IMO-Steps / imo_proofs /imo_1974_p3.lean
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import Mathlib
set_option linter.unusedVariables.analyzeTactics true
open Nat BigOperators Finset
lemma aux_1
(a : ℕ) :
¬ a ^ 22 [MOD 5] := by
intro ha₀
induction' a with n hn
. simp at ha₀
have ha₁: ¬ 02 [MOD 5] := by decide
exact ha₁ ha₀
. let b:ℕ := n % 5
have hb₀: b < 5 := by omega
have hb₁: n ≡ b [MOD 5] := by exact Nat.ModEq.symm (Nat.mod_modEq n 5)
have hb₂: (n + 1) ≡ (b + 1) [MOD 5] := by
exact Nat.ModEq.add_right 1 hb₁
have hb₃: (n + 1) ^ 2 ≡ (b + 1) ^ 2 [MOD 5] := by
exact Nat.ModEq.pow 2 hb₂
interval_cases b
. simp at *
have g₀: 12 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 12 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 42 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 42 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 92 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 92 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 162 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 162 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 252 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 252 [MOD 5] := by decide
exact g₁ g₀
lemma aux_2
(a : ℕ) :
¬ a ^ 23 [MOD 5] := by
intro ha₀
induction' a with n hn
. simp at ha₀
have ha₁: ¬ 03 [MOD 5] := by decide
exact ha₁ ha₀
. let b:ℕ := n % 5
have hb₀: b < 5 := by omega
have hb₁: n ≡ b [MOD 5] := by exact Nat.ModEq.symm (Nat.mod_modEq n 5)
have hb₂: (n + 1) ≡ (b + 1) [MOD 5] := by
exact Nat.ModEq.add_right 1 hb₁
have hb₃: (n + 1) ^ 2 ≡ (b + 1) ^ 2 [MOD 5] := by
exact Nat.ModEq.pow 2 hb₂
interval_cases b
. simp at *
have g₀: 13 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 13 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 43 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 43 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 93 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 93 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 163 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 163 [MOD 5] := by decide
exact g₁ g₀
. simp at hb₃
have g₀: 253 [MOD 5] := by
refine Nat.ModEq.trans hb₃.symm ha₀
have g₁: ¬ 253 [MOD 5] := by decide
exact g₁ g₀
lemma aux_3
(n : ℕ) :
7 ^ (2 * n + 1) ≡ 2 [MOD 5] ∨ 7 ^ (2 * n + 1) ≡ 3 [MOD 5] := by
induction' n with d hd
. simp
left
decide
. let b:ℕ := (7 ^ (2 * d + 1)) % 5
have hb: b = (7 ^ (2 * d + 1)) % 5 := by rfl
have hb₀: b < 5 := by
rw [hb]
omega
have hb₁: (7 ^ (2 * d + 1)) ≡ b [MOD 5] := by
exact ModEq.symm (mod_modEq (7 ^ (2 * d + 1)) 5)
ring_nf at *
have hb₂: 7 ^ (d * 2) * 7 * 49 ≡ b * 49 [MOD 5] := by
