

Magnitude of a Force on a hatch in a Vessel.

  • Thread starter Basch
  • Start date

We're told the density of ever material involved here, the liquid in the vessel, called "LAB", the water on the outside, and the acryllic that the vessed is made of.
LAB: 860 kg/m^3
Water: 1000 kg/m^3
Acryllic: 1185kg/m^3
Also, the wall thickness of the vessel is 5.4 cm. The height of the neck is labeled delta h, we're also told to not take the pressure difference between the inside and the outside, due to the 5.4cm wall.

This is a three part question, but I'm only looking for help on the first part, which asks us to find the force on the hatch, which is 1.00m^2 big, when delta h = 0.

2. Relevant equations
We need to use Pressure = Force/Area for this, solving for force gives us
Force = Pressure*Area
density * gravity * height = pressure

3. The attempt at a solution

My attempt to solve the question, was to solve for the value of pressure of the inside of the system, and then use that to solve for force. Since the height of liquid in the neck is 0, we have no liquid in the neck, so we only have to consider whats inside the circular area, which has a height of 12m, density of 860kg/m^3, and gravity is 9.81 m/s^2, so which we have to add the pressure of 1 atm due to the air at the top, 1.01e-5 Pa.

Which gives us: 101239 Pa * 1.00 m^2, so the answer is 1.01e5 N?


Homework Helper
But what about the buoyant force from the water beneath the hatch?

Isn't the pressure there going to be 12m*Δρ*A ?
Oops, I accidentally submitted this twice, i had already solved it in another post. Sorry.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Hot Threads