[Haskell-cafe] Mutable arrays

Jeff φ jeff1.61803 at gmail.com
Sat Feb 2 05:32:44 EST 2008


by dividing all elements by the largest element.

I managed to write code to do this, but it seems overly complex.  I could
write something much simpler in Clean or C++.  Most likely, my code is
complex because I don't have any experience with mutable arrays in Haskell.
I couldn't find any tutorials on the Internet.  I'd be grateful for
suggestions on simplifying the following code.   Thanks.

{-# OPTIONS_GHC -fglasgow-exts -fbreak-on-exception #-}

-- normalize_ary This takes a mutable array.  Determines the largest
-- element in the array (max_elem) and then divides every element by
-- max_elem.
normalize_ary :: (Num t1,
                  Num t,
                  Ix t,
                  Ix t1,
                  MArray a e t2,
                  Ord e,
                  Fractional e,
                  Enum t,
                  Enum t1) =>
                 a (t, t1) e -> t2 ()
normalize_ary ary =
        -- The following two commented out lines of code show my first
        -- attempt at determining a value for max_elem.  However, this
        -- produces a stack overflow.

        -- elem_ary <- getElems ary
     -- let max_elem = foldl1 max elem_ary

    max_elem <- calc_max_2d_elem ary
    max_elem `seq` map_in_place_2d_arr (\x -> x / max_elem) ary

map_in_place_2d_arr :: (MArray a e t, Enum t2, Enum t1, Ix t1, Ix t2) =>
                       (e -> e) -> a (t1, t2) e -> t ()
map_in_place_2d_arr fn arr = ret
      ret = do ((i1,j1),(i2,j2)) <- getBounds arr
               ( mapM_ (\i ->  do v <- readArray arr i
                                  writeArray arr i (fn v) )
                       [(i,j) | i <- [i1..i2], j <- [j1..j2]])

calc_max_2d_elem :: (Ord t, MArray a t t1, Ix t2, Ix t3, Num t3, Num t2) =>
                    a (t3, t2) t -> t1 t
calc_max_2d_elem arr =
    do m <- readArray arr (0,0)
       (_,(i_max, j_max)) <- getBounds arr
       let calc_max_loop arr m (i,j)
         | j == j_max     = return m
         | otherwise      = do e <- readArray arr (i,j)
                   let m2 = max e m
                                   m2 `seq` calc_max_loop arr m2 nxt_idx
         where nxt_idx | i == i_max - 1 = (0,j+1)
                           | otherwise      = (i+1,j)
       calc_max_loop arr m (0,0)
An HTML attachment was scrubbed...
URL: http://www.haskell.org/pipermail/haskell-cafe/attachments/20080202/15382352/attachment.htm

More information about the Haskell-Cafe mailing list