10 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.name = 'sea bass steak' | 8,916 | |
cookbook | How much fat does the Raspberry Chiffon Pie have? | Raspberry Chiffon Pie refers to title | SELECT T2.total_fat FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie' | 8,917 | |
cookbook | What is the percentage calories protein of Raspberry Chiffon Pie? | Raspberry Chiffon Pie refers title; percentage calories protein refers to pcnt_cal_prot | SELECT pcnt_cal_prot FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie' | 8,918 | |
cookbook | How many ingredients are required to make the Raspberry Chiffon Pie? | Raspberry Chiffon Pie refer to title | SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Raspberry Chiffon Pie' | 8,919 | |
cookbook | List the names of alcohol free recipes. | alcohol free refers to alcohol = 0 | SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.alcohol = 0 | 8,920 | |
cookbook | What is the average vitamin C amount of all cakes? | average vitamin C refers to AVG(vitamin_c); all cakes refers to title LIKE '%cake%' | SELECT AVG(T1.vitamin_c) FROM Nutrition AS T1 INNER JOIN Recipe AS T2 ON T2.recipe_id = T1.recipe_id WHERE T2.title LIKE '%cake%' | 8,921 | |
cookbook | How many dairy recipes can serve more than 10 people? | dairy recipes refers to category = 'dairy'; serve more than 10 people refers to servings > 10 | SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.category = 'dairy' AND T1.servings > 10 | 8,922 | |
cookbook | List the names of recipes that can lead to constipation. | lead to constipation refers to iron > 20 | SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.iron > 20 | 8,923 | |
cookbook | Which recipe has the highest calories? | the highest calories refers to MAX(calories) | SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.calories DESC LIMIT 1 | 8,924 | |
cookbook | How many recipes are non-dairy? | non-dairy refers to category NOT LIKE '%dairy" | SELECT COUNT(T2.recipe_id) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id INNER JOIN Nutrition AS T3 ON T3.recipe_id = T2.recipe_id WHERE T1.category NOT LIKE '%dairy%' | 8,925 | |
cookbook | List all the ingredients of Apricot Yogurt Parfaits. | Apricot Yogurt Parfaits refers to title | SELECT T3.name, T3.category FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Apricot Yogurt Parfaits' | 8,926 | |
cookbook | Identify recipes with different maximum and minimum quantities. | maximum quantities refers to max_qty; minimum quantities refers to max_qty <> min_qty | SELECT T1.title FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.max_qty <> T2.min_qty | 8,927 | |
cookbook | What ingredients does the longest cooking time recipe have? | the longest cooking time refers to MAX(cook_min) | SELECT T3.name FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id ORDER BY T1.cook_min DESC LIMIT 1 | 8,928 | |
cookbook | Calculate the percentage of recipes with no cholesterol included and have a cooking time less than 20 minutes among all recipes. | no cholesterol refers to cholestrl = 0; cooking time less than 20 minutes refers to cook_min < 20; calculation = MULTIPLY(DIVIDE(COUNT(cholestrl = 0 THEN recipe_id), COUNT(recipe_id)), 100) | SELECT CAST(SUM(CASE WHEN T1.cook_min < 20 AND T2.cholestrl = 0 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id | 8,929 | |
cookbook | Among all recipes containing cheese, what is the percentage of recipes with calories greater than 200? | cheese is a category; calories greater than 200 refers to calories > 200; calculation = MULTIPLY(DIVIDE(COUNT(calories > 200 THEN recipe_id), COUNT(recipe_id)), 100) | SELECT CAST(SUM(CASE WHEN T4.calories > 200 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id INNER JOIN Nutrition AS T4 ON T4.recipe_id = T1.recipe_id WHERE T3.category = 'cheese' | 8,930 | |
human_resources | Which employee has the highest salary? Please give his or her full name. | the highest salary refers to MAX(salary); full name = firstname, lastname | SELECT firstname, lastname FROM employee ORDER BY salary DESC LIMIT 1 | 8,931 | |
human_resources | How many emplyees have a good job performance? | good job performance refers to performance = 'Good' | SELECT COUNT(*) FROM employee WHERE performance = 'Good' | 8,932 | |
human_resources | Please list the social security numbers of the male employees with a salary of over $70,000 a year. | social security numbers refers to ssn; male employees refers to gender = 'M'; salary of over $70,000 a year refers to salary > '70000' | SELECT ssn FROM employee WHERE gender = 'M' AND CAST(REPLACE(SUBSTR(salary, 4), ',', '') AS REAL) > 70000 | 8,933 | |
human_resources | What is the required education for the position of regional manager? | required education refers to educationrequired; position of regional manager refers to positiontitle = 'Regional Manager' | SELECT educationrequired FROM position WHERE positiontitle = 'Regional Manager' | 8,934 | |
