Take the 2-minute tour ×

in solving wave equation by Fourier transform after taking fourier transform of wave equation $$\frac{\partial^2y}{\partial^2x}=\frac{1}{v^2} \frac{\partial^2y}{\partial t^2}$$ we get $$(-ia)^2 Y(a,t)=\frac{1}{v^2}\frac{d^2Y(a,t)}{dx^2}$$ this is ok. now how we can get to this: $Y(a,t)=F(a)e^{(+-)ivat}$


share|improve this question
add comment

1 Answer

up vote 0 down vote accepted

HINT: Rearrange your expression to yield $(va)^{2}Y(a,t)+\frac{d^{2}Y(a,t)}{dt^{2}}=0$.

share|improve this answer
so now the descriptor equation is $r^2+(va)^2=0$ and this yield to $Y(a,y)=F(a)(e^{ivat}+e^{-ivat})$ and this equals to $Y(a,t)=F(a)(e^{(+-)ivat})$. i am right? –  r.zarei Jan 12 '12 at 8:33
add comment

Your Answer


