# Super Safe RSA - Crypto
On this RSA challenge, we get the following:```c: 2425856200769915981651037422985132378377167608258701728568281807599094681752373n: 27648161471552692194976798121921575562926832795742781625850575808536319404313029e: 65537```
First thing I try is to factorize the n on [Alpertron](https://www.alpertron.com.ar/ECM.HTM). Then we get p and q:```p = 169164339873385123585987559611932758873q = 163439655735047847596122332439710591236173```
Then we create this script to decrypt the ciphertext c:```python#!/usr/bin/env pythonimport libnum
n = 27648161471552692194976798121921575562926832795742781625850575808536319404313029c = 2425856200769915981651037422985132378377167608258701728568281807599094681752373e = 65537
p = 169164339873385123585987559611932758873q = 163439655735047847596122332439710591236173
n=p*qphi=(p-1)*(q-1)d = libnum.modular.invmod(e, phi)print libnum.n2s(pow(c, d, n))```
After running the script, we get the flag: picoCTF{us3_l@rg3r_pr1m3$_2461}