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What is the probability of flipping a fair coin five times and the coin landing on heads on at least two flips?
|
[
"A.5/8",
"B.7/8",
"C.11/16",
"D.13/16"
] | 3
|
D.13/16
|
aqua_rat
|
The number of possible outcomes is 2^5=32.
0 heads: There is 1 way to have all tails.
1 head: There are 5 ways to have one head.
P(0 or 1 head)=6/32=3/16
P(at least 2 heads)=1 - 3/16 = 13/16
The answer is D.
|
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
|
[
"A.234",
"B.127",
"C.274",
"D.918"
] | 1
|
B.127
|
aqua_rat
|
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.
Answer:B
|
A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 8 hours longer than the first half, how many hours did it take the runner to run the second half?
|
[
"A.10",
"B.12",
"C.16",
"D.20"
] | 2
|
C.16
|
aqua_rat
|
The runner runs the first 20 miles at speed v and the second 20 miles at speed v/2.
The time T2 to run the second half must be twice the time T1 to run the first half.
T2 = 2*T1 = T1+8
T1 = 8 and so T2 = 16.
The answer is C.
|
A and B can together finish a work in 40days. They worked together for 10days and then B left. After another 12days, A finished the remaining work. In how many days A alone can finish the job?
|
[
"A.10",
"B.25",
"C.60",
"D.16"
] | 3
|
D.16
|
aqua_rat
|
A+B 10days work = 10*1/40 = 1/4
Remaining work = 1-1/4 = 3/4
3/4 work is done by A in 12 days
whole work will be done by A in 12*4/3 = 16days
Answer is D
|
If 60% of 3/5 of a number is 36, then the number is?
|
[
"A.80",
"B.100",
"C.75",
"D.90"
] | 1
|
B.100
|
aqua_rat
|
Let the number be x. Then 60% of 3/5 of x=36
60/100*3/5*x=36
x=(36*25/9)=100
Required number=100.
Correct Option: B
|
What is the probability Q of randomly selecting an arrangement of the letters of the wordMEDITERRANEANin which the first letter is E and the last letter is R?
|
[
"A.1/13",
"B.1/20",
"C.1/26",
"D.1/50"
] | 2
|
C.1/26
|
aqua_rat
|
Why do you calculate the total combinations and everything, it is much easier to calculate as follows:
3/13 * 1 * 1 * 1 * 1 ..... * 2/12 = 6/156 = 1/26
This is because 3/13 = Probability that first letter will be E and 2/12 = probability that thefirstletter will be R. Between everything else cuts down to 1*1*1... e.g. probability Q of the second letter is 11/11 = 1, > we do not care what's in between.C
|
There r 4 prime numbers in ascending order. The multiplication of first 3 is 385 and that of last 3is 1001. what is the last number is
|
[
"A.8",
"B.10",
"C.11",
"D.13"
] | 3
|
D.13
|
aqua_rat
|
Explanation:
abcbcd=3851001=>ad=513
abcbcd=3851001=>ad=513
So d = 13
D
|
Real-estate salesman Z is selling a house at a 30 percent discount from its retail price. Real-estate salesman X vows to match this price, and then offers an additional 15 percent discount. Real-estate salesman Y decides to average the prices of salesmen Z and X, then offer an additional 40 percent discount. Salesman Y's final price is what fraction of salesman X's final price?
|
[
"A.39/6",
"B.62/11",
"C.11/61",
"D.21/61"
] | 0
|
A.39/6
|
aqua_rat
|
Let the retail price be = x
Selling price of Z = 0.7x
Selling price of X = 0.85*0.7x = 0.60x
Selling price of Y = ((0.7x + 0.6x)/2)*0.60 = 0.65x * 0.60 = 0.39x
0.39x = k * 0.60x
k = 0.39/0.6 = 39/6
Answer: A
|
A jar is filled with red, white, and blue tokens that are equivalent except for their color. The chance of randomly selecting a red token, replacing it, then randomly selecting a white token is the same as the chance of randomly selecting a blue token. If the number of tokens of every color is a multiple of 8, what is the smallest possible total number of tokens in the jar?
|
[
"A. 9",
"B. 12",
"C. 15",
"D. 18"
] | 2
|
C. 15
|
aqua_rat
|
(Red / Total Coins)*(White / Total Coins) = (Blue / Total Coins)
í.ẹ. Red*White = Blue*Total Coins
Let, Red = 3a
White = 3b
Blue = 3c
Total Coins = 3(a+b+c)
í.ẹ. 3a * 3b = 3c*3(a+b+c)
í.ẹ. a*b = c*(a+b+c)
For smallest values of a, b and c
2*3 = 1*(1+2+3)
í.ẹ. Minimum Total Coins = 3*(1+2+3) = 15
Answer: Option C
|
A conical vessel, whose internal radius is 12 cm and height 50 cm, is full of liquid. The contents are emptied into a cylindrical vessel with internal radius 10 cm. Find the height to which the liquid rises in the cylindrical vessel.
|
[
"A.24 cm",
"B.14 cm",
"C.20 cm",
"D.37 cm"
] | 0
|
A.24 cm
|
aqua_rat
|
Volume of the liquid in the cylindrical vessel
= Volume of the conical vessel
= ((1/3)* (22/7)* 12 * 12 * 50) )cm3 = (22 *4 *12 * 50)/7 cm3.
Let the height of the liquid in the vessel be h.
Then (22/7)*10*10*h =(22*4*12*50)/7 or h = (4*12*50)/100 = 24 cm
ANSWER A 24 cm
|
When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 40% water?
|
[
"A.1.2 kg",
"B.1.5 kg",
"C.1.7 kg",
"D.1.9 kg"
] | 0
|
A.1.2 kg
|
aqua_rat
|
Explanation :
Flower-nectar contains 50% of non-water part.
In honey this non-water part constitutes 60% (100-40).
