def search_list(list_provided):
 for i in range((len(list_provided) - 1)):
  if ((not (list_provided[i] in list_provided[(i + 1):])) and (not (list_provided[i] in list_provided[:i]))):
   'If the same number is not present before or after in the list then\n            return the number'
   return str(list_provided[i])
   break

def search_list ( list_provided ) : for i in range ( ( len ( list_provided ) - 1 ) ) : if ( ( not ( list_provided [ i ] in list_provided [ ( i + 1 ) : ] ) ) and ( not ( list_provided [ i ] in list_provided [ : i ] ) ) ) : return str ( list_provided [ i ] ) break
search list provided for characters that are represented only once .