def options_list_to_dictionary(options_list):
    options = dict([(options_list[i*2], options_list[i*2+1])
                    for i in xrange(len(options_list) / 2)])
    return options
Given a list of options of the form:
dataset/ETHPy150Open dropbox/emmer/emmer/packets.py/options_list_to_dictionary