metadata

base_model: LGAI-EXAONE/EXAONE-3.5-2.4B-Instruct
base_model_relation: finetune
license: other
license_name: exaone
license_link: LICENSE
language:
  - en
  - ko
tags:
  - chat
  - abliterated
  - uncensored
  - lg-ai
  - exaone
  - exaone-deep
pipeline_tag: text-generation
library_name: transformers

huihui-ai/DeepSeek-R1-0528-Qwen3-8B-abliterated

This is an uncensored version of deepseek-ai/DeepSeek-R1-0528-Qwen3-8B created with abliteration (see remove-refusals-with-transformers to know more about it). This is a crude, proof-of-concept implementation to remove refusals from an LLM model without using TransformerLens.

ollama

You can use huihui_ai/deepseek-r1-abliterated:8b directly, Switch the thinking toggle using /set think and /set nothink

ollama run huihui_ai/deepseek-r1-abliterated

Usage

You can use this model in your applications by loading it with Hugging Face's transformers library: You can try using /no_think to toggle think mode, but it’s not guaranteed to work every time.

import torch
from transformers import AutoModelForCausalLM, AutoTokenizer, TextIteratorStreamer
from threading import Thread

model_name = "Huihui-EXAONE-Deep-2.4B-abliterated"
streaming = True    # choose the streaming option

model = AutoModelForCausalLM.from_pretrained(
    model_name,
    torch_dtype=torch.bfloat16,
    trust_remote_code=True,
    device_map="auto"
)
tokenizer = AutoTokenizer.from_pretrained(model_name)

# Choose your prompt:
#   Math example (AIME 2024)
prompt = r"""Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:
\[\log_2\left({x \over yz}\right) = {1 \over 2}\]\[\log_2\left({y \over xz}\right) = {1 \over 3}\]\[\log_2\left({z \over xy}\right) = {1 \over 4}\]
Then the value of $\left|\log_2(x^4y^3z^2)\right|$ is $\tfrac{m}{n}$ where $m$ and $n$ are relatively prime positive integers. Find $m+n$.

Please reason step by step, and put your final answer within \boxed{}."""
#   Korean MCQA example (CSAT Math 2025)
prompt = r"""Question : $a_1 = 2$인 수열 $\{a_n\}$과 $b_1 = 2$인 등차수열 $\{b_n\}$이 모든 자연수 $n$에 대하여\[\sum_{k=1}^{n} \frac{a_k}{b_{k+1}} = \frac{1}{2} n^2\]을 만족시킬 때, $\sum_{k=1}^{5} a_k$의 값을 구하여라.

Options :
A) 120
B) 125
C) 130
D) 135
E) 140
 
Please reason step by step, and you should write the correct option alphabet (A, B, C, D or E) within \\boxed{}."""

messages = [
    {"role": "user", "content": prompt}
]
input_ids = tokenizer.apply_chat_template(
    messages,
    tokenize=True,
    add_generation_prompt=True,
    return_tensors="pt"
)

if streaming:
    streamer = TextIteratorStreamer(tokenizer)
    thread = Thread(target=model.generate, kwargs=dict(
        input_ids=input_ids.to("cuda"),
        eos_token_id=tokenizer.eos_token_id,
        max_new_tokens=32768,
        do_sample=True,
        temperature=0.6,
        top_p=0.95,
        streamer=streamer
    ))
    thread.start()

    for text in streamer:
        print(text, end="", flush=True)
else:
    output = model.generate(
        input_ids.to("cuda"),
        eos_token_id=tokenizer.eos_token_id,
        max_new_tokens=32768,
        do_sample=True,
        temperature=0.6,
        top_p=0.95,
    )
    print(tokenizer.decode(output[0]))

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