The image is a photo of Richard Hamming. The entire image can be interpreted as a 65536-bit Hamming Code in SECDED (extended) mode. To find the error bit, treat the entire image as a 1D array of bits with black pixel = 1 and white pixel = 0 (the inverse will also work). Then, XOR together the **indices** of the 1 pixels, we get 19589, which corresponds to pixel (133, 76).
Hence the flag is `texsaw{one_hundred_and_thirty_three_seventy_six}`
A Python solution script:
```import numpy as npfrom functools import reduceimport operator as opfrom PIL import Image
img = Image.open("message.bmp", "r")width, height = img.sizepixels = list(img.getdata())
def find_faulty_bit(bits):    onelist = [i for i, bit in enumerate(bits) if bit]    faultybit = reduce(op.xor, onelist)    return faultybit
fb = find_faulty_bit(pixels)
print(fb)print((fb%width, fb//width))print((bin(fb%width), bin(fb//width)))
```