exact ModEq.mul hb₁ rfl
have hb₃: 7 ^ (d * 2) * 7 * 492 * 49 [MOD 5] ∨ 7 ^ (d * 2) * 7 * 493 * 49 [MOD 5] := by
cases' hd with hd₀ hd₁
. left
exact ModEq.mul hd₀ rfl
. right
exact ModEq.mul hd₁ rfl
ring_nf at hb₂
ring_nf at *
cases' hb₃ with hb₄ hb₅
. interval_cases b
. ring_nf at hb₂
have g₀: 098 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₄
have g₁: ¬ 098 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
have g₀: 4998 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₄
have g₁: ¬ 4998 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
have g₀: 983 [MOD 5] := by decide
right
refine Nat.ModEq.trans hb₂ g₀
. ring_nf at hb₂
have g₀: 14798 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₄
have g₁: ¬ 14798 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
have g₀: 19698 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₄
have g₁: ¬ 19698 [MOD 5] := by decide
exact (g₁ g₀).elim
. interval_cases b
. ring_nf at hb₂
have g₀: 0147 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₅
have g₁: ¬ 0147 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
have g₀: 49147 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₅
have g₁: ¬ 49147 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
have g₀: 98147 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₅
have g₁: ¬ 98147 [MOD 5] := by decide
exact (g₁ g₀).elim
. ring_nf at hb₂
exact Or.intro_left (7 ^ (d * 2) * 3433 [MOD 5]) hb₅
. ring_nf at hb₂
have g₀: 196147 [MOD 5] := by
refine Nat.ModEq.trans hb₂.symm hb₅
have g₁: ¬ 196147 [MOD 5] := by decide
exact (g₁ g₀).elim
lemma aux_4
(n b a : ℕ)
(k : ℝ)
-- (hk : k = √8)
-- (hb : b = ∑ k ∈ range (n + 1), (2 * n + 1).choose (2 * k + 1) * 2 ^ (3 * k))
-- (ha : a = ∑ k ∈ range (n + 1), (2 * n + 1).choose (2 * k) * 2 ^ (3 * k))
(hb₁ : ↑b = 1 / k * ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x + 1)) * k ^ (2 * x + 1))
(ha₁ : ↑a = ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x)) * k ^ (2 * x))
(hk₀ : k * k⁻¹ = 1) :
(1 + k) ^ (2 * n + 1) = ↑a + ↑b * k := by
rw [mul_comm _ k, hb₁, ← mul_assoc]
rw [← inv_eq_one_div, hk₀, one_mul, ha₁]
rw [add_comm, add_pow k 1 (2 * n + 1)]
simp
clear hb₁ ha₁ b a hk₀
let f : ℕ → ℝ := fun i => ↑((2 * n + 1).choose (i)) * k ^ i
let fs₂ := Finset.range (2 * n + 2)
-- let fs₀ : Finset ℕ := Finset.filter (fun x => Odd x) (Finset.range (2 * n + 2))
let fs₀ : Finset ℕ := fs₂.filter (fun x => Odd x)
let fs₁ : Finset ℕ := fs₂.filter (fun x => Even x)
let fs₃ : Finset ℕ := Finset.range (n + 1)
have h₀: ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x + 1)) * k ^ (2 * x + 1) =
