# crackme-py
Category: Reverse Engineering AUTHOR: SYREAL
## Solving
Open up the source code:```py# Hiding this really important number in an obscure piece of code is brilliant!# AND it's encrypted!# We want our biggest client to know his information is safe with us.bezos_cc_secret = "A:4@r%uL`M-^M0c0AbcM-MFE067d3eh2bN"
# Reference alphabetalphabet = "!\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ"+ \            "[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~"```Wow, okay. Jess Bezos! Now look a little lower:```pydef decode_secret(secret):    """ROT47 decode
    NOTE: encode and decode are the same operation in the ROT cipher family.    """```So a ROT47, we can just use [cyberchef](https://gchq.github.io/CyberChef/) and decode the secret:```picoCTF{1|\/|_4_p34|\|ut_ef5b69a3}```Here we go.