human_resources | Which position has a lower minimum salary, Account Representative or Trainee? | position of Account Representative refers to positiontitle = 'Account Representative'; position of Trainee refers to positiontitle = 'Trainee'; lower minimum salary refers to MIN(minsalary) | SELECT positiontitle FROM position WHERE positiontitle = 'Account Representative' OR positiontitle = 'Trainee' ORDER BY minsalary ASC LIMIT 1 | 8,935 | |
human_resources | In which city's office does Sandy Adams work at? | Sandy Adams is the fullname of an employee; full name = firstname, lastname; city refers to locationcity | SELECT T2.locationcity FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.lastname = 'Adams' AND T1.firstname = 'Sandy' | 8,936 | |
human_resources | Among the employees working at the office in New York, how many of them have a good job performance? | Sandy Adams is the fullname of an employee; full name = firstname, lastname; New York refers to state = 'NY'; good job performance refers to performance = 'Good'; | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.state = 'NY' AND T1.performance = 'Good' | 8,937 | |
human_resources | What is the office phone number of the location at which Sandy Adams works? | Sandy Adams is the fullname of an employee; full name = firstname, lastname; | SELECT T2.officephone FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.lastname = 'Adams' AND T1.firstname = 'Sandy' | 8,938 | |
human_resources | How many male employees work at the address 450 Peachtree Rd? | male employees refers to gender = 'M' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.address = '450 Peachtree Rd' AND T1.gender = 'M' | 8,939 | |
human_resources | How many employees work as an Account Representative? | work as an Account Representative refers to positiontitle = 'Account Representative' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Account Representative' | 8,940 | |
human_resources | How much higher is James Johnson's salary from the minimum salary of his title? | James Johnson is the fullname of an employee; full name = firstname, lastname; minimum salary refers to minsalary; calculation = SUBTRACT(salary, minsalary) | SELECT CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL) - CAST(REPLACE(SUBSTR(T2.minsalary, 4), ',', '') AS REAL) AS diff FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.lastname = 'Johnson' AND T1.firstname = 'James' | 8,941 | |
human_resources | Among the employees who are Trainees, how many of them work in New York? | Trainees is a position title; California refers to state = 'NY' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Trainee' AND T2.state = 'NY' | 8,942 | |
human_resources | Please list the full names of the employees who are working as a Trainee. | full name = firstname, lastname; trainees is a position title | SELECT T1.firstname, T1.lastname FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Trainee' | 8,943 | |
human_resources | Which employee's job position requires a higher education level, Jose Rodriguez or Sandy Adams? | Jose Rodriguez AND Sandy Adams are the fullname of employee; full name = firstname, lastname; higher education level refers to MAX(educationrequired) | SELECT T1.firstname, T1.lastname FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE (T1.lastname = 'Adams' AND T1.firstname = 'Sandy') OR (T1.lastname = 'Rodriguez' AND T1.firstname = 'Jose') ORDER BY T2.educationrequired DESC LIMIT 1 | 8,944 | |
human_resources | Please list the zip codes of the offices where all the male employees with a good job performance work at. | male employees refers to gender = 'M'; good job performance refers to performance = 'Good' | SELECT T2.zipcode FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.gender = 'M' AND T1.performance = 'Good' | 8,945 | |
human_resources | Please list the social security numbers of all the employees who work in California. | social security numbers refers to ssn; California refers to state = 'CA' | SELECT T1.ssn FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.state = 'CA' | 8,946 | |
human_resources | Among the employees who work as a Trainee, how many of them have a salary of over &20,000 a year? | Trainee is a position title; salary of over 20,000 refers to salary > '20000' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL) > 20000 AND T2.positiontitle = 'Trainee' | 8,947 | |
human_resources | What is the average salary of the employees who work as a Trainee? | average = DIVIDE( SUM(salary), COUNT(positiontitle) where positiontitle = 'Trainee'; Trainee is a position title | SELECT AVG(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) AS avg FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Trainee' | 8,948 | |
