### Phase stream 2
#### Problem
- Given the output.txt file, get the flag
#### Hints
- The encrypted flag is hidden among 9999 other lines in output.txt.- Also, the flag is encrypted by 'xor'ing with a key of length 1
#### Solution
- We know that the flag starts with "CHTB{" and ends with "}".- Also, suppose the key = x and the plaintext char =c, then encoded char (e) = c ^ x.- So, for each line, we xor the first 5 chars of the encoded string with "CHTB{".- This, will give us 5 possible keys. If all the 5 keys are same, then we can be sure that this line contains the flag.- Also, the 'xor'ed value will give us the key.- So, we use the given key and the line to get the flag.- You can find the code in decrypt.py- Flag - `CHTB{n33dl3_1n_4_h4yst4ck}`