Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
perimeter of triangle withsides 41, 13,16 = 70
| 70 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 13 + 16 = 70
|
56 * 59 = 3304
| 3,304 |
Step 1: Compute 56 * 59.
Step 2: The result is 3304.
|
area of circle withradius 14 = 615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
50* 41 = 2050
| 2,050 |
Step 1: Compute 50 * 41.
Step 2: The result is 2050.
|
area of rectangle with width 22 and height47 = 1034
| 1,034 |
Step 1: Area formula is width × height.
Step 2: 22 × 47 = 1034
|
hypotenuse of righttriangle with legs11 and3 = 11.40
| 11.4 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 3²) = sqrt(121 + 9) = sqrt(130) = 11.40
|
7 ** 3= 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
areaof circlewithradius 19= 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
perimeterofrectanglewith width 11and height12= 46
| 46 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (11 + 12) = 2 × 23 = 46
|
area of triangle withbase 28and height50 = 700.00
| 700 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 28 × 50 = 700.00
|
(51) * 99= 5049
| 5,049 |
Step 1: Compute 51 * 99.
Step 2: The result is 5049.
|
40 /5=8
| 8 |
Step 1: Compute 40 / 5.
Step 2: The result is 8.
|
perimeter ofcirclewith radius 12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
perimeter of rectangle withwidth 9and height 26 =70
| 70 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (9 + 26) = 2 × 35 = 70
|
area of circlewith radius 18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
perimeterofrectangle with width3 and height 42 =90
| 90 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (3 + 42) = 2 × 45 = 90
|
21 +8 = 29
| 29 |
Step 1: Compute 21 + 8.
Step 2: The result is 29.
|
45/5= 9
| 9 |
Step 1: Compute 45 / 5.
Step 2: The result is 9.
|
53 + 10=63
| 63 |
Step 1: Compute 53 + 10.
Step 2: The result is 63.
|
hypotenuse of right triangle with legs27 and14= 30.41
| 30.41 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 14²) = sqrt(729 + 196) = sqrt(925) = 30.41
|
perimeter of triangle with sides 25,37, 38 = 100
| 100 |
Step 1: Perimeter formula is a + b + c.
Step 2: 25 + 37 + 38 = 100
|
(9)%(10)= 9
| 9 |
Step 1: Compute 9 % 10.
Step 2: The result is 9.
|
perimeterof rectanglewith width40andheight 34 =148
| 148 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 34) = 2 × 74 = 148
|
perimeter of circlewithradius 4=25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
hypotenuseof right trianglewith legs 10and 4 =10.77
| 10.77 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(10² + 4²) = sqrt(100 + 16) = sqrt(116) = 10.77
|
82 % 13 = 4
| 4 |
Step 1: Compute 82 % 13.
Step 2: The result is 4.
|
96+ 73 = 169
| 169 |
Step 1: Compute 96 + 73.
Step 2: The result is 169.
|
60% (7) =4
| 4 |
Step 1: Compute 60 % 7.
Step 2: The result is 4.
|
area ofrectangle withwidth 3 andheight 48 = 144
| 144 |
Step 1: Area formula is width × height.
Step 2: 3 × 48 = 144
|
1% 15= 1
| 1 |
Step 1: Compute 1 % 15.
Step 2: The result is 1.
|
area ofrectangle withwidth 11 and height19=209
| 209 |
Step 1: Area formula is width × height.
Step 2: 11 × 19 = 209
|
(10) ** (2) = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
perimeter of rectangle with width32 andheight 18= 100
| 100 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (32 + 18) = 2 × 50 = 100
|
perimeter of circle with radius3 = 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
(19) + 47 = 66
| 66 |
Step 1: Compute 19 + 47.
Step 2: The result is 66.
|
(7) **3= 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
perimeter ofrectangle with width 33 and height 32 =130
| 130 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 32) = 2 × 65 = 130
|
22 * (58) = 1276
| 1,276 |
Step 1: Compute 22 * 58.
Step 2: The result is 1276.
|
100% (8) = 4
| 4 |
Step 1: Compute 100 % 8.
Step 2: The result is 4.
|
hypotenuseof right triangle with legs 11and 6= 12.53
| 12.53 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 6²) = sqrt(121 + 36) = sqrt(157) = 12.53
|
perimeter of circlewith radius 1 =6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
area of circlewith radius 2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
areaofcircle with radius 7 = 153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
78/13= 6
| 6 |
Step 1: Compute 78 / 13.
Step 2: The result is 6.
|
perimeterofcircle with radius10 =62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
perimeter of rectangle with width 49 and height9 = 116
| 116 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 9) = 2 × 58 = 116
|
43% 12 = 7
| 7 |
Step 1: Compute 43 % 12.
Step 2: The result is 7.
|
45 % 9 =0
| 0 |
Step 1: Compute 45 % 9.
Step 2: The result is 0.
|
69 - (60)= 9
| 9 |
Step 1: Compute 69 - 60.