Therefore 0.5 X Amount of flower-nectar = 0.60 X Amount of honey = 0.60 X 1 kg
Therefore amount of flower-nectar needed =
(0.60/0.51)kg=1.2 kgs
Answer : A
|
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
|
[
"A.3.6 kg",
"B.3.696 kg",
"C.36 kg",
"D.36.9 kg"
] | 1
|
B.3.696 kg
|
aqua_rat
|
Solution
External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron =(22/7×(42)-(32)×21)cm3
= (22/7×7 ×1×21)cm3
= 462 cm3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
Answer B
|
A bread merchant declares a 20% discount after 8 P.M. Each bread costs Rs.40 when it is not on sale. Sam goes before 8 P.M. to buy 4 pieces of bread. Max goes after 8 P.M. with the same amount of money that Sam had to buy bread. How many pieces did Max get over Sam?
|
[
"A.1",
"B.2",
"C.3",
"D.4"
] | 0
|
A.1
|
aqua_rat
|
Explanation:
Sam: 4 pieces * 40 = 160
Max: Max had 160. 160 / (40*(1-20%)) = 160 / (40*0.80) = 160 / 32 = 5 pieces
Max - Sam = 5 - 4 = 1
Correct Option: A
|
A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 12 cm by 6 cm. The total number of bricks required is :
|
[
"A.16000",
"B.18000",
"C.20000",
"D.30000"
] | 3
|
D.30000
|
aqua_rat
|
Explanation:
Number of bricks =Courtyard area /1 brick area
=(1800×1200 /12×6)=30000
Option D
|
The cube root of .000216 is:
|
[
"A..6",
"B..06",
"C.77",
"D.87"
] | 1
|
B..06
|
aqua_rat
|
Explanation:
(.000216)1/3 = [216/(10)6 ] 1/3 = 6/100 =0.06
ANSWER IS B
|
Find k if 64 / k = 4.
|
[
"A.16",
"B.17",
"C.18",
"D.14"
] | 0
|
A.16
|
aqua_rat
|
Since 64 /k = 4 and 64/ 16 = 4, then
k = 16 correct answer A
|
A train 120 meter long passes an electric pole in 12 seconds and another train of same length traveling in opposite direction in 8 seconds. The speed of the second train is
|
[
"A.10m/s",
"B.20m/s",
"C.30m/s",
"D.40m/s"
] | 1
|
B.20m/s
|
aqua_rat
|
speed of 1st train=120/12=10m/s
let the speed of 2nd is v
then
240/(v+10)=8
8v=160
v=20m/s
ANSWER:B
|
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
|
[
"A.378",
"B.240",
"C.772",
"D.281"
] | 1
|
B.240
|
aqua_rat
|
Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train
= (15 x 20)m
= 300 m. Let the length of the platform be x meters. Then, (x + 300)/36
= 15 ==> x + 300 = 540
==> x
= 240 m.
Answer: B
|
How many words with or without meaning, can be formed by using all the letters of the word, ‘ORANGE’, using each letter exactly once?
|
[
"A.700",
"B.720",
"C.750",
"D.800"
] | 1
|
B.720
|
aqua_rat
|
The word ‘ORANGE’ contains 6 different letters.
Therefore, Required number of words= Number of arrangement of 6 letters, taken all at a time
=6P6
= 6!
= 6*5*4*3*2*1
= 720
ANSWER:B
|
The average age of three boys is 12 years and their ages are in the proportion 2 : 6 : 8. The age of the youngest boy is:
|
[
"A.21 years",
"B.8.75 years",
"C.6.75 years",
"D.9 years"
] | 2
|
C.6.75 years
|
aqua_rat
|
Total age of 3 boys = (12 × 3) years = 36 years. Ratio of their ages = 2 : 6 : 8.
Age of the youngest = (36 × 3â„16) years = 6.75 years.
Answer C
|
Square RSTU shown above is rotated in a plane about its center in a clockwise direction the minimum number of degrees necessary for R to be in the position where T is now shown. The number of degrees through which RSTU is rotated is
|
[
"A. 135 degree",
"B. 180 degree",
"C. 225 degree",
"D. 270 degree"
] | 1
|
B. 180 degree
|
aqua_rat
|
From the options, I am assuming the positioning of T and R relative to each other to be as shown. To replace T by R, focus on OR. Say, you rotate OR clockwise (and with it the entire square) and bring it in place of OT. How many degrees did you go? You covered 2 right angles i.e. 180 degrees.
Answer : B
|
Set M contains number that satisfy the condition that, if integer x is in the set then x + 6 will also be in the set M. If -4 is one value in the set, which of the following values must also be present in the set M? I) -10 II) 2 III) 8
|
[
"A.I only",
"B.II only",
"C.I and II only",
"D.II and III only"
] | 3
|
D.II and III only
|
aqua_rat
|
Since -4 is in the set, then the set must also include 2, 8, 14, 20, etc...
Depending on whether -4 is the starting element in the set or not, we can have -10...or not.
The answer is D.
|
Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
|
[
"A.6",
"B.5",
"C.7",
"D.9"
] | 3
|
D.9
|
aqua_rat
|
1/10 + 1/15 - 1/x
= 1/18
x = 9
Answer:D
|
Every day a cyclist meets a car at the station.The road is straight and both are travelling in the same direction. The cyclist travels with a speed of 12 mph.One day the cyclist comes late by 20 min. and meets the car 5miles before the Station. What is the speed of the car?
|
[
"A.40 Kmph.",
"B.50 Kmph.",
"C.60 Kmph.",
"D.70 Kmph."
] | 2
|
C.60 Kmph.
|
aqua_rat
|
If they normally meet at 8AM, then
cyclist will reach at station on that day at 8:20 AM. But train will reach station at 8AM only.
and he will be at at point 5 miles before station at 7.55 AM ( i.e 25 min before 8:20 AM)
so train will take 5 mins to travel( to reach stn at 8AM) 5 miles.
so speed of train = 60 Kmph.
