 if they will provide a barcode. It might end up being free of charge for them to do it, or you'll have to get a special printer that prints stickers and special software that generates UPC's. If anything my recommendation in any case would be to get the business themselves to do it to save yourself the hassle. Even knocking a small fraction of the price off your product would be worth saving yourself the hassle.
First you will ask them about barcode.
bar codes, I believe, is part of an accounting process that keep track of your inventory.
Depends upon the type of product you're selling, but most products already have bar codes.
If not, there are devices that prints price tags that include bar codes.
Guess it depends on what you mean by bar code?
As Francis says, bar codes are used as inventory management BUT UPC codes are used at retail to scan a product. Check out this article here on how to create UPC codes.
For queries about s tart up funding and prospective benefits, you have to seek the advice of the experts in this field. You can also send proposals to investors who may find your business appealing and wish to invest as well.
You can do whatever you are comfortable with. I mean, You may generate it yourself and let the retailer do it for you. Generating barcode is no tough task. There are free platforms available online where you can easily generate a barcode of your choice.This home was on the market for 2 days before we went and looked at it. My client saw it and fell in love with all the potential it had. He decided to place a bid and was up against 2 other offers, all cash. He got it for 302,000 even after competing with other offers. This home was sadly vacant for a whole year and the sellers needed to sell it as they were parting ways. I am so excited for this beautiful house to be brought back to life and given a new look. Look out for this house, as it will be ready to hit the market in January or February.Home>Apps>Google Photos – the only photo backup you’ll ever need. And it’s free!
After quite few attempts at photo-related services, Google has finally nailed it with its simply-named Google Photos app. Designed to be a centralized photo service that serves all your photo backup needs, the app simply saves every photo on your smartphone to the cloud and creates a searchable database for ease of use.
In the free tier, Google lets you backup unlimited photos in high-resolution (up to 16MP) and these photos are then available to you on any device! If you are a serious photographer that needs every pixel of resolution from your DSLR, Google offers paid storage too. However, for the regular user, this app offers a simple, low-key way of saving all photos at no cost.
The real advantage to using Photos for photo backup is Google’s expertise in search and image recognition. There is no manual effort in tagging each photo that you capture – just let the app backup every photo you take (over Wi-Fi only please), and you can start searching by someone’s name, places, landmarks or even names of objects! That’s some serious stuff! Since all your photos are saved to the cloud, you can access them on your PC or another phone as well.
Over the past few months, Google has added some new features such as Shared Albums – to share a selection of photos from that trip with your friends and family, auto-created albums and auto-enhanced images, Chromecast support – to cast your photos and videos from your smartphone or PC to your big screen TVs and Labels – for when you actually want to tag some photos in a certain way.
All put together, Google Photos is the best photo backup solution on the market today because of it’s simple, no-hassles approach, it’s extensive search capabilities and because it’s free for regular users like you and me!
NovoGeek 2.010 30. December 2010 NovoGeek Comments spection. Hence the version NovoGeek 2.010 [something like web 2.0 ;)] Technically, I had an awesome experience working on jQuery + ASP.NET, which gave me a very good understanding of the web. My online and in-person contributions to Microsoft developer community fetched me Microsoft MVP award, which is a very good motivation and milestone for any.NET developer. I have used twitter to the best, learning and sharing lots of tech stuff. After my stint with jQuery for a long time, I have moved to Future Web Research Lab, SETLabs (R&D wing of Infosys), which does cutting edge research on web technologies. Our team develops patented products/platforms in the areas of Augmented Reality, Web accessibility and Social networks. I have ample freedom here, working on areas of my interest. Unlike my previous work, I'm encouraged and sponsored to attend International conferences, where I can interact with professors/researchers and present technical/research papers. I have attended BASNA 2010 this month and would be attending ICDCN 2011, Mobile India 2011 and may be more. Have to start presenting research papers in 2011. All I can see is I'm grooming to the next version of myself :) Personally, 2010 also took my non-technical passions to a peak level. Playing Chess with Viswanathan Anand, the current World Chess Champion, in a simultaneous match is a dream come true!! I've learnt the art of Yoga and practiced it so rigorously that I could perform advanced asanas with ease. Yoga & meditation brought a very positive change in me-physical fitness, concentration, philosophy and more. I read lot more books this year and started building my small sweet library. Had awesome time with great mentors, friends, well wishers and books. Can't hope for something better than this :) Having exciting plans for 2011, from upgrading my blog to specializing in certain areas & socializing more. Hope 2011 turns out to be brighter for me and you as well. Happy New Year wishes in advance and happy programmingQ: Compute $E(UV)$ only knowing $E(U \mid V)$ and $U,V$ not independent. I am trying to understand and master simple tricks with conditional expectation computations.
Consider a random variable U with $E(U)=C_1$ and $\text{Var}(U)=\sigma^2$. Let $V$ be another random variable with a linear conditional mean and constant conditional variance:
$$
E(V\mid U)=A+BU \\
\text{Var}(V\mid U)=\sigma_{V\mid U}^2
$$
Where $A,B,\sigma \text{ and } \sigma_{V\mid U}$ are constants.
I managed to find $E(V), \text{Var}(V)$ etc. But I am unable to compute the Covariance of $U$ and $V$:
When applying the definition: $Cov(U,V)=E(UV)-E(U)E(V)$ I am not able to solve $E(UV)$ or to see how to approach the solution. I realise there exist countless similar type of exercices on conditional expectations with their solutions but since $U$ and $V$ are not independent I cannot apply the usual tricks. 
PS: I try to apply $E(UV)=E(E(UV\mid V))$ but what really is an obstacle for me, is to understand how to go from $E(V\mid U)$ to $E(UV\mid U)$. Once I will understand that step I will have a better grasp on the topic.
Any idea or advice toward the solution would be much appreciated, thank you! 

A: Apply:$$\mathbb E[UV]=\mathbb E[\mathbb E(UV|U)]=\mathbb E[U\mathbb E(V|U)]$$

A: Hint:
$$E(X) = E(E(X|Y))$$
Use $X = UV$ and $Y = U$.
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