# Internetwache 2016 : Code (70)
**Category:** Code |**Points:** 70 |**Name:** A numbers game II |**Solves:** 230 |**Description:**
> Math is used in cryptography, but someone got this wrong. Can you still solve the equations? Hint: You need to encode your answers.>>Attachment: code70.zip>>Service: 188.166.133.53:11071
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## Write-upDownload the zip. The file looks like this:```pythondef encode(eq):    out = []    for c in eq:        q = bin(ord(c)^(2<<4)).lstrip("0b")        q = "0" * ((2<<2)-len(q)) + q        out.append(q)    b = ''.join(out)    pr = []    for x in range(0,len(b),2):        c = chr(int(b[x:x+2],2)+51)        pr.append(c)    s = '.'.join(pr)    return s```I replace the self.\_xor to ^ since I don't want a class.
The first loop is to transfer the result of the xor of ASCII value of any character in the equation and 32 to a 8-bit binary code.
The second loop is to transfer every two dit to a number then plused to 3.
So what we need to do is easy.
Just reverse the process.
1. First minus 3 then transfer to 2-digit binary code.2. put them together then split into 8-digit groups.3. Transfer the 8-digit binary code to int then do the xor again. (hint: a^b^b=a)4. get the equation, use the function in Code50 to calculate the result.5. encode the result and send to server.