def get_success_url(self):
        if 'return_url' in self.request.POST:
            return self.request.POST['return_url']
        return super(SubscriptionUpdateView, self).get_success_url()
Find the correct "next" url after a successful submission
dataset/ETHPy150Open ofa/connect/open_connect/notifications/views.py/SubscriptionUpdateView.get_success_url