March 13, 2014

Homework Help: chemistry

Posted by Darcy on Tuesday, April 10, 2007 at 5:19pm.

Please, can someone help?

Evaluate log 1.

This is my work up until I have gotten stuck:

log 1

Wow, my apologies, this is algebra, not chemistry.

but actually I think they use it in chemistry too...

Take the log base 10 of each side.

log 1 = log 10^x

I don't understand what you mean by taking the log base 10 of each side.

ok so far you had
10^x = 1, but 10^0 =1
so 10^x=10^0
it would be intuitively obvious that x=0

Thank you. I never thought of that.

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