human_resources | By what percentage is the average salary of Trainees higher than the minimum salary of this postion? | AVG(salary); Trainee is a position title; minimum salary refers to minsalary; calculation = DIVIDE(SUBTRACT(AVG(salary), minsalary), minsalary) * 100 | SELECT 100 * (AVG(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) - CAST(REPLACE(SUBSTR(T2.minsalary, 4), ',', '') AS REAL)) / CAST(REPLACE(SUBSTR(T2.minsalary, 4), ',', '') AS REAL) AS per FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Trainee' | 8,949 | |
human_resources | Give the number of female employees. | number of female employees means COUNT(gender = 'F') | SELECT COUNT(*) FROM employee WHERE gender = 'F' | 8,950 | |
human_resources | State the name of the city where Jose Rodriguez works. | Jose Rodriguez is the fullname of an employee; full name = firstname, lastname; name of city refers to locationcity | SELECT T2.locationcity FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.firstname = 'Jose' AND T1.lastname = 'Rodriguez' | 8,951 | |
human_resources | In which state does Emily Wood work? | Emily Wood is the full name of an employee; full name = firstname, lastname; | SELECT T2.state FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.firstname = 'Emily' AND T1.lastname = 'Wood' | 8,952 | |
human_resources | What is the education required for David Whitehead to reach his current position? | David Whitehead is the full name of an employee; full name = firstname, lastname | SELECT T2.educationrequired FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'David' AND T1.lastname = 'Whitehead' AND T1.gender = 'M' | 8,953 | |
human_resources | How many employees are there in the "Miami" office? | Miami office refers to locationcity = 'Miami' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.locationcity = 'Miami' | 8,954 | |
human_resources | Who is the highest paid employee in "Boston"? Give the full name. | Boston refers to locationcity = 'Boston'; the highest paid employee refers to MAX(salary); full name = firstname, lastname | SELECT T1.firstname, T1.lastname FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.locationcity = 'Boston' ORDER BY T1.salary DESC LIMIT 1 | 8,955 | |
human_resources | Who is the employee in “New York City” with a good performance? Give the social security number of the employee. | New York City refers to locationcity = 'New York City'; good performance refers to performance = 'Good'; social security number refers to ssn | SELECT T1.firstname, T1.lastname, T1.ssn FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.locationcity = 'New York City' AND T1.performance = 'Good' | 8,956 | |
human_resources | How many "account representatives" are there in Chicago with a good performance? | account representatives is a position title; Chicago refers to locationcity = 'Chicago'; good performance refers to performance = 'Good' | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Account Representative' AND T2.locationcity = 'Chicago' AND T1.performance = 'Good' | 8,957 | |
human_resources | What is Kenneth Charles's position title? | Kenneth Charles is the full name of an employee; full name = firstname, lastname | SELECT T2.positiontitle FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'Kenneth' AND T1.lastname = 'Charles' | 8,958 | |
human_resources | Give the full address of the office of the highest paid manager. | the highest paid refers to MAX(salary); manager is a position title | SELECT T2.address FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Manager' ORDER BY T1.salary DESC LIMIT 1 | 8,959 | |
human_resources | What is the max salary for 'Tracy Coulter' if he/she stays on his/her position? | Tracy Coulter is the full name of an employee; full name = firstname, lastname | SELECT T2.maxsalary FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'Tracy' AND T1.lastname = 'Coulter' | 8,960 | |
human_resources | If Jose Rodriguez tried his best, how many percentage can his salary raise without changing his position? | Jose Rodriguez is the full name of an employee; full name = firstname, lastname; calculation = DIVIDE(SUBTRACT(maxsalary, salary), salary) * 100 | SELECT 100 * (CAST(REPLACE(SUBSTR(T2.maxsalary, 4), ',', '') AS REAL) - CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) / CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL) AS per FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'Jose' AND T1.lastname = 'Rodriguez' | 8,961 | |
human_resources | How many employees whose performance is poor have a salary of over $50,000 per year? | performance is poor refers to performance = 'Poor'; salary of over $50,000 refers to salary > '50000' | SELECT COUNT(*) FROM employee WHERE performance = 'Poor' AND CAST(REPLACE(SUBSTR(salary, 4), ',', '') AS REAL) > 50000 | 8,962 | |
