The odds against an event are 5 : 3 and the odds in favour of another independent event are 7 : 5. The probability that at least one of the two events will occur is
A. \(\frac{52}{96}\)
B. \(\frac{71}{96}\)
C. \(\frac{69}{96}\)
D. \(\frac{13}{96}\)
Answer:B
The odds against an event are 5 : 3 and the odds in favour of another independent event are 7 : 5. The probability that at least one of the two events will occur is
A. \(\frac{52}{96}\) B. \(\frac{71}{96}\) C. \(\frac{69}{96}\) D. \(\frac{13}{96}\)