1. Try to decrypt the ciphertext by using Base64 and Hex with n th times (random), you will get this secret code
```035e44154106060c17181b```
2. Decrypt the secret code to get the flag
```c = '035e44154106060c17181b'c = [chr(eval('0x' + c[i:i+2])) for i in range(0, len(c) - 1, 2)]x = list('b00t2root{}')flag = ''for i in range(len(c)):    flag += chr(ord(c[i]) ^ ord(x[i]))print('b00t2root{' + flag[-1] + flag[:-1] + '}')```
3. Here is the flag
```b00t2root{fantasticcc}```