# Crypto PHP
No GPU Cores Will Be Harmed in the Solving of This Challenge!
Url: http://gold.razictf.ir/PleaseCreateABitcoinAddressForMe/
Tags: web security
## Solution
We are greeted with `I'm not giving you any flags!`. Looking at the source:
```
I'm not giving you any flags!```
We download the `index.php.bak`:
```php 0)    {        return false;    }
    return substr(strtoupper(hash("sha256",hash("sha256",pack("H*",substr($address,0,strlen($address)-8)),true))),0,8) == substr($address,strlen($address)-8);}
$address = "35hK24tcLEWcgNA4JxpvbkNkoAcDGqQPsP";if (isset ($_GET["PleaseCreateABitcoinAddressForMe"])){$address = $_GET["PleaseCreateABitcoinAddressForMe"];}
$check = checkAddress($address);if ($check){	if (substr( $address, 0, 5 ) === "1Razi")	{		echo "flag";	}}else{	echo "I'm not giving you any flags!";}
echo $check;
?>```
We can provide an address through the get parameter `PleaseCreateABitcoinAddressForMe`. It's checked via `checkAdress` which has to return true in order to continue. The provided address has to start with `1Razi`.
Let's analyze what `checkAdress` does. It uses `bcmath` for arbitrary precision calculations. We iterate over the chars of the address and add that to the result of `bcmul($dec, "58", 0)`. After that we have a very large number. Like the first variable name `origbase58` implies, this is base58 -> decimal.
If you want to restore the next step it in python, you need the fractions module, because python converts these numbers to `bignumber`:
```python>>> n = 42468160281214442798985882180071997964045162989719209072>>> int(n / 16)2654260017575902720967102997974858231782517263919218688>>> (Fraction(n) / 16).numerator2654260017575902674936617636254499872752822686857450567>>> int(n / 16) % 160>>> (Fraction(n) / 16 % 16).numerator7```
It converts our number from decimal to a hexadecimal string. So you don't actually need it but to initally understand what it is doing it might be helpful.
```python>>> dec = n>>> hexchars = "0123456789ABCDEF">>> addr = "">>> while dec > 0:...         dv, rem = divmod(dec, 16)...         dec = Fraction(dv)...         addr += hexchars[rem.numerator]...>>> addr[::-1]'1BB63666D1882FDD5ED9DA658AFAF56502193C397E54470'>>> hex(n)[2:].upper()'1BB63666D1882FDD5ED9DA658AFAF56502193C397E54470'```
The string is additionally padded with zeros for starting 1s in the address and if the length is odd. The length has to be 50 afterwards and the first two chars (1 byte) has to be zero. Since the required address already starts with a 1 that is converted to zeros this is no problem.
Let's summarize: our adress is converted like this: base58 -> decimal -> hexadecimal string.
### The mistake
The last part is hard to read, storing results in variables we can now see:
```php