human_resources | Who is the employee with the highest salary? Specify his/her full name. | the highest salary refers to MAX(salary); full name = firstname, lastname | SELECT firstname, lastname FROM employee WHERE CAST(REPLACE(SUBSTR(salary, 4), ',', '') AS REAL) = ( SELECT MAX(CAST(REPLACE(SUBSTR(salary, 4), ',', '') AS REAL)) FROM employee ) | 8,963 | |
human_resources | How many positions have a maximum salary of no more than US$1000,000? | maximum salary of no more than US$1000,000 refers to maxsalary < '100000'; | SELECT COUNT(*) FROM position WHERE CAST(REPLACE(SUBSTR(maxsalary, 4), ',', '') AS REAL) < 100000 | 8,964 | |
human_resources | How much is the salary of the first ever employee that was hired? | first-ever employee that was hired refers to MIN(hiredate) | SELECT salary FROM employee ORDER BY hiredate ASC LIMIT 1 | 8,965 | |
human_resources | How much is the minimum salary given to the position with the most complex work? | most complex work refers to MAX(educationrequired); minimum salary refers to minsalary | SELECT minsalary FROM position ORDER BY educationrequired DESC LIMIT 1 | 8,966 | |
human_resources | What is the full office location address where most of the employees work at? | full office location address = address, locationcity, state, zipcode; location where most employees work at refers to MAX(locationID) | SELECT T2.address, T2.locationcity, T2.state, T2.zipcode FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID GROUP BY T2.address, T2.locationcity, T2.state, T2.zipcode ORDER BY COUNT(*) DESC LIMIT 1 | 8,967 | |
human_resources | What is the average salary of all employees with a 2 year degree position? | 2 year degree refers to educationrequired = '2 year degree'; calculation = DIVIDE(SUM(salary), COUNT(positiontitle)) | SELECT AVG(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.educationrequired = '2 year degree' | 8,968 | |
human_resources | How many male Regional Managers are there? | male refers to gender = 'M'; Regional Managers is a position title | SELECT COUNT(*) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Regional Manager' AND T1.gender = 'M' | 8,969 | |
human_resources | Which position has the highest amount of poor performing employees? | poor performing employees refers to performance = 'Poor'; the highest amount of employees refers to MAX(positiontitle) | SELECT T2.positiontitle FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.performance = 'Poor' GROUP BY T2.positiontitle ORDER BY COUNT(T2.positiontitle) DESC LIMIT 1 | 8,970 | |
human_resources | Which position has the highest number of female employees with a 2 year degree? | 2 year degree refers to educationrequired = '2 year degree'; female refers to gender = 'F'; the highest number of employees refers to MAX(positionID) | SELECT T2.positiontitle FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T2.educationrequired = '2 year degree' AND T1.gender = 'F' GROUP BY T2.positiontitle ORDER BY COUNT(T2.positiontitle) DESC LIMIT 1 | 8,971 | |
human_resources | How many Account Representatives are there in Illinois with satisfying performance? | Account Representatives is a position title; satisfying performance mostly refers togood performance | SELECT COUNT(*) FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Account Representative' AND T1.performance = 'Good' AND T2.state = 'IL' | 8,972 | |
human_resources | What is the average salary of the worst performing managers? | the worst performing refers to performance = 'Poor'; manager is a positiontitle; average salary refers to AVG(salary) | SELECT AVG(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.performance = 'Poor' AND T2.positiontitle = 'Manager' | 8,973 | |
human_resources | In which state can you find the highest amount of good performing Account Representatives? | good performing refers to performance = 'Good'; Account Representatives is a positiontitle; highest amount of employee refers to MAX(positionID); | SELECT T2.state FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Account Representative' AND T1.performance = 'Good' GROUP BY T2.state ORDER BY COUNT(T2.state) DESC LIMIT 1 | 8,974 | |
human_resources | Mention the employee's full name and performance status who got the lowest in salary per year. | full name = firstname, lastname; the lowest salary refers to MIN(salary) | SELECT firstname, lastname, performance FROM employee ORDER BY salary ASC LIMIT 1 | 8,975 | |
human_resources | List the location cities in the Western states. | Western states refers to state = 'CO' OR state = 'UT' OR state = 'CA'; location cities refers to locationcity | SELECT locationcity FROM location WHERE state IN ('CO', 'UT', 'CA') | 8,976 | |