∑ x ∈ fs₀, ↑((2 * n + 1).choose (x)) * k ^ (x) := by
have h₀₁: ∑ x ∈ fs₃, f (2 * x + 1) = ∑ x ∈ (fs₀), f x := by
refine sum_bij ?i ?_ ?i_inj ?i_surj ?h
. intros a _
exact (2 * a + 1)
. intros a ha₀
have ha₁: a ≤ n := by exact mem_range_succ_iff.mp ha₀
have ha₂: 2 * a + 12 * n + 1 := by linarith
have ha₃: (2 * a + 1) ∈ fs₂ := by exact mem_range_succ_iff.mpr ha₂
have ha₄: Odd (2 * a + 1) := by exact odd_two_mul_add_one a
refine mem_filter.mpr ?_
exact And.symm ⟨ha₄, ha₃⟩
. intros a _ b _ h₃
linarith
. intros b hb₀
use ((b - 1) / 2)
refine exists_prop.mpr ?_
have hb₁: b ∈ fs₂ ∧ Odd b := by exact mem_filter.mp hb₀
have hb₂: 1 ≤ b := by
by_contra! hc₀
interval_cases b
have hc₁: ¬ Odd 0 := by decide
apply hc₁ hb₁.2
have hb₃: Even (b - 1) := by
refine (Nat.even_sub hb₂).mpr ?_
simp only [not_even_one, iff_false, not_even_iff_odd]
exact hb₁.2
constructor
. have hb₄: b < 2 * n + 2 := by exact List.mem_range.mp hb₁.1
have hb₅: (b - 1) / 2 < n + 1 := by omega
exact mem_range.mpr hb₅
. have hb₆: 2 * ((b - 1) / 2) = b - 1 := by exact two_mul_div_two_of_even hb₃
rw [hb₆]
exact Nat.sub_add_cancel hb₂
. exact fun a _ => rfl
exact h₀₁
have h₁: ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x)) * k ^ (2 * x) =
∑ x ∈ fs₁, ↑((2 * n + 1).choose (x)) * k ^ (x) := by
have h₁₁: ∑ x ∈ fs₃, f (2 * x) = ∑ x ∈ (fs₁), f x := by
refine sum_bij ?_ ?_ ?_ ?_ ?_
. intros a _
exact (2 * a)
. intros a ha₀
have ha₁: a < n + 1 := by exact List.mem_range.mp ha₀
have ha₂: 2 * a < 2 * n + 2 := by linarith
refine mem_filter.mpr ?_
constructor
. exact mem_range.mpr ha₂
. exact even_two_mul a
. intros a _ b _ h₃
exact Nat.eq_of_mul_eq_mul_left (by norm_num) h₃
. intros b hb₀
use (b/2)
refine exists_prop.mpr ?_
have hb₁: b ∈ fs₂ ∧ Even b := by exact mem_filter.mp hb₀
constructor
. have hb₂: b < 2 * n + 2 := by exact List.mem_range.mp hb₁.1
have hb₃: (b / 2) < n + 1 := by exact Nat.div_lt_of_lt_mul hb₂
exact mem_range.mpr hb₃
. exact two_mul_div_two_of_even hb₁.2
. exact fun a _ => rfl
exact h₁₁
have h₂: ∑ x ∈ range (2 * n + 1 + 1), k ^ x * ↑((2 * n + 1).choose x) =
∑ x ∈ fs₂, ↑((2 * n + 1).choose x) * k ^ x := by
refine Finset.sum_congr (rfl) ?_
intros x _
rw [mul_comm]
rw [h₀, h₁, h₂]
have h₃: fs₂ = fs₀ ∪ fs₁ := by
refine Finset.ext_iff.mpr ?_
intro a
constructor
. intro ha₀
refine mem_union.mpr ?mp.a
have ha₁: Odd a ∨ Even a := by exact Or.symm (even_or_odd a)
cases' ha₁ with ha₂ ha₃
. left
refine mem_filter.mpr ?mp.a.inl.h.a
exact And.symm ⟨ha₂, ha₀⟩
. right
refine mem_filter.mpr ?mp.a.inl.h.b
exact And.symm ⟨ha₃, ha₀⟩
. intro ha₀
apply mem_union.mp at ha₀
cases' ha₀ with ha₁ ha₂