ANSWER:C
|
What is the sum of all remainders obtained when the first 130 natural numbers are divided by 9?
|
[
"A.397",
"B.401",
"C.403",
"D.412"
] | 3
|
D.412
|
aqua_rat
|
A positive integer can give only the following 9 remainders when divided by 9: 1, 2, 3, 4, 5, 6, 7, 8, and 0.
1 divided by 9 gives the remainder of 1;
2 divided by 9 gives the remainder of 2;
...
8 divided by 9 gives the remainder of 8;
9 divided by 9 gives the remainder of 0.
We'll have 11 such blocks, since 99/9=11. The last will be:
91 divided by 9 gives the remainder of 1;
92 divided by 9 gives the remainder of 2;
...
98 divided by 9 gives the remainder of 8;
99 divided by 9 gives the remainder of 0.
The last number, 100, gives the remainder of 1 when divided by 9, thus the sum of all remainders will be:
11(1+2+3+4+5+6+7+8+0)+1=412.
Answer: D.
|
A merchant marks his wares 40% more than the real price and allows 20% discount. His profit is:
|
[
"A.20%",
"B.18%",
"C.16%",
"D.12%"
] | 3
|
D.12%
|
aqua_rat
|
Let the CP = 100 Rs.
Mark Price = 140
Discount = 20%
Selling price 80/100 × 140
Hence profit = 12%
Answer: D.
|
(161)^2 - (162)^2 =
|
[
"A.1",
"B.100",
"C.229",
"D.325"
] | 3
|
D.325
|
aqua_rat
|
Using the formula:
(a+1)^2 - a^2 = 2a+1
So, Answer = 162*2 + 1
= 324+1 = 325 = Answer = D
|
The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is?
|
[
"A.30/7",
"B.30/9",
"C.30/2",
"D.30/3"
] | 0
|
A.30/7
|
aqua_rat
|
Required fraction = L.C.M of 6/7, 5/14, 10/21
= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7
Answer:A
|
Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 heads.
|
[
"A.5/32",
"B.6/32",
"C.5/16",
"D.4/32"
] | 0
|
A.5/32
|
aqua_rat
|
Exactly 4 heads out of 5 would be: HHHHT, HHTHH, or many other combinations.
therefore, no. of possible combinations are 5!/4!*1! = 5
Probability = 5/2^5 = 5/32
ANSWER:A
|
While working alone at their constant rates, computer X can process 240 files in 4 hours, and computer Y can process 240 files in 6 hours. If all files processed by these computers are the same size, how many hours would it take the two computers, working at the same time at their respective constant rates, to process a total of 240 files?
|
[
"A.2",
"B.2.2",
"C.2.4",
"D.2.6"
] | 2
|
C.2.4
|
aqua_rat
|
Both computers together process files at a rate of 240/4 + 240/6 = 60+40 = 100 files per hour.
The time required to process 240 files is 240/100 = 2.4 hours
The answer is C.
|
A sum of Rs. 1530 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is:
|
[
"A.Rs. 120",
"B.Rs. 160",
"C.Rs. 270",
"D.Rs. 300"
] | 2
|
C.Rs. 270
|
aqua_rat
|
EXPLANATION
Let C’s share = Rs. x
Then, B’s share = Rs. x/4 , A’s share = Rs. (2/3 x x/4 ) = Rs. x/6
=x/6 + x/4 + x = 1530
=> 17x/12 = 1530
=> 1530 x 12/ 17 = Rs.1080
Hence, B’s share = Rs. (1080/4) = Rs. 270.
Answer C
|
The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 55 with him, what was the average amount with the group before his joining the group?
|
[
"A.s. 25.6",
"B.s. 155/6",
"C.s. 16.6",
"D.s. 260/6"
] | 1
|
B.s. 155/6
|
aqua_rat
|
Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 55. So, the amount with remaining 6 people = 210 - 55= Rs. 155
The average amount with them = 155/6
ANSWER:B
|
Three of the sides of a rectangular prism have areas of 91, 39, and 21. What is the volume of the rectangular prism?
|
[
"A.252",
"B.269",
"C.273",
"D.920"
] | 2
|
C.273
|
aqua_rat
|
One easy way to get the answer for this question is just multiply the unit's digits of these three numbers, i.e (1*9*1 = 9) (Why the multiplication is needed?, you can see the solution suggested by Bunuel in the above post)
Now look out for the answer whose square gives us a 9 in the unit place.
So, it is easy to pic (C) 273 whose square will give us a 9 in the unit place( 3*3), and hence this is the answer.
|
If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability E that this product will be a multiple of 45?
|
[
"A.1/32",
"B.1/28",
"C.1/24",
"D.1/16"
] | 2
|
C.1/24
|
aqua_rat
|
There are 3 single digit multiple of 3, that is, 3,6,9.
There are 8 prime nos less than 20 - 2,3,5,7,11,13,17,19
Total outcome - 8*3 = 24
Favourable outcome = 1 (9*5)
Hence required probability E= 1/24. Answer C.
|
The average of 13 result is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th result?
|
[
"A.35",
"B.37",
"C.46",
"D.48"
] | 2
|
C.46
|
aqua_rat
|
Sum of all the 13 results = 13 * 60 = 780
Sum of the first 7 of them = 7 * 57 = 399
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 399 - 780 = 46.
C
|
What sum of money will produce Rs.60 as simple interest in 4 years at 3 1/2 percent?
|
[
"A.337",
"B.429",
"C.266",
"D.288"
] | 1
|
B.429
|
aqua_rat
|
60 = (P*4*7/2)/100
P = 429
Answer: B
|
A and B go around a circular track of length 600 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
|
[
"A.120 sec",
"B.165 sec",
"C.186 sec",
"D.167 sec"
] | 0
|
A.120 sec
|
aqua_rat
|
Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 600/ (36 * 5/18) , 600/ (54 * 5 /18) }
= LCM (60, 40)
=120 sec.
