
### Santa's Crackme
![title](Images/1_title.png)
The first and the most easiest crackme. The input is xored with 3 and compared with encoded flag.
![main](Images/1_main.png)
![flag](Images/1_flag.png)
Solution:
``` pythonflag = '[.NBPx67m47\\26\\a7g\\74\\o2`0m60\\`k0`h2m5~'password = ''for i in flag:    password += chr(ord(i) ^ 3)print password```
``` >>> X-MAS{54n74_15_b4d_47_l1c3n53_ch3ck1n6}```