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DENVER (AP) — Two hyenas at the Denver Zoo have tested positive for the coronavirus, the first confirmed cases among the animals worldwide, a national veterinary lab announced Friday.
Samples from a variety of animals at the zoo, including the spotted hyenas, were tested after several lions at the facility became ill, according to the National Veterinary Services Laboratories. The hyena samples tested presumptive positive at a lab at Colorado State University, and the cases were confirmed by the national lab.
In addition to the two hyenas, 11 lions and two tigers at the zoo tested positive for the virus.
“Hyenas are famously tough, resilient animals that are known to be highly tolerant to anthrax, rabies and distemper. They are otherwise healthy and expected to make a full recovery,” the zoo said in a statement.
Zoo officials said the hyenas — 22-year-old Ngozi and 23-year-old Kibo — are experiencing mild symptoms, including slight lethargy, some nasal discharge and an occasional cough.
The other animals that tested positive in recent weeks have either fully recovered or are on the path to a full recovery.
“We now know that many other species may be susceptible to COVID-19 based on multiple reports, and we continue to use the highest level of care and precaution when working with all of our 3,000 animals and 450 different species,” the statement said..Q: dynamic allocation of matrix this function is supposed to allocate a matrix ('resMat') of 1 rows with 2 cols.
for some reason all I get in'resMat' is 1 row with 1 col.
any idea why?
thanks.
void Ex2()
{
    int** resMat = NULL;
    int rows = 1;
    int* cols = (int*)calloc(rows, sizeof(int*));
    cols = {2};
    int i;
    resMat = (int**)calloc(rows, sizeof(int*));
    assert(resMat);
    for (i = 0; i < rows; i++)
    {
        resMat[i] = (int*)calloc(cols[i], sizeof(int)); // cols[i]=cols[0]=2
        assert(resMat[i]);
    }   

I changed the code a bit to be more readable. 'rows' and 'cols' are actually defined by other functions and that's why 'cols' is an array(in case rows>1)

A: These statements
int* cols = (int*)calloc(rows, sizeof(int*));
cols = {2};

that produce a memory leak (at first the pointer cols was initialized with the address of the allocated memory and then was reassigned by the integer constant 2; so the address of the allocated memory is lost) with this for loop
for (i = 0; i < rows; i++)
{
    resMat[i] = (int*)calloc(cols[i], sizeof(int)); // cols[i]=cols[0]=2
    assert(resMat[i]);
}   

do not make a sense.
In this statement within the for loop
resMat[i] = (int*)calloc(cols[i], sizeof(int));

there is used the pointer cols with the value 2 that is dereferenced
in the expression cols[i] that results in undefined behavior
All what you need is the following
int cols = 2;

resMat = calloc(rows, sizeof(int*));
assert(resMat);
for ( i = 0; i < rows; i++)
{
    resMat[i] = calloc( cols, sizeof( int ));
    assert(resMat[i]);
} 

Does anyone have a solution to this? Check out the before