Answer:A
|
How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?
|
[
"A.16.5",
"B.16.0",
"C.16.4",
"D.16.8"
] | 3
|
D.16.8
|
aqua_rat
|
D = 110 + 170 = 280 m
S = 60 * 5/18 = 50/3
T = 280 * 3/50 = 16.8 sec
Answer: D
|
What are the last two digits of 55*34*86*47*23*51?
|
[
"A.18",
"B.20",
"C.23",
"D.25"
] | 1
|
B.20
|
aqua_rat
|
55*34*86*47*23*51=
We have to focus on the last two digits only, so 55*34=70*86=20*47=40
40*23=20 therefore 20*51=20
Hence Answer is B
|
A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
|
[
"A.277",
"B.277",
"C.2877",
"D.2000"
] | 3
|
D.2000
|
aqua_rat
|
P(11/10)4 - P(6/5)2 = 482
P = 2000
Answer: D
|
The daytime telephone rate between two cities is 60 cents for the first 3 minutes and c cents for each additional minute. The total charge is reduced 40 percent on calls made after 10:00 P.M. The cost, in dollars, of a 35-minute call made at 10:30 P.M. between these two cities is:
|
[
"A. 0.4(0.60) + 35c",
"B. 0.4(0.60 + 0.32c)",
"C. 0.4(0.60 + 9c)",
"D. 0.6(0.60 + 32c)"
] | 3
|
D. 0.6(0.60 + 32c)
|
aqua_rat
|
For first three minutes = 60 cents
Remaining minutes = 35 -3 = 32
charge for 32 minutes = 32c
total cost (if the call was made in daytime) = 0.60 + 32c
40% chargereducedon night calls => 60% charge
=>0.6(0.60 + 32c)
Hence, Answer is D
|
A cube of side 5cm is painted on all its side. If it is sliced into 1 cubic centimer cubes, how many 1 cubic centimeter cubes will have exactly one of their sides painted?
|
[
"A.9",
"B.61",
"C.98",
"D.54"
] | 3
|
D.54
|
aqua_rat
|
Look at the image below:
Little cubes with exactly one painted side will be those 3*3=9, which are in the center of each face. (6 faces)*(9 per each) = 54.
Answer: D.
|
A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 72. If the marks secured by Reema was written as 36 instead of 86 then find the correct average marks up to two decimal places.
|
[
"A.73.41",
"B.74.31",
"C.72.43",
"D.73.43"
] | 3
|
D.73.43
|
aqua_rat
|
Correct average = 35x72+(86-36)/35
≈ 72 + 1.43 = 73.43
Answer D
|
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
|
[
"A.Rs. 4991",
"B.Rs. 5991",
"C.Rs. 6991",
"D.Rs. 6001"
] | 0
|
A.Rs. 4991
|
aqua_rat
|
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Answer: A
|
A machine P completes a certain amount of work in 12 hrs and machine Q completes the same work in x hrs if both machines works together to complete the same work in 8 hrs then what is x?
|
[
"A.12 hrs",
"B.18 hrs",
"C.24 hrs",
"D.32 hrs"
] | 2
|
C.24 hrs
|
aqua_rat
|
Explanation:
P’s 1hr work = 1/12
Q’s 1 hr work = 1/x
(A+B)’s 1 hr work = 1/8 = 1/12+1/x
=> x = 24 hrs
Answer: Option C
|
In the first 20 overs of a cricket game, the run rate was only 4.3. What should be the run rate in the remaining 30 overs to reach the target of 264 runs?
|
[
"A.5.93",
"B.6.5",
"C.6.75",
"D.7"
] | 0
|
A.5.93
|
aqua_rat
|
Explanation :
Required run rate = (264 - (4.3 x 20))/30 = 178/30 = 5.93
Answer : A
|
The difference between the two digit number and the number obtained by interchanging its digits is 54. The difference between the digits is?
|
[
"A.7",
"B.6",
"C.5",
"D.1"
] | 1
|
B.6
|
aqua_rat
|
Explanation:
(10x + y) – (10y + x) = 54
x – y = 6
Answer: B
|
If a 7 cm cube is cut into 1 cm cubes, then what is the percentage increase in the surface area of the resulting cubes?
|
[
"A.140%",
"B.350%",
"C.450%",
"D.600%"
] | 3
|
D.600%
|
aqua_rat
|
The area A of the large cube is 7*7*6 = 294 square cm.
The area of the 343 small cubes is 7*7*7*6 = 7A, an increase of 600%.
The answer is D.
|
Out of n consecutive natural numbers, four numbers are selected such that the differences of all the possible pairs are distinct. What is the least value of n for which this is possible?
|
[
"A.6",
"B.7",
"C.8",
"D.9"
] | 1
|
B.7
|
aqua_rat
|
Explanation :
Let the 4 numbers be X1, X2, X3, X4 where X1<X2<X3<X4. Let X1 + a1 = X2, X2 + a2 = X3, X3 + a3 = X4. The difference of X1 and each of the other three, of X2 and each of the greater two, of X3 and X4 are tabulated.
X1 X2 X3
X2 a1
X3 a1+a2 a2
X4 a1+a2+a3 a2+a3 a3
We require that n be minimized and these 6 expressions have distinct values. Let X1 = 1
Now, n = 1+a1+a2+a3. Now a1, a2, a3 can be chosen as the least possible values i.e. 1,2 and 3. However the order of chosing should be such that the six expressions (differences) should all be distinct.
By little trial and error (a1, a2, a3) can be (1, 3, 2) or (2, 3, 1) in which case n = 7 and the four numbers can be (1, 2, 5, 7) or (1, 3, 6, 7) respectively.
Hence the minimum value of n is 7.
