# Challenge description
Have you ever heard the term "The sum of two squares"?
It's like the following :```4 = 0^2 + 2^28 = 2^2 + 2^216 = 0^2 + 4^2----------------------------5002 = 39^2 + 59^2 => 49^2 + 51^2 => 51^2 + 49^2 => 59^2 + 39^2And so on. In the example of 16, if we add the square of 0 & 4 we get 16. So here we are getting two values 0 & 4. So that's the answer.
So write a program & find out the two values of 25000. Conditions are the following :
* Remove the duplicates* Pick the third one```Flag Format : KCTF{0,1}
**Author: TareqAhmed**
-----------------------------------------------------------Solve.py ```python
y=25000
for i in range(0,y//2):        for j in range(0,y//2):                if (i*i + j*j == y) :                    print(i,j)
```Output of solve.py :
![image](https://user-images.githubusercontent.com/58823465/150652307-e3f79e6a-4112-4385-a97e-19057ee6b0c8.png)
``` KCTF{90,130} ```