Simply reversing encrypt order we can get easy flag. Here is a working example - [https://ideone.com/LLxa3j](https://ideone.com/LLxa3j)
```python#!/usr/bin/env python3
from random import *from Crypto.Util.number import *
def decrypt(msg, KEY):	c = KEY ^ m	return long_to_bytes(c)
m = 2290064970177041546889165766737348623235283630135906565145883208626788551598431732k = 23226475334448992634882677537728533150528705952262010830460862502359965393545print(decrypt(m, k))```
> MAPNA{R_U_MT19937_PRNG_Predictor?}