def singleNumber(self, A):
        storage = 0
        for element in A:
            storage ^= element # XOR

        return storage
Compare cache file with known source data, return cache and fingerprint.
dataset/ETHPy150Open algorhythms/LeetCode/136 Single Number.py/Solution.singleNumber--crossover with--dataset/ETHPy150Open openaddresses/machine/openaddr/cache.py/compare_cache_details