def numTrees_math(self, n):
        return math.factorial(2*n)/(math.factorial(n)*math.factorial(n))-math.factorial(2*n)/(
            math.factorial(n+1)*math.factorial(n-1))
Resolves the argument to a numeric constant, which can be passed to
dataset/ETHPy150Open algorhythms/LeetCode/094 Unique Binary Search Trees.py/Solution.numTrees_math--crossover with--dataset/ETHPy150Open GeekTrainer/Flask/Work/Trivia - Module 5/env/Lib/site-packages/pip/_vendor/requests/packages/urllib3/util/ssl_.py/resolve_cert_reqs