Answer : B
|
A person is traveling at 65 km/hr and reached his destiny in 3 hr then find the distance?
|
[
"A.205 km",
"B.195 km",
"C.295 km",
"D.115 km"
] | 1
|
B.195 km
|
aqua_rat
|
T = 3 hrs
D= T*S = 65*3 = 195 km
Answer is B
|
The number of boys in the class is 8 more than the number of girls in the class, which is five times the difference between the number of girls and boys in the class.How many boys are there in the class?
|
[
"A.20",
"B.30",
"C.40",
"D.50"
] | 2
|
C.40
|
aqua_rat
|
8+y=5(x-y); y=no of girlz & x=boys
so, y=32 & x=8+y ie 40
40 ans.
ANSWER:C
|
If it is a 3x3 matrix, for which elements in first row are (V, 50, W), second row (196,X, Y)and in third row are (269, Z, 123).It is given that the sum of the numbers in each row, column, diagonal are same. Then find the value of (Y + Z).
|
[
"A.1118",
"B.1119",
"C.1121",
"D.1122"
] | 3
|
D.1122
|
aqua_rat
|
matrix
v 50 w
196 x y
269 z 123
in 1st row and 1st column
v+196+269=v+50+w
w=415
Again, in 2nd column and 3rd row
50+x+z=269+z+123
x=342
As sum of each row column and diagonal are same.
So, 269+342+415=1026
415+y+123=1026
y=488
269+z+123=1026
z=634
y+z=488+634=1122
ANSWER:D
|
Solve 8x – 4 = 4x + 11
|
[
"A.5(1/3)",
"B.6(1/3)",
"C.7(1/3)",
"D.3(3/4)"
] | 3
|
D.3(3/4)
|
aqua_rat
|
Sol.
8x – 4 = 4x + 11
=> 8x – 4x = 11 + 4
=> 4x = 15 => x = 15/3 = 3(3/4).
Answer D
|
3,4,7,11,18,29,47,?
|
[
"A.76",
"B.77",
"C.75",
"D.78"
] | 0
|
A.76
|
aqua_rat
|
Each number is the sum of the previous two numbers, ie 29 + 47 = 76.
Answer : A
|
The greatest number of four digits which is divisible by 10, 20, 25 and 60 is:
|
[
"A.9000",
"B.9300",
"C.9400",
"D.9600"
] | 0
|
A.9000
|
aqua_rat
|
Greatest number of 4-digits is 9999.
L.C.M. of 10, 20, 25 and 60 is 1500.
On dividing 9999 by 1500, the remainder is 999.
Required number (9999 - 999) = 9000.
ANSWER :A
|
A company, Chauncy Co., has an annual travel budget of $59,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
|
[
"A.Expenses will not go over the budget.",
"B.$500",
"C.$4,225",
"D.$1,725"
] | 3
|
D.$1,725
|
aqua_rat
|
annual travel budget of $59,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 59000-60725 = 1725
Answer: Option D
|
If each term in the sum a1+a2+a3+.....+an is either 7 or 77 and the sum equals 343, which of the following could be equal to n?
|
[
"A.38",
"B.39",
"C.40",
"D.41"
] | 1
|
B.39
|
aqua_rat
|
Since, there is no 49 in the answer choices (343/7 = 49), we know there is at least one 77.
343 - 77 = 266
266/7 = 38
38+1 = 39.
If 39 wasn't there, I would have subtracted 77 from 266 and continued in a similar way.
Ans.B
|
Company P had 15 percent more employees in December than it had in January. If Company P had 470 employees in December, how many employees did it have in January?
|
[
"A. 391",
"B. 408",
"C. 410",
"D. 423"
] | 1
|
B. 408
|
aqua_rat
|
D = number of employees in December
J = number of employees in January
J x 1.15 = D
J x 1.15 = 470
J = 470/1.15
J = 47,000/115 = 408
Thus B is the correct answer.
|
Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?
|
[
"A.5",
"B.6",
"C.1",
"D.7"
] | 0
|
A.5
|
aqua_rat
|
2M + 3W ----- 35 h
4M + 4W ------- 21 h
7M -------? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 days
Answer: A
|
If log 2= 0.030103, the number of digits in 264 is :
|
[
"A.18",
"B.19",
"C.20",
"D.21"
] | 2
|
C.20
|
aqua_rat
|
log 264 = 64 log 2 = (64*0.30103) = 1926592
Its characteristics is 19.
Hence, the number of digits in 264 is 20.
ANSWER:C
|
If air is called green , green is called blue, blue is called orange, sky is called yellow, yellow is called water and water is called pink, then what is the color of clear sky ?
|
[
"A.Orange",
"B.Sky",
"C.Water",
"D.Yellow"
] | 0
|
A.Orange
|
aqua_rat
|
Explanation:
The colour of clear sky is 'blue' and as given, 'blue' is called 'orange'.
So, the colour of clear sky is 'orange'.
Answer: A
|
A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.12000. A's share is?
|
[
"A.8876",
"B.2765",
"C.4000",
"D.1298"
] | 2
|
C.4000
|
aqua_rat
|
x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 12000 = 4000
Answer:C
|
In a panel of 10 light bulbs, the odds of any light bulb to burn out are 0.7 at any given 10 minutes. Should a light bulb burn out, the whole panel would instantly turn off. What are the odds that the panel would be turned off within the first 10 minutes after it was switched on?
|
[
"A.1-0.06^10",
"B.1-0.3^10",
"C.(1-0.3)^10",
"D.0.06"
] | 1
|
B.1-0.3^10
|
aqua_rat
|
ans B.
Prob that light will not turned off = 0.3^10. Hence prob (turn off) = 1 - prob (not turn off).
|
A tap can fill a tank in 10 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely?
|
[
"A.5 hrs 15 mins",
"B.11 hrs 15 mins",
"C.3 hrs 15 mins",
"D.6 hrs 15 mins"
] | 1
|
B.11 hrs 15 mins
|
aqua_rat
|
Time taken by one tap to fill the tank = 5 hrs.
