The given file is python 3 bytecode, which can be decompiled using a tool such as `uncompyle6`. The obtained code contains somewhat obfuscated variable and function names, one of the less obfuscated variables - `flagtext` - is hint text that runs across the screen when the program is run.
The program asks for a flag as input so it must check it somewhere. Digging through the code, the part displaying the flag wrapper has variables `input_x` and `cur_x`, which line up with the beginning of the input text and the cursor after it. The cursor position is dependent on the length of `girafix`, which is presumably the input text. `girafix` gets passed to `lababa` once it is `26` characters long, so that is the checker function, where after renaming the variables to something more sensible:
```python 3def cryptfun1(param):    locarr = [     73, 13, 19, 88, 88, 2, 77, 26, 95, 85, 11, 23, 114, 2, 93, 54, 71, 67, 90, 8, 77, 26, 0, 3, 93, 68]    result = ''    for c in range(len(locarr)):        if param[c] != chr(locarr[c] ^ ord(keystring[c])):            return 'bbblalaabalaabbblala'        b2a = ''        a2b = [122, 86, 75, 75, 92, 90, 77, 24, 24, 24, 25, 106, 76, 91, 84, 80, 77, 25, 77, 81, 92, 25, 92, 87, 77, 80, 75, 92, 25, 74, 77, 75, 80, 87, 94, 25, 88, 74, 25, 95, 85, 88, 94]        for bbb in a2b:            b2a += chr(bbb ^ 57)        else:            return b2a```
where `keystring` (originally `babababa`) is a string from one of the setup functions earlier:
```python 3babababa = 'you-may-need-this-key-1337'```
This is a simple xor cipher, and the result is just
```python 3"".join(chr(locarr[c] ^ ord(keystring[c])) for c in range(26))# 0bfu5c4710ns_v5_4n1m4710ns```
Which works in the program and yields the flag `darkCON{0bfu5c4710ns_v5_4n1m4710ns}` when combined with the wrapper.