# int_generator> There is a machine that takes any integer between 0 and 2**35 (inclusive) and returns a 16-digit integer.What are flag1, flag2, and flag3?
> FLAG format：FLAG{flag1_flag2_flag3}
## About the ChallengeWe have been given a zip file (You can download the file [here](mis-int-generator.zip)). There are 2 files inside the zip file, `chall.py` and `output.txt`. Here is the content of `chall.py`
```pythonimport random
k = 36maxlength = 16
def f(x, cnt):    cnt += 1    r = 2**k    if x == 0 or x == r:        return -x, cnt    if x * x % r != 0:        return -x, cnt    else:        return -x * (x - r) // r, cnt
def g(x):    ret = x * 2 + x // 3 * 10 - x // 5 * 10 + x // 7 * 10    ret = ret - ret % 2 + 1    return ret, x // 100 % 100
def digit(x):    cnt = 0    while x > 0:        cnt += 1        x //= 10    return cnt
def pad(x, cnt):    minus = False    if x < 0:        minus = True        x, cnt = g(-x)    sub = maxlength - digit(x)    ret = x    for i in range(sub - digit(cnt)):        ret *= 10        if minus:            ret += pow(x % 10, x % 10 * i, 10)        else:            ret += pow(i % 10 - i % 2, i % 10 - i % 2 + 1, 10)    ret += cnt * 10 ** (maxlength - digit(cnt))    return ret
def int_generator(x):    ret = -x    x_, cnt = f(x, 0)    while x_ > 0:        ret = x_        x_, cnt = f(x_, cnt)    return pad(ret, cnt)
num1 = random.randint(0, 2 ** (k - 1))num2 = random.randint(0, 2 ** (k - 1))num3 = random.randint(0, 2 ** (k - 1))
print("int_generator(num1):{}".format(int_generator(num1)))print("int_generator(num2):{}".format(int_generator(num2)))print("int_generator(num3):{}".format(int_generator(num3)))```
This code is a Python implementation of a complex integer generator function that takes an integer as input and returns a padded integer. The generator function involves multiple sub-functions that manipulate and transform the input integer in various ways, including checking for certain properties, performing arithmetic operations, and adding padding zeros to ensure that the output integer is of a fixed length. The code uses a combination of mathematical techniques and random number generation to generate unique, large, and complex integers. Overall, the code seems to be designed for some specific application that requires the generation of such integers.
And here is the content of `output.txt`
```int_generator(flag1):1008844668800884int_generator(flag2):2264663430088446int_generator(flag3):6772814078400884```
## How to Solve?I solved this with one of the TCP1P players, `@kaelanalysis`. He already got the `flag1`, `flag2` and `flag3`. But because we can't input negative number, we need to find another way to get the value of `flag2`
![num](images/num.png)
To find the `flag2` im using bruteforce approach.
```pythonfor i in range(0, 2 ** (k - 1)):    num2 = i
    print("int_generator(" + str(i) + "):{}".format(int_generator(num2)))```
So this code will try every number from `0` to `2**35`. And here is the command that I used to get `flag2`
```shellpython3 solve.py | grep 2264663430088446```
![flag2](images/flag2.png)
```FLAG{0_26476544_34359738368}```