## Challenge Description```a cat in space, eating a croissant, while starting a revolution.MD5 (chall.jpg.pcap) = 8408b3176d9f974c03f919d36d48770a```## Challenge SolutionWe're provided with a pcap file `chall.jpg.pcap`. When I opened it up with wireshark there were roughly 240000 ICMP type 8  Echo (ping) request packets with each has 1 byte data in them. The first two packets were FF D8 and the last two were FF D9, which is hinting at a generic JPEGimage file. This means that if we extract the 1 hexbyte data from each packet and write them into file, we should get an jpg image file. Here is a python script for that:```pyfrom scapy.all import *import binascii
# Read pcap filepackets = rdpcap("chall.jpg.pcap")
# Initialize empty hexdumphexdump = ""
for packet in packets:    # Check if packet is an ICMP Echo (ping) request    if packet.haslayer(ICMP) and packet[ICMP].type == 8:        # Extract hexbyte data        hexbyte = packet.load.hex()         # packet.load = b'\xff'     b'\xff'.hex() = 'ff'        # Append hexbyte to hexdump        hexdump += hexbyte                  # b'\xff' + b'\xd9' = b'\xff\xd9'
# Convert hexdump to binary data. 'ffd9' => b'\xff\xd9'binary_data = binascii.unhexlify(hexdump)   # binary_data = bytes.fromhex(hexdump)
# Write binary data to .jpg filewith open("flag.jpg", "wb") as f:    f.write(binary_data)
print("Image written to flag.jpg")```We can improve the script above and remove unnecessary lines; for instance we don't have to check each package if they're ICMP Echo (ping) request or not. It'll slow down the process.```py#!/usr/bin/env python3from scapy.all import *
packets = rdpcap("chall.jpg.pcap")bytedata = b''
for packet in packets:    bytedata += packet.load
with open('flag.jpg', 'wb') as file:    file.write(bytedata)```
If we open up flag.jpg we'll get the flag: `shctf{look_at_da_kitty}`