# Old Story
This is an old story about wheat and chessboard, and it's easy, right?
File:[Old_story.zip](Old_story.zip)
Inside the zip got a `cipher.txt`:```[524288, 4194304, 16384, 1024, 4194304, 32, 262144, 2097152, 4194304, 16777216, 70368744177664, 2251799813685248, 8192, 8388608, 8192, 4503599627370496, 16777216, 36028797018963968, 16384, 2199023255552, 67108864, 1048576, 2097152, 18014398509481984, 33554432, 68719476736, 4, 17179869184, 536870912, 549755813888, 262144, 4294967296, 16384, 128, 288230376151711744, 137438953472, 16777216, 36028797018963968, 1024, 4503599627370496, 16384, 68719476736, 262144, 4611686018427387904]```Which is a list of numbers
We notice all the numbers is power of 2
So we wrote a script to get the power index of each number:
```pythonimport mathtext = [524288, 4194304, ...]for t in text:	print math.log(t,2)```Output:```...37.024.055.010.052.014.036.018.062.0```
Googling `wheat and chessboard` we found a clue which is **64**
What if the index is in **base64**?
So we code a script based on [base64 table](https://en.wikipedia.org/wiki/Base64#Base64_table):
```pythonimport stringimport mathtext = [524288, 4194304, ...]base = string.ascii_uppercase+string.ascii_lowercase+string.digits+"+/"print ''.join([base[int(math.log(t,2)-1)] for t in text]).decode('base64')```
Just Guessing, simple challenge!
# Flag> ISITDTU{r1c3_che55b0ard_4nd_bs64}