. exact mem_of_mem_filter a ha₁
. exact mem_of_mem_filter a ha₂
have h₄: Disjoint fs₀ fs₁ := by
refine disjoint_filter.mpr ?_
intros x _ hx₁
exact not_even_iff_odd.mpr hx₁
nth_rw 2 [add_comm]
rw [h₃, Finset.sum_union h₄]
lemma aux_5
(n b a : ℕ)
(k : ℝ)
-- (hk : k = √8)
-- (hb : b = ∑ k ∈ range (n + 1), (2 * n + 1).choose (2 * k + 1) * 2 ^ (3 * k))
-- (ha : a = ∑ k ∈ range (n + 1), (2 * n + 1).choose (2 * k) * 2 ^ (3 * k))
(hb₁ : ↑b = 1 / k * ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x + 1)) * k ^ (2 * x + 1))
(ha₁ : ↑a = ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x)) * k ^ (2 * x))
(hk₀ : k * k⁻¹ = 1) :
(1 - k) ^ (2 * n + 1) = ↑a - ↑b * k := by
rw [mul_comm _ k, hb₁, ← mul_assoc]
rw [← inv_eq_one_div, hk₀, one_mul, ha₁, sub_eq_add_neg]
rw [add_comm 1 _, add_pow (-k) 1 (2 * n + 1)]
simp
clear hb₁ ha₁ b a hk₀
let f₀ : ℕ → ℝ := fun i => ↑((2 * n + 1).choose (i)) * k ^ i
let f₁ : ℕ → ℝ := fun i => ↑((2 * n + 1).choose (i)) * (-k) ^ i
let fs₂ := Finset.range (2 * n + 2)
let fs₀ : Finset ℕ := fs₂.filter (fun x => Odd x)
let fs₁ : Finset ℕ := fs₂.filter (fun x => Even x)
let fs₃ : Finset ℕ := Finset.range (n + 1)
have h₀: ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x + 1)) * k ^ (2 * x + 1) =
- ∑ x ∈ fs₀, ↑((2 * n + 1).choose (x)) * (-k) ^ (x) := by
rw [neg_eq_neg_one_mul, Finset.mul_sum]
have h₀₁: ∑ x ∈ fs₃, f₀ (2 * x + 1) = ∑ x ∈ (fs₀), -1 * f₁ x := by
refine sum_bij ?i ?_ ?i_inj ?i_surj ?h
. intros a _
exact (2 * a + 1)
. intros a ha₀
have ha₁: a ≤ n := by exact mem_range_succ_iff.mp ha₀
have ha₂: 2 * a + 12 * n + 1 := by linarith
have ha₃: (2 * a + 1) ∈ fs₂ := by exact mem_range_succ_iff.mpr ha₂
have ha₄: Odd (2 * a + 1) := by exact odd_two_mul_add_one a
refine mem_filter.mpr ?_
exact And.symm ⟨ha₄, ha₃⟩
. intros a _ b _ h₃
linarith
. intros b hb₀
use ((b - 1) / 2)
refine exists_prop.mpr ?_
have hb₁: b ∈ fs₂ ∧ Odd b := by exact mem_filter.mp hb₀
have hb₂: 1 ≤ b := by
by_contra! hc₀
interval_cases b
have hc₁: ¬ Odd 0 := by decide
apply hc₁ hb₁.2
have hb₃: Even (b - 1) := by
refine (Nat.even_sub hb₂).mpr ?_
simp only [not_even_one, iff_false, not_even_iff_odd]
exact hb₁.2
constructor
. have hb₄: b < 2 * n + 2 := by exact List.mem_range.mp hb₁.1
have hb₅: (b - 1) / 2 < n + 1 := by omega
exact mem_range.mpr hb₅
. have hb₆: 2 * ((b - 1) / 2) = b - 1 := by exact two_mul_div_two_of_even hb₃
rw [hb₆]
exact Nat.sub_add_cancel hb₂
. intros b hb₀
ring_nf
have hb₁: (-1:ℝ) ^ (b * 2) = 1 := by
refine (neg_one_pow_eq_one_iff_even (by norm_num)).mpr ?_
rw [mul_comm]
exact even_two_mul b
rw [hb₁, mul_one]
exact h₀₁