Step 2: The result is 9.
|
perimeter oftriangle with sides 30,22,25 = 77
| 77 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 22 + 25 = 77
|
area ofcircle with radius 8 =201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
perimeteroftrianglewith sides 33, 22,15 = 70
| 70 |
Step 1: Perimeter formula is a + b + c.
Step 2: 33 + 22 + 15 = 70
|
area oftriangle with base23 and height 27 = 310.50
| 310.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 23 × 27 = 310.50
|
(16)- (36) =-20
| -20 |
Step 1: Compute 16 - 36.
Step 2: The result is -20.
|
10 **3 = 1000
| 1,000 |
Step 1: Compute 10 ** 3.
Step 2: The result is 1000.
|
14 %2 = 0
| 0 |
Step 1: Compute 14 % 2.
Step 2: The result is 0.
|
(60) / 15=4
| 4 |
Step 1: Compute 60 / 15.
Step 2: The result is 4.
|
171 / 19 = 9
| 9 |
Step 1: Compute 171 / 19.
Step 2: The result is 9.
|
(42) /7 =6
| 6 |
Step 1: Compute 42 / 7.
Step 2: The result is 6.
|
hypotenuse of right triangle withlegs 20and 18 =26.91
| 26.91 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 18²) = sqrt(400 + 324) = sqrt(724) = 26.91
|
perimeter of triangle with sides8, 42, 42 =92
| 92 |
Step 1: Perimeter formula is a + b + c.
Step 2: 8 + 42 + 42 = 92
|
perimeterof trianglewithsides 14, 3, 10 = 27
| 27 |
Step 1: Perimeter formula is a + b + c.
Step 2: 14 + 3 + 10 = 27
|
perimeter of circlewith radius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
area ofcircle withradius 3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
15 - (64) = -49
| -49 |
Step 1: Compute 15 - 64.
Step 2: The result is -49.
|
areaof circle with radius 11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
perimeter of triangle with sides 22, 50, 23 = 95
| 95 |
Step 1: Perimeter formula is a + b + c.
Step 2: 22 + 50 + 23 = 95
|
(30) / (15) =2
| 2 |
Step 1: Compute 30 / 15.
Step 2: The result is 2.
|
130 / 13 =10
| 10 |
Step 1: Compute 130 / 13.
Step 2: The result is 10.
|
87 + 50 =137
| 137 |
Step 1: Compute 87 + 50.
Step 2: The result is 137.
|
perimeter oftriangle with sides 36, 33,33 = 102
| 102 |
Step 1: Perimeter formula is a + b + c.
Step 2: 36 + 33 + 33 = 102
|
(10) ** (2) = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
hypotenuseof right triangle with legs28and 9= 29.41
| 29.41 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(28² + 9²) = sqrt(784 + 81) = sqrt(865) = 29.41
|
94+33 = 127
| 127 |
Step 1: Compute 94 + 33.
Step 2: The result is 127.
|
12 / (6) = 2
| 2 |
Step 1: Compute 12 / 6.
Step 2: The result is 2.
|
2 ** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
5 + 86 = 91
| 91 |
Step 1: Compute 5 + 86.
Step 2: The result is 91.
|
57 % 10 = 7
| 7 |
Step 1: Compute 57 % 10.
Step 2: The result is 7.
|
area of circle with radius 1 =3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
perimeter of trianglewith sides49,5, 7 = 61
| 61 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 5 + 7 = 61
|
area of circle withradius 6 = 113.10
| 113.1 |
Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10
|
12- 29= -17
| -17 |
Step 1: Compute 12 - 29.
Step 2: The result is -17.
|
89 *80 =7120
| 7,120 |
Step 1: Compute 89 * 80.
Step 2: The result is 7120.
|
hypotenuse of right triangle with legs 2 and 21 = 21.10
| 21.1 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 21²) = sqrt(4 + 441) = sqrt(445) = 21.10
|
area of triangle withbase 16 and height 22= 176.00
| 176 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 22 = 176.00
|
perimeter of circle with radius 1 =6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
7 **4 =2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
area ofcircle with radius 3 = 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(7)** (4)= 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
(2) ** (4) = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
152/ 19 = 8
| 8 |
Step 1: Compute 152 / 19.
Step 2: The result is 8.
|
area ofcircle with radius3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(44) % (2)= 0
| 0 |
Step 1: Compute 44 % 2.
Step 2: The result is 0.
|
areaof circle with radius2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
(2) /1=2
| 2 |
Step 1: Compute 2 / 1.
Step 2: The result is 2.
|
perimeter oftriangle with sides 17, 20, 12 = 49
| 49 |
Step 1: Perimeter formula is a + b + c.
Step 2: 17 + 20 + 12 = 49
|
perimeter of rectangle withwidth2andheight 20= 44
| 44 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 20) = 2 × 22 = 44
|
perimeterof rectangle with width9 and height 39=96
| 96 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (9 + 39) = 2 × 48 = 96
|
4 **2 =16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
hypotenuse of right triangle withlegs 17 and 5 =17.72
| 17.72 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 5²) = sqrt(289 + 25) = sqrt(314) = 17.72
|
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