Inside of each 7z file there were two images and another 7z file.  The two images differed by only 1 pixel and were sometimes rotated/flipped. We had to use the different pixel to generate the password to the 7z file.  ```from PIL import Imageimport sysimport subprocessimport os
def extract(file, pwd, outdir):	o = subprocess.call(		['7z', 'x', '-y', '-p' + pwd, '-o' + outdir, file])	return o
def tryy(l, x, y, p1, p2):	r1, g1, b1 = p1	r2, g2, b2 = p2
	xy = str(x) + str(y)	rgb1 = '{:0{}X}'.format(r1, 2) + '{:0{}X}'.format(g1, 2) + '{:0{}X}'.format(b1, 2)	rgb2 = '{:0{}X}'.format(r2, 2) + '{:0{}X}'.format(g2, 2) + '{:0{}X}'.format(b2, 2)	password = xy + rgb1 + rgb2	print(password)
	fn = f"level{l}/level_{l+1}.7z"	code = extract(fn, password, f"level{l+1}")	if code == 0:		os.remove(fn)	return code == 0
def find_pixel(im1, im2, f=lambda x, y: (x, y)):	pp = None	width, height = im1.size	for y in range(height):		for x in range(width):			x2, y2 = f(x, y)			p1 = im1.getpixel((x, y))			try:				p2 = im2.getpixel((x2, y2))			except:				return None			if p1 != p2:				if pp:					return None				pp = x, y, p1, p2	return pp
def do(l):	im1 = Image.open(f'level{l}/level_{l}.png')	im2 = Image.open(f'level{l}/lev3l_{l}.png')	width, height = im1.size	funs = [		lambda x, y: (x, y),		lambda x, y: (x, height - 1 - y),		lambda x, y: (width - 1 - x, y),		lambda x, y: (width - 1 - x, height - 1 - y),		lambda x, y: (y, x),		lambda x, y: (y, width - 1 - x),		lambda x, y: (height - 1 - y, x),		lambda x, y: (height - 1 - y, width - 1 - x),	]
	for f in funs:		pp = find_pixel(im1, im2, f=f)		if not pp:			continue
		tryy(l, *pp)
i = 0while True:	do(i)	i += 1```We had to do this 1024 times to get the flag: `{FLG:p1xel0ut0fBound3xcept1on_tr4p_1s_shutt1ng_d0wn}`.