have h₁: ∑ x ∈ range (n + 1), ↑((2 * n + 1).choose (2 * x)) * k ^ (2 * x) =
∑ x ∈ fs₁, ↑((2 * n + 1).choose (x)) * (-k) ^ (x) := by
have h₁₁: ∑ x ∈ fs₃, f₀ (2 * x) = ∑ x ∈ (fs₁), f₁ x := by
refine sum_bij ?_ ?_ ?_ ?_ ?_
. intros a _
exact (2 * a)
. intros a ha₀
have ha₁: a < n + 1 := by exact List.mem_range.mp ha₀
have ha₂: 2 * a < 2 * n + 2 := by linarith
refine mem_filter.mpr ?_
constructor
. exact mem_range.mpr ha₂
. exact even_two_mul a
. intros a _ b _ h₃
exact Nat.eq_of_mul_eq_mul_left (by norm_num) h₃
. intros b hb₀
use (b/2)
refine exists_prop.mpr ?_
have hb₁: b ∈ fs₂ ∧ Even b := by exact mem_filter.mp hb₀
constructor
. have hb₂: b < 2 * n + 2 := by exact List.mem_range.mp hb₁.1
have hb₃: (b / 2) < n + 1 := by exact Nat.div_lt_of_lt_mul hb₂
exact mem_range.mpr hb₃
. exact two_mul_div_two_of_even hb₁.2
. intros b hb₀
ring_nf
have hb₁: (-1:ℝ) ^ (b * 2) = 1 := by
refine (neg_one_pow_eq_one_iff_even (by norm_num)).mpr ?_
rw [mul_comm]
exact even_two_mul b
rw [hb₁, mul_one]
exact h₁₁
have h₂: ∑ x ∈ range (2 * n + 1 + 1), (-k) ^ x * ↑((2 * n + 1).choose x) =
∑ x ∈ fs₂, ↑((2 * n + 1).choose x) * (-k) ^ x := by
refine Finset.sum_congr (rfl) ?_
intros x _
rw [mul_comm]
rw [h₀, h₁, h₂, sub_neg_eq_add]
have h₃: fs₂ = fs₀ ∪ fs₁ := by
refine Finset.ext_iff.mpr ?_
intro a
constructor
. intro ha₀
refine mem_union.mpr ?mp.a
have ha₁: Odd a ∨ Even a := by exact Or.symm (even_or_odd a)
cases' ha₁ with ha₂ ha₃
. left
refine mem_filter.mpr ?mp.a.inl.h.a
exact And.symm ⟨ha₂, ha₀⟩
. right
refine mem_filter.mpr ?mp.a.inl.h.b
exact And.symm ⟨ha₃, ha₀⟩
. intro ha₀
apply mem_union.mp at ha₀
cases' ha₀ with ha₁ ha₂
. exact mem_of_mem_filter a ha₁
. exact mem_of_mem_filter a ha₂
have h₄: Disjoint fs₀ fs₁ := by
refine disjoint_filter.mpr ?_
intros x _ hx₁
exact not_even_iff_odd.mpr hx₁
nth_rw 2 [add_comm]
rw [h₃, Finset.sum_union h₄]
theorem imo_1974_p3
(n : ℕ) :
¬ 5 ∣ ∑ k ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * k + 1)) * (2^(3 * k)) := by
let k:ℝ := Real.sqrt (8:ℝ)
have hk: k = Real.sqrt (8:ℝ) := by rfl
let b:ℕ := ∑ k ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * k + 1)) * (2^(3 * k))
have hb: b = ∑ k ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * k + 1)) * (2^(3 * k)) := by rfl
rw [← hb]
let a:ℕ := ∑ k ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * k) * (2 ^ (3 * k)))
have ha: a = ∑ k ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * k) * (2 ^ (3 * k))) := by rfl
have hb₁: b = (1 / k) *
∑ x ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * x + 1)) * (k ^ (2 * x + 1)) := by
rw [hb, hk]
simp
rw [Finset.mul_sum]
refine Finset.sum_congr (rfl) ?_