Part filled by the taps in 1 hour = 4 * 1/10 = 2/5
Remaining part = 1 - 1/2 = 1/2
2/5 : 1/2 :: 1 : x
x = 1/2 * 1 * 5/2 = 5/4 = 1 hr 15 mins
So, total time taken = 11 hrs 15 mins
ANSWER: B
|
A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
|
[
"A.30%",
"B.10%",
"C.20%",
"D.19%"
] | 1
|
B.10%
|
aqua_rat
|
2420 --- 242
100 --- ? => 10%
Answer: B
|
In a card game, a combination of three kings beats all others. If Jose is the first to draw from a standard deck of 52 cards, what is the probability that he wins the game with the best possible combination?
|
[
"A.1/5550",
"B.1/5600",
"C.1/5400",
"D.1/5525"
] | 3
|
D.1/5525
|
aqua_rat
|
he best possible combination is the case when he wins in his first two draws
There are 52 cards in a deck of cards with 4 kings in it.
Probability of first card to be king = 4/52
Probability of Second card to be king = 3/51
Probability of third card to be king = 2/50
Probability of Best possible case = (4/52)*(3/51)*(2/50) = 1/5525
D
|
Two trains travelling in the same direction at 40 and 22 kmph completely pass off another in 1 minute. If the length of the first train is 125 m, what is the length of the second train?
|
[
"A.228",
"B.266",
"C.175",
"D.99"
] | 2
|
C.175
|
aqua_rat
|
RS = 40 – 22 = 18 * 5/18 = 5 mps
T = 60 sec
D = 5 * 60 = 300 m
125
--------
175 m
Answer: C
|
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is?
|
[
"A.650",
"B.690",
"C.698",
"D.700"
] | 2
|
C.698
|
aqua_rat
|
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Answer: Option C
|
A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C?
|
[
"A.100",
"B.400",
"C.300",
"D.500"
] | 1
|
B.400
|
aqua_rat
|
Explanation :
Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
Amount to be paid to C = 3200 × (1/8) = 400
ANSWER:B
|
A man has Rs.355 in the denominations of one-rupee notes, 20-rupee notes and 50-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
|
[
"A.20",
"B.15",
"C.71",
"D.40"
] | 1
|
B.15
|
aqua_rat
|
Let number of notes of each denomination be x.
Then x + 20x + 50x = 355
71x = 355
x = 5
Hence, total number of notes = 3x = 15.
Answer is B.
|
If √10 = 3.16, find the value of If √5/2
|
[
"A.1.3",
"B.1.58",
"C.2.03",
"D.2.15"
] | 1
|
B.1.58
|
aqua_rat
|
Explanation:
√(5/2) =√(5×2/2×2)= √(10)/2 =3.16/2 = 1.58
ANSWER: B
|
What should come in place of the question mark (?) in the following equation?
6000 + 500 = 870+ ?
|
[
"A.6789",
"B.3654",
"C.5630",
"D.6777"
] | 2
|
C.5630
|
aqua_rat
|
6000 + 500 = 870+ ?
6000 + 500 – 870= 5630
Answer C
|
A water tank is two-fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely ?
|
[
"A.6 min to empty",
"B.7 min to full",
"C.6 min to full",
"D.7 min to empty"
] | 0
|
A.6 min to empty
|
aqua_rat
|
Explanation:
There are two important points to learn in this type of question,
First, if both will open then tank will be empty first.
Second most important thing is,
If we are calculating filling of tank then we will subtract as (filling-empting)
If we are calculating empting of thank then we will subtract as (empting-filling)
So lets come on the question now,
Part to emptied 2/5
Part emptied in 1 minute = 1/6-1/10=1/15
=>1/15:2/5::1:x
=>2/5∗15=6mins
ANSWER IS A
|
In a class of 30 students, 5 students did not borrow any books from the library, 10 students each borrowed 1 book, 8 students each borrowed 2 books, and the rest of the students each borrowed at least 4 books. If the average (arithmetic mean) number of books borrowed per student was 2, what is the maximum number of books that any single student could have borrowed ?
|
[
"A.5",
"B.8",
"C.16",
"D.18"
] | 2
|
C.16
|
aqua_rat
|
The average number of books per student was 2means that total of 2*30=60 books were borrowed;
5+12+8=25 students borrowed total of 5*0+12*1+8*2=28 books;
So 60-28=32 books are left to distribute among 30-25=5 students, these 5 arethe rest who borrowed at least 4 books;
Tomaximizethe number of books one student from above 5 could have borrowed we shouldminimizethe number of books other 4 students from 5 could have borrowed. Minimum these 4 students could have borrowed is 4 books per student, so total number of books they could have borrowed is 4*4=16 books. So the 5th student could have borrowed is 32-16=16 books.
Answer: C.
|
The L.C.M of two numbers is 45 times their H.C.F if one of the numbers is 125and sum of H.C.F and L.C.M. is 1150, the other number is:
|
[
"A.215",
"B.220",
"C.225",
"D.235"
] | 2
|
C.225
|
aqua_rat
|
Let H.C.F be h and L.CM be l.Then, l-45h and l+h=1150
45h+h=1150 or h=25.so, l=(1150-25)-1125.
Hence, other number=(25*1125/125)=225.
Correct Option:C
|
A two member committee comprising of one male and one female member is to be constitute out of five males and three females. Amongst the females. Ms. A refuses to be a member of the committee in which Mr. B is taken as the member. In how many different ways can the committee be constituted ?
|
[
"A.11",
"B.12",
"C.13",
"D.14"
] | 3
|
D.14
|
aqua_rat
|
Solution: 5C1 * 3C1 -1
= 15-1
= 14
Answer: Option D
|
A man on tour travels first 160 km at 64 km/he and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is?
|
[
"A.71.17 km/hr",
"B.71.21 km/hr",
"C.71.11 km/hr",
"D.81.11 km/hr"
] | 2
|
C.71.11 km/hr
|
aqua_rat
|
Total time taken = (160/64 + 160/8) = 9/2 hrs.
