Dr.Me A.

asked • 02/06/18

A confusing question for me. Help please

I have answered the first question, but the second one is little confusing for me. 
Archery An arrow is shot at 30.0above the horizontal. Its velocity is 49m/s, and it hits the target.
a. What is the maximum height the arrow will attain?
Answer: (49sin30)2/2*9.8 = 30.625m
b. The target is at the height from which the arrow was shot. How far was it?

1 Expert Answer


Kurt T. answered • 02/06/18

Math Tutoring and Test Prep

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