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Syntactic Confectionery Delight

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In the right typeface, if "a","n" and "p" can do handstands, you have (another) "e", "u" and "d" available, so it's really more then 426. Let a double for e, and add "h" who can also be "y" and this could get weird.

Edit: if "p" makes the costume right, they can also be "b", "d" or "q". As far as I can tell, this doesn't violate the rules above.

In reply to Re^2: Challenge: 8 Letters, Most Words by dwhite20899
in thread Challenge: 8 Letters, Most Words by Limbic~Region

and:  <code> code here </code>

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