<a href="https://colab.research.google.com/github/spellvia2/testrepostory/blob/main/math_symbol_prac.ipynb" target="_parent"></a>

## 수학 기호 연습

수식 기호들을 집어 넣는 연습을 해봅시다. $\theta =1 $ $1 \le 5$  
$\sum_{i=1}^{n}i^2$


큰 시그마 
$$
\sum_{i=1}^{n} \frac{1}{i}
$$

$X_1,X_2,....,X_n$이 독립일 때  
$var$($\displaystyle\sum_{i=1}^{n} X_i$) = $\displaystyle\sum_{i=1}^{n}var(X_i)$  
이 성립한다.  

$X$~$N(m,\sigma)$  
$f(x) = \frac{1}{\sigma\sqrt{2\pi}}exp(-\frac{(x-m)^2}{2\sigma^2})$  
$\int_{-\infty}^{\infty}\frac{1}{\sigma\sqrt{2\pi}}exp(-\frac{(x-m)^2}{2\sigma^2})$
 

\begin{align}
r = Corr(X,Y)&=\frac{\frac{1}{n-1}\displaystyle\sum_{i=1}^{n} (x_i-\bar{x})
(y_i-\bar{y})}
{\sqrt{\frac{1}{n-1}\displaystyle\sum_{i=1}^{n} (x_i-\bar{x})}
\sqrt{\frac{1}{n-1}\displaystyle\sum_{i=1}^{n} (y_i-\bar{y})}}\\
&=  \frac{\displaystyle\sum_{i=1}^{n} (x_i-\bar{x})
(y_i-\bar{y})}
{\sqrt{\displaystyle\sum_{i=1}^{n} (x_i-\bar{x})}
\sqrt{\displaystyle\sum_{i=1}^{n} (y_i-\bar{y})}}\\
\end{align}



```python

```


```python

```

e8cc2cd1afc408b7ecc00ac2c31f7728fa30cf9d
ipynb
Jupyter Notebook
math_symbol_prac.ipynb
spellvia2/testrepostory
b213b0d3664abab876907fd5b9e60ab605b6c2f4
MIT
math_symbol_prac.ipynb
spellvia2/testrepostory
b213b0d3664abab876907fd5b9e60ab605b6c2f4
MIT
math_symbol_prac.ipynb
spellvia2/testrepostory
b213b0d3664abab876907fd5b9e60ab605b6c2f4
MIT
Qwen/Qwen-72B
1. YES
2. YES