Average speed = 320 * 2/9 = 71.11 km/hr.
Answer:C
|
Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
|
[
"A.Rs.15000",
"B.15002",
"C.26879",
"D.26992"
] | 0
|
A.Rs.15000
|
aqua_rat
|
Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x
= Rs. 1.08x = 18000 - 10/100(18000)
= 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
|
A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 25 days starting with sunday is
|
[
"A.342",
"B.285",
"C.290",
"D.295"
] | 0
|
A.342
|
aqua_rat
|
Explanation:
As the month begin with sunday, so there will be five sundays in the month. So result will be:
=(510×5+240×25/30)=(8550/25)=342
Answer: Option A
|
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
|
[
"A.36 kg",
"B.42 kg",
"C.54 kg",
"D.63 kg"
] | 3
|
D.63 kg
|
aqua_rat
|
Explanation:
S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.
C.P. of 1 kg of mixture = Rs.(100/110 x 9.24)= Rs. 8.40
By the rule of allilation, we have:
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27
x =(7x 27 / 3)= 63 kg.
ANSWER IS D
|
The probabilities of solving a question by 3students A, B & C are 1/2,1/3 &1/4, respectively. The probability that the problem will be solved is?
|
[
"A.1/2",
"B.3/4",
"C.3/5",
"D.3/7"
] | 1
|
B.3/4
|
aqua_rat
|
Sol. First, we find the probability of not solving the problem x PTO x = (1 — D x - D x - D
1 2 3 1 =iXiX71=4;
1 3 Required probability 3/4
B
|
What is the average (arithmetic mean) of all the multiples of ten from 10 to 170 inclusive?
|
[
"A.90",
"B.80",
"C.100",
"D.105"
] | 1
|
B.80
|
aqua_rat
|
10 and 190 inclusive would mean there are 17 terms.
No need to add up all the terms and further divide by 17 since the terms are evenly spaced in ascending order from 10, 20, 30........170
The middle term is the average which is the tenth term = 80
B is the answer.
|
Pipe A can fill a tank in 9 hours, pipe B in 12 hours, and pipe C in 18 hours. If all the pipes are open, in how many hours will the tank be filled?
|
[
"A.2",
"B.3",
"C.4",
"D.5"
] | 2
|
C.4
|
aqua_rat
|
The part filled by A + B + C in 1 hour
= 1/9 + 1/12 + 1/18
= 9/36 = 1/4
All the three pipes together will fill the tank in 4 hours.
The answer is C.
|
A bartender removed from a bottle a certain quantity of a drink which had 25 % ALCOHOL CONTENT and replaced the same quantity with another drink that had an alcohol content of 10%. The alcohol content in the drink after replacement is 20 % What the quantity of the drink that he replaced if there was 1 Litres of the drink in the bottle
|
[
"A.1/2",
"B.1/3",
"C.2/3",
"D.3/5"
] | 1
|
B.1/3
|
aqua_rat
|
1 litre of drink = 1000 milliliters
Let x be the quantity taken out
We now have 1000 - x quantity of liquid => there is 0.25(1000-x) quantity of alcohol. --- (1)
Now, we add x amount of alcohol from a 10% concentrate. It means 0.1x alcohol is added ---(2)
Since it says final alcohol content in 1 litre of drink is 20% or 200 milli litre
from (1) and (2) above -
(1000-x)0.25 + 0.1x = 200
Solving for x, we get 333.33 ml or 1/3 of a litre
ANSWER:B
|
There are 200 questions in a 3 hr examination. Among these questions there are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems
|
[
"A.36 minutes",
"B.60 minutes",
"C.72 minutes",
"D.100 minutes"
] | 2
|
C.72 minutes
|
aqua_rat
|
Explanation :
Let x = minutes spent on a non-math problem
then 2x = minutes spent on a math problem
x(200-50) + 2x(50) = 180
x(150) + 2x(50) = 180
150x + 100x = 180
250x = 180
x = 0.72 minutes
Time to spend on math problems:
2x(50)=100x = 100(0.72) = 72 minutes
Answer : C
|
The Income of a man increase consistently by 2% per year. If his present income is Rs. 12000 then what will his income be after 1 year ?
|
[
"A.12040",
"B.12140",
"C.12240",
"D.12340"
] | 2
|
C.12240
|
aqua_rat
|
Explanation :
Income = 12000 x 1.02 = 12240
Answer : Option C
|
Two men started from the same place walk at the rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5 km apart, if they walk in the same direction?
|
[
"A.10hours",
"B.12hours",
"C.17hours",
"D.15hours"
] | 2
|
C.17hours
|
aqua_rat
|
To be 0.5km apart they take 1 hour
To be 8.5km apart they take = 1/0.5 * 8.5 = 17 hours
Answer is C
|
What distance (in meters) will be covered by a bus moving at 54 km/hr in 30 seconds?
|
[
"A.390",
"B.420",
"C.450",
"D.480"
] | 2
|
C.450
|
aqua_rat
|
54 km/hr = 54 * 5/18 = 15 m/s
distance = 15 * 30 = 450 meters
The answer is C.
|
A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1800. The difference between the profit shares of A and C is?
|
[
"A.720",
"B.266",
"C.155",
"D.600"
] | 0
|
A.720
|
aqua_rat
|
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1800
=> 5 parts out of 15 parts is Rs. 1800
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1800) = Rs. 720
Answer:A
|
A total of $20,000 was invested in two certificates of deposit at simple annual interest rates of 6 percent and 10 percent, respectively. If the total interest on the two certificates was $1,440 at the end of one year, what fractional part of the $20.000 was invested at the higher rate?
