# picoCTF 2022 St3g0 (Forensics 300 points)The challenge is the following,
![Figure 1](img/challenge.png) 
We are also given the file [pico.flag.png](./files/pico.flag.png)
![Figure 1](files/pico.flag.png)
I went to [Steganography Online](https://stylesuxx.github.io/steganography/) to decode the image, but decoding the image did not reveal anything.
![Figure 1](img/noflag.png) 
I decided to use [zsteg](https://github.com/zed-0xff/zsteg) instead, with the `-a` option to try all known methods, and the `-v` option to run verbosely,
`zsteg -a -v pico.flag.png`
This revealed the flag at `b1,rgb,lsb,xy`, where `rgb` means it uses RGB channel, `lsb` means least significant bit comes first, and `xy` means the pixel iteration order is from left to right.
![Figure 1](img/flag.png) 
Therefore, the flag is,
`picoCTF{7h3r3_15_n0_5p00n_1b8d71db}`
