<gh_stars>100-1000
# Copyright 2018 The Lucid Authors. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
# ==============================================================================

"""Convert an "image" with n channels into 3 RGB channels."""

from __future__ import absolute_import, division, print_function

import math
import numpy as np


def hue_to_rgb(ang, warp=True):
    """Produce an RGB unit vector corresponding to a hue of a given angle."""
    ang = ang - 360*(ang//360)
    colors = np.asarray([
        [1, 0, 0],
        [1, 1, 0],
        [0, 1, 0],
        [0, 1, 1],
        [0, 0, 1],
        [1, 0, 1],
    ])
    colors = colors / np.linalg.norm(colors, axis=1, keepdims=True)
    R = 360 / len(colors)
    n = math.floor(ang / R)
    D = (ang - n * R) / R

    if warp:
        # warping the angle away from the primary colors (RGB)
        # helps make equally-spaced angles more visually distinguishable
        adj = lambda x: math.sin(x * math.pi / 2)
        if n % 2 == 0:
            D = adj(D)
        else:
            D = 1 - adj(1 - D)

    v = (1-D) * colors[n] + D * colors[(n+1) % len(colors)]
    return v / np.linalg.norm(v)


def sparse_channels_to_rgb(array):
    assert (array >= 0).all()

    channels = array.shape[-1]

    rgb = 0
    for i in range(channels):
        ang = 360 * i / channels
        color = hue_to_rgb(ang)
        color = color[tuple(None for _ in range(len(array.shape)-1))]
        rgb += array[..., i, None] * color

    rgb += np.ones(array.shape[:-1])[..., None] * (array.sum(-1) - array.max(-1))[..., None]
    rgb /= 1e-4 + np.linalg.norm(rgb, axis=-1, keepdims=True)
    rgb *= np.linalg.norm(array, axis=-1, keepdims=True)

    return rgb


def collapse_channels(array):
    if (array < 0).any():
        array = np.concatenate([np.maximum(0, array), np.maximum(0, -array)], axis=-1)
    return sparse_channels_to_rgb(array)

# Copyright 2018 The Lucid Authors. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
# ==============================================================================

"""Convert an "image" with n channels into 3 RGB channels."""

from __future__ import absolute_import, division, print_function

import math
import numpy as np


def hue_to_rgb(ang, warp=True):
    """Produce an RGB unit vector corresponding to a hue of a given angle."""
    ang = ang - 360*(ang//360)
    colors = np.asarray([
        [1, 0, 0],
        [1, 1, 0],
        [0, 1, 0],
        [0, 1, 1],
        [0, 0, 1],
        [1, 0, 1],
    ])
    colors = colors / np.linalg.norm(colors, axis=1, keepdims=True)
    R = 360 / len(colors)
    n = math.floor(ang / R)
    D = (ang - n * R) / R

    if warp:
        # warping the angle away from the primary colors (RGB)
        # helps make equally-spaced angles more visually distinguishable
        adj = lambda x: math.sin(x * math.pi / 2)
        if n % 2 == 0:
            D = adj(D)
        else:
            D = 1 - adj(1 - D)

    v = (1-D) * colors[n] + D * colors[(n+1) % len(colors)]
    return v / np.linalg.norm(v)


def sparse_channels_to_rgb(array):
    assert (array >= 0).all()

    channels = array.shape[-1]

    rgb = 0
    for i in range(channels):
        ang = 360 * i / channels
        color = hue_to_rgb(ang)
        color = color[tuple(None for _ in range(len(array.shape)-1))]
        rgb += array[..., i, None] * color

    rgb += np.ones(array.shape[:-1])[..., None] * (array.sum(-1) - array.max(-1))[..., None]
    rgb /= 1e-4 + np.linalg.norm(rgb, axis=-1, keepdims=True)
    rgb *= np.linalg.norm(array, axis=-1, keepdims=True)

    return rgb


def collapse_channels(array):
    if (array < 0).any():
        array = np.concatenate([np.maximum(0, array), np.maximum(0, -array)], axis=-1)
    return sparse_channels_to_rgb(array)
# Copyright 2018 The Lucid Authors. All Rights Reserved. # # Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # #     http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. # See the License for the specific language governing permissions and # limitations under the License. # ============================================================================== Convert an "image" with n channels into 3 RGB channels. Produce an RGB unit vector corresponding to a hue of a given angle. # warping the angle away from the primary colors (RGB) # helps make equally-spaced angles more visually distinguishable