```python
import numpy as np
import pandas as pd
import math as mt
import matplotlib.pyplot as plt
import sympy
from sklearn.preprocessing import MinMaxScaler
```

# Caso 1: Senoide


```python
m1 = 1.2
m2 = 2.7
k1 = 10
k2 = 20
k3 = 15

omega_n_1 = (k1/m1)**0.5
mr = m2/m1
k32 = k3/k2
omega_r = (k2/k1)**0.5

a1 = 1 + omega_r**2 * (1+mr+k32)
a2 = omega_r**2 * (1+k32*(1+omega_r**2 * mr))

Omega1 = (0.5*(a1-(a1**2 - 4*a2)**0.5))**0.5

Omega2 = (0.5*(a1+(a1**2 - 4*a2)**0.5))**0.5

print("Omega1 = {:.2f} rad/s".format(Omega1))

print("Omega2 = {:.2f} rad/s".format(Omega2))

rasao_1 = mr*omega_r**2/(1+omega_r**2 *mr-Omega1**2)

rasao_2 = omega_r**2 *(1+k32) - Omega2**2/(omega_r**2)

print("rasao_1 = {:.2f}".format(rasao_1))

print("rasao_2 = {:.2f}".format(rasao_2))
```

    Omega1 = 1.16 rad/s
    Omega2 = 2.77 rad/s
    rasao_1 = 1.08
    rasao_2 = -0.33


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ipynb
Jupyter Notebook
10_periodo/vibracoes/Trabalho_14.ipynb
Esterci/Engenharia_Mecanica_UFJF
54368f19e36d399d53bc5d5b9c712963e60e93d2
MIT
10_periodo/vibracoes/Trabalho_14.ipynb
Esterci/Engenharia_Mecanica_UFJF
54368f19e36d399d53bc5d5b9c712963e60e93d2
MIT
10_periodo/vibracoes/Trabalho_14.ipynb
Esterci/Engenharia_Mecanica_UFJF
54368f19e36d399d53bc5d5b9c712963e60e93d2
MIT
Qwen/Qwen-72B
1. YES
2. YES