|
[
"A. 3/8",
"B. 9/10",
"C. 1/2",
"D. 3/5"
] | 1
|
B. 9/10
|
aqua_rat
|
x * 6/100 * 1 + (20000 - x) * 10/100 * 1 = 1440
6x - 8x = 144000 - 200000
=> -2x = -4000
=> x = 2000
So 18000/20000 = 9/10
Answer - B
|
The sale price sarees listed for Rs.400 after successive discount is 25% and 20% is?
|
[
"A.297",
"B.879",
"C.342",
"D.240"
] | 3
|
D.240
|
aqua_rat
|
400*(75/100)*(80/100)
= 240
Answer: D
|
A bus travels from town A to town B. If the bus's speed is 50 km/hr, it will arrive in town B 42 min later than scheduled. If the bus increases its speed by 509509 m/sec, it will arrive in town B 30 min earlier than scheduled. Find:
A) The distance between the two towns;
B) The bus's scheduled time of arrival in B;
C) The speed of the bus when it's on schedule.
|
[
"A.60",
"B.37",
"C.26",
"D.28"
] | 0
|
A.60
|
aqua_rat
|
First we will determine the speed of the bus following its increase. The speed is increased by 509509 m/sec =50⋅60⋅6091000=50⋅60⋅6091000 km/hr =20=20 km/hr. Therefore, the new speed is V=50+20=70V=50+20=70 km/hr. If xx is the number of hours according to the schedule, then at the speed of 50 km/hr the bus travels from A to B within (x+4260)(x+4260) hr. When the speed of the bus is V=70V=70 km/hr, the travel time is x−3060x−3060 hr. Then
50(x+4260)=70(x−3060)50(x+4260)=70(x−3060)
5(x+710)=7(x−12)5(x+710)=7(x−12)
72+72=7x−5x72+72=7x−5x
2x=72x=7
x=72x=72 hr.
So, the bus is scheduled to make the trip in 33 hr 3030 min.
The distance between the two towns is 70(72−12)=70⋅3=21070(72−12)=70⋅3=210 km and the scheduled speed is 210/7/2=60 km/hr.
Answer:A
|
If x = |x| , then which one of the following statements could be true?
I. x = 0
II. x < 0
III. x > 0
|
[
"A. None",
"B. I only",
"C. III only",
"D. I and II and III"
] | 3
|
D. I and II and III
|
aqua_rat
|
Answer copied from NOVA guide
Statement I could be true because ± 0 = −(+0) = −(0) = 0 .
Statement II could be true because the right side of the equation is always negative [ ± x = (a positive number) = a negative number].
Now, if one side of an equation is always negative, then the other side must always be negative,
otherwise the opposite sides of the equation would not be equal.
Since Statement III is the opposite of Statement II, it must be false. But let’s show this explicitly:
Suppose x were positive. Then x = x, and the equation x = ± x becomes x = x. Dividing both sides of this equation by x yields 1 = 1. This is contradiction.
Hence, x cannot be positive. The answer is (D).
|
Maddie has 24 apples, if she give 12 to mike, how many does she have left?
|
[
"A.12",
"B.14",
"C.16",
"D.18"
] | 0
|
A.12
|
aqua_rat
|
24-12=12
A 12
|
A stick of 30 cm is broken into two pieces, what is the length of the shorter piece if the longer piece is 6 cm longer than the other?
|
[
"A.11",
"B.10",
"C.12",
"D.13"
] | 2
|
C.12
|
aqua_rat
|
Since, 30 is the total length. Smaller is any one from answers.
Try Back solving from answer D, i.e. 12. 12+(12+6) = 31 > 30
Hence, Select next smaller no. : 12 +(12+6) =30.
So, 12 is the answer
Answer is C
|
A shopkeeper sold an article for Rs 2552.36. Approximately what was his profit percent if the cost price of the article was Rs 2400
|
[
"A.4%",
"B.5%",
"C.6%",
"D.7%"
] | 2
|
C.6%
|
aqua_rat
|
Explanation:
Gain % = (152.36*100/2400) = 6.34 % = 6% approx
Option C
|
A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
|
[
"A.5",
"B.6",
"C.7",
"D.9"
] | 1
|
B.6
|
aqua_rat
|
Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.
Answer: B
|
Irin, Ingrid and Nell bake chocolate chip cookies in the ratio of 9.18: 5.17: 2.05. If altogether they baked a batch of 148 cookies, what percent of the cookies did Nell bake?
|
[
"A.0.125%",
"B.1.25%",
"C.12.5%",
"D.125%"
] | 2
|
C.12.5%
|
aqua_rat
|
9.18x+5.17x+2.05x = 16.4x = 148 cookies
x= 148/16.4 = 9 (approx)
So, tell baked 9*2.05 cookies or 19 cookies (approx)
% share = 19/148 = 12.5 approx
Hence, answer is C.
|
On adding four times the age of Chris Hemsworth four years from now to five times his age five years from now, we will get ten times his current age.
How old is Chris right now?
|
[
"A.38 years",
"B.24 years",
"C.40 years",
"D.41 years"
] | 3
|
D.41 years
|
aqua_rat
|
D
41 years.
If the current age of Dakota is x
4(x+4) + 4(x+5) = 10x
Thus x=41 years
|
If a, b, c are integers; a² + b² = 45 and b² + c² = 40, then the values of a, b and c respectively are :
|
[
"A.2, 6, 3",
"B.3, 2, 6",
"C.5, 4, 3",
"D.4,5,3"
] | 1
|
B.3, 2, 6
|
aqua_rat
|
a² + b² = 45 ….(1) and b² + c² = 40
Subtracting, we get: a² - c² = 5 => (a + c) (a – c) = 5.
(a + c) = 5 and (a – c) = 1.
Solving we get: a = 3, c = 2. Putting c = 2 in (ii), we get b = 6.
ANSWER:B
|
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