human_resources | Which city and address has zip code of above 90000? | zip code of above 90000 refers to zipcode > 90000; city refers to locationcity | SELECT locationcity, address FROM location WHERE zipcode > 90000 | 8,977 | |
human_resources | Which positions are suitable with 4 years degree education? | 4 years degree education refers to educationrequired = '4 year degree'; positions refers to positiontitle | SELECT positiontitle FROM position WHERE educationrequired = '4 year degree' | 8,978 | |
human_resources | What is the maximum salary of position "Trainer"? | maximum salary refers to maxsalary; Trainee is a positiontitle | SELECT maxsalary FROM position WHERE positiontitle = 'Trainee' | 8,979 | |
human_resources | List the full name and social security number of the account representative with average performance. | full name = firstname, lastname; social security number refers to ssn; account representative is a position title; average performance refers to performance = 'Average' | SELECT T1.firstname, T1.lastname, T1.ssn FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.performance = 'Average' | 8,980 | |
human_resources | When was Emily Wood hired? Mention her position and salary. | Emily Wood is the full name of an employee; full name = firstname, lastname; when was she hired refers to hiredate | SELECT T1.hiredate, T2.positiontitle, T1.salary FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'Emily' AND T1.lastname = 'Wood' | 8,981 | |
human_resources | What are the maximum and minimum salary range and position title of Bill Marlin? | Bill Marlin is the full name of an employee; full name = firstname, lastname; maximum salary refers to maxsalary; minimum salary refers to minsalary | SELECT T2.maxsalary, T2.minsalary, T2.positiontitle FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.firstname = 'Bill' AND T1.lastname = 'Marlin' | 8,982 | |
human_resources | List the full names, gender and positions who's location is in New York city. | full name = firstname, lastname; New York city refers to locationcity = 'New York City' | SELECT T1.firstname, T1.lastname, T1.gender, T3.positiontitle FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T2.locationcity = 'New York City' | 8,983 | |
human_resources | Mention the full name, hired date and performance status of the employee whose location is in Utah state. | full name = firstname, lastname; Utah refers to state = 'UT' | SELECT T1.firstname, T1.lastname, T1.hiredate, T1.performance FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T2.state = 'UT' | 8,984 | |
human_resources | Among the employees with poor performance, provide the managers' full names, location city, address and its zip code. | poor performance refers to performance = 'Poor'; full name = firstname, lastname; managers is a position title | SELECT T1.firstname, T1.lastname, T2.locationcity, T2.address, T2.zipcode FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T3.positiontitle = 'Manager' AND T1.performance = 'Poor' | 8,985 | |
human_resources | What is the education required to be account representative? Mention account representative full name and salary who got poor in performance status. | account representative is a position title; full name = firstname, lastname; poor performance refers to performance = 'Poor' | SELECT T2.educationrequired, T1.firstname, T1.lastname, T1.salary FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID WHERE T1.performance = 'Poor' AND T2.positiontitle = 'Account Representative' | 8,986 | |
human_resources | Write down the full name, performance status and located city of the employee who's social security number is "767-74-7373". | full name = firstname, lastname; ssn = '767-74-7373' | SELECT T1.firstname, T1.lastname, T2.state, T2.locationcity FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID WHERE T1.ssn = '767-74-7373' | 8,987 | |
human_resources | Describe the employees' full name, positions, located city and office phone number within Colorado state. | full name = firstname, lastname; Colorado state refers to state = 'CO'; positions refers to positiontitle; located city refers to locationcity; office phone number refers to officephone; | SELECT T1.firstname, T1.lastname, T3.positiontitle, T2.locationcity, T2.officephone FROM employee AS T1 INNER JOIN location AS T2 ON T1.locationID = T2.locationID INNER JOIN position AS T3 ON T3.positionID = T1.positionID WHERE T2.state = 'CO' | 8,988 | |
