# TaskThe challenge was an image of a QR code, that was cut in a 3x3 grid and shuffled around. It also contained the python code that created the shuffling.
# SolutionOne way is to try to guess there every peace belongs by eye. But this took to long, so lets just run the original script multiple times and check using the pyzbar library, if a valid QR code is in the image. Since there are not that many possibilities, the flag was found pretty quickly:
```[(0, 1), (0, 2), (1, 2), (2, 1), (2, 2), (1, 1), (1, 0), (2, 0), (0, 0)][Decoded(data=b'Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. INS{Im-puzzl3d-6c2bd4d3-e739-4f8d-b8cd-6bd663bde735} Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.', type='QRCODE', rect=Rect(left=0, top=0, width=234, height=234), polygon=[Point(x=0, y=0), Point(x=0, y=234), Point(x=234, y=234), Point(x=234, y=0)], quality=1, orientation='UP')]```
Full code:
```pythonfrom PIL import Imageimport randomfrom pyzbar.pyzbar import decode
# function of the original challenge, slightly modified to also return the image to directly check itdef shuffle3x3GridImage(image_path, output_path):    # Open the image    original_image = Image.open(image_path)     # Get the size of the image    width, height = original_image.size    assert(width == 234 and height == 234)     # Calculate the size of each grid cell    cell_width = width // 3    cell_height = height // 3     # Create a new image to store rearranged pieces    new_image = Image.new("RGB", (width, height))     # Create a list to store shuffled grid positions    positions = [(x, y) for x in range(3) for y in range(3)]    random.shuffle(positions)    print(positions)     # Split the original image into 16 pieces and rearrange them    for i, pos in enumerate(positions):        # Calculate the coordinates of the current grid cell        x1 = pos[0] * cell_width        y1 = pos[1] * cell_height        x2 = x1 + cell_width        y2 = y1 + cell_height         # Crop the corresponding part of the original image        cropped_piece = original_image.crop((x1, y1, x2, y2))         # Calculate the coordinates to paste the cropped piece        new_x = (i % 3) * cell_width        new_y = (i // 3) * cell_height         # Paste the cropped piece onto the new image        new_image.paste(cropped_piece, (new_x, new_y))     # Save the rearranged image    new_image.save(output_path)    return new_image
for x in range(10000):    img = shuffle3x3GridImage("puzzledVersion25QRcode.png", "unpuzzled.png")    barcodes = decode(img)    print(barcodes)```