intros x _
rw [mul_comm ((√8)⁻¹), mul_assoc]
refine mul_eq_mul_left_iff.mpr ?_
left
rw [pow_succ, pow_mul, pow_mul, Real.sq_sqrt (by norm_num)]
norm_num
have ha₁: a = ∑ x ∈ Finset.range (n + 1), (Nat.choose (2 * n + 1) (2 * x) * (k ^ (2 * x))) := by
rw [ha, hk]
simp
refine Finset.sum_congr (rfl) ?_
intros x _
refine mul_eq_mul_left_iff.mpr ?_
left
rw [pow_mul, pow_mul, Real.sq_sqrt (by norm_num)]
norm_num
have hk₀: k * k⁻¹ = 1 := by
refine (mul_inv_eq_one₀ ?_).mpr (rfl)
rw [hk]
norm_num
have h₀: (1 + k) ^ (2 * n + 1) = a + b * k := by
exact aux_4 n b a k hb₁ ha₁ hk₀
have h₁: (1 - k) ^ (2 * n + 1) = a - b * k := by
exact aux_5 n b a k hb₁ ha₁ hk₀
have h₂: ((1 + k) * (1 - k)) ^ (2 * n + 1) = (a + b * k) * (a - b * k) := by
rw [mul_pow, h₀, h₁]
rw [← sq_sub_sq 1 k] at h₂
rw [← sq_sub_sq (↑a) ((↑b:ℝ) * k)] at h₂
rw [mul_pow, hk] at h₂
norm_num at h₂
have h₃: (7:ℕ) ^ (2 * n + 1) = b ^ 2 * 8 - a ^ 2 := by
have h₃₀: Odd (2 * n + 1) := by exact odd_two_mul_add_one n
have h₃₁: (-7:ℝ) = (-1:ℝ) * (7:ℕ) := by norm_num
have h₃₂: (-1:ℝ) ^ (2 * n + 1) = -1 := by exact Odd.neg_one_pow h₃₀
have h₃₃: ↑a ^ 2 - ↑b ^ 2 * 8 = (-1:ℝ) * (↑b ^ 2 * 8 - ↑a ^ 2) := by
linarith
rw [h₃₁, mul_pow, h₃₂, h₃₃] at h₂
simp at h₂
have h₃₄: (7:ℝ) ^ (2 * n + 1) = ↑b ^ 2 * 8 - ↑a ^ 2 := by
linarith
norm_cast at h₃₄
rw [Int.subNatNat_eq_coe] at h₃₄
rw [← Int.toNat_sub, ← h₃₄]
exact rfl
have h₄: 7 ^ (2 * n + 1) ≡ 2 [MOD 5] ∨ 7 ^ (2 * n + 1) ≡ 3 [MOD 5] := by
refine aux_3 n
by_contra! hc₀
have hc₁: b^2 * 80^2 * 8 [MOD 5] := by
refine ModEq.mul ?_ rfl
refine ModEq.pow 2 ?_
exact modEq_zero_iff_dvd.mpr hc₀
simp at hc₁
have h₅: a ^ 2 < b ^ 2 * 8 := by
have h₅₀: 0 < 7 ^ (2 * n + 1) := by
exact Nat.pow_pos (by norm_num)
rw [h₃] at h₅₀
exact Nat.lt_of_sub_pos h₅₀
cases' h₄ with h₄₀ h₄₁
. rw [h₃] at h₄₀
have hc₂: b ^ 2 * 8 - a ^ 2 + a ^ 22 + a ^ 2 [MOD 5] := by
exact ModEq.add_right (a ^ 2) h₄₀
rw [Nat.sub_add_cancel (le_of_lt h₅)] at hc₂
have hc₃: 3 + (2 + a ^ 2) ≡ 3 [MOD 5] := by
apply Nat.ModEq.trans hc₂.symm at hc₁
exact ModEq.add_left 3 hc₁
have hc₄: a ^ 23 [MOD 5] := by
rw [← add_assoc, ← zero_add 3] at hc₃
norm_num at hc₃
have hc₄: 50 [MOD 5] := by decide
exact Nat.ModEq.add_left_cancel hc₄ hc₃
have hc₅: ¬ a ^ 23 [MOD 5] := by exact aux_2 a
exact hc₅ hc₄
. rw [h₃] at h₄₁
have hc₂: b ^ 2 * 8 - a ^ 2 + a ^ 23 + a ^ 2 [MOD 5] := by
exact ModEq.add_right (a ^ 2) h₄₁
rw [Nat.sub_add_cancel (le_of_lt h₅)] at hc₂
apply Nat.ModEq.trans hc₂.symm at hc₁
have hc₃: a ^ 22 [MOD 5] := by
refine Nat.ModEq.add_left_cancel' 3 ?_
exact hc₁
have hc₄: ¬ a ^ 22 [MOD 5] := by exact aux_1 a
exact hc₄ hc₃