human_resources | Calculate the monthly average salary of the employee with highest salary. Mention his name, position title and location city. | highest salary refers to MAX(salary); name = firstname, lastname; calculation = DIVIDE(MAX(salary), 12) | SELECT SUM(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) / 12 AS avg, T1.firstname, T1.lastname , T2.positiontitle, T3.locationcity FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID INNER JOIN location AS T3 ON T1.locationID = T3.locationID WHERE CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL) = ( SELECT MAX(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) FROM employee AS T1 INNER JOIN position AS T2 ON T1.positionID = T2.positionID INNER JOIN location AS T3 ON T1.locationID = T3.locationID ) | 8,989 | |
bike_share_1 | Which trip had the longest duration? State the start and end station. | start station refers to start_station_name; end station refers to end_station_name; | SELECT start_station_name, end_station_name FROM trip WHERE duration = ( SELECT MAX(duration) FROM trip ) | 8,990 | |
bike_share_1 | What is the percentage of the trip were done by a subscriber? | subscription_type = 'Subscriber'; DIVIDE(COUNT(id where subscription_type = 'Subscriber'), COUNT(id)) as percentage; | SELECT CAST(COUNT(subscription_type) AS REAL) * 100 / ( SELECT COUNT(subscription_type) FROM trip ) FROM trip WHERE subscription_type = 'Subscriber' | 8,991 | |
bike_share_1 | State the final station of bike id 13. Which city was it at? | final station refers to end_station_name where MAX(end_date); | SELECT T2.end_station_id, T1.city FROM station AS T1 INNER JOIN trip AS T2 ON T1.name = T2.end_station_name WHERE T2.bike_id = 13 ORDER BY T2.end_date DESC LIMIT 1 | 8,992 | |
bike_share_1 | Name all the trips where the bike was borrowed and returned on a different day. State the city where the bike was returned. | the bike was borrowed and returned on a different day implies that start_date and end_date are not equal to each other; where the bike was returned refers to end_station_name; | SELECT DISTINCT T1.city FROM station AS T1 INNER JOIN trip AS T2 ON T2.start_station_name = T1.name WHERE SUBSTR(CAST(T2.start_date AS TEXT), INSTR(T2.start_date, '/') + 1) - SUBSTR(CAST(T2.start_date AS TEXT), INSTR(T2.start_date, ' ') - 5) <> SUBSTR(CAST(T2.end_date AS TEXT), INSTR(T2.end_date, '/') + 1) - SUBSTR(CAST(T2.end_date AS TEXT), INSTR(T2.end_date, ' ') - 5) | 8,993 | |
bike_share_1 | Which is the station where no bike could not be borrowed form on the 2013/11/03 02:01:01? State the location of the station. | Latitude and longitude coordinates can be used to indicate a location, where latitude refers to lat longtitude refer to long; bikes_available = 0 means no bike can be borrowed; 3/11/2013 02:01:01 refers to time; | SELECT T1.name, T1.long FROM station AS T1 INNER JOIN status AS T2 ON T2.station_id = T1.id WHERE T2.time = '2013/11/03 02:01:01' AND T2.bikes_available = 0 | 8,994 | |
bike_share_1 | Name the station and city with the most borrowed bike. | the station with the most borrowed bikes refers to MAX(start_station); | SELECT T2.start_station_name, T1.city FROM station AS T1 INNER JOIN trip AS T2 ON T2.start_station_name = T1.name GROUP BY T2.start_station_name ORDER BY COUNT(T2.start_station_name) DESC LIMIT 1 | 8,995 | |
bike_share_1 | What was the hottest temperature on the day of trip ID 4080? | the hottest temperature refers to max_temperature_f; | SELECT MAX(T2.max_temperature_f) FROM trip AS T1 INNER JOIN weather AS T2 ON T2.zip_code = T1.zip_code AND T2.date = SUBSTR(CAST(T1.start_date AS TEXT), 1, INSTR(T1.start_date, ' ') - 1) WHERE T1.id = 4080 | 8,996 | |
bike_share_1 | At what date and time did San Jose Diridon Caltrain Station have most bikes available. | San Jose Diridon Caltrain Station is the name of the station; most bikes available refers to MAX(bikes_available); | SELECT T2.time FROM station AS T1 INNER JOIN status AS T2 ON T2.station_id = T1.id WHERE T1.name = 'San Jose Diridon Caltrain Station' AND T2.bikes_available = ( SELECT MAX(T2.bikes_available) FROM station AS T1 INNER JOIN status AS T2 ON T2.station_id = T1.id WHERE T1.name = 'San Jose Diridon Caltrain Station' ) | 8,997 | |
bike_share_1 | Name all the trip on the days when it rained. State the duration of the trip | events = 'Rain'; | SELECT T1.id, T1.duration FROM trip AS T1 INNER JOIN weather AS T2 ON T2.zip_code = T1.zip_code AND T2.date = SUBSTR(CAST(T1.start_date AS TEXT), 1, INSTR(T1.start_date, ' ') - 1) WHERE T2.events LIKE '%Rain%' OR T2.events LIKE '%rain%' | 8,998 | |
bike_share_1 | List all trips where bikes were returned at location 37.331415, -121.8932. State the date the bike was borrowed. | 37.331415 and -121.8932 are latitude (lat) and longitude (long) coordinates indicating location; returned at refers to end_station_name; the date the bike was borrowed refers to start_date; | SELECT T2.end_station_name, T2.start_date FROM station AS T1 INNER JOIN trip AS T2 ON T2.end_station_name = T1.name WHERE T1.lat = 37.331415 AND T1.long = -121.8932 | 8,999 |
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