E = 2πf(2-s)NphrkwΦ 13. In an alternator, frequency per revolution is equal to
A. number of poles
B. twice the number of poles
C. speed in rps
D. number of pole-pairs
Answer:A
E = 2πf(2-s)NphrkwΦ 13. In an alternator, frequency per revolution is equal to
A. number of poles B. twice the number of poles C. speed in rps D. number of pole-pairs
Explanation: For a P-pole machine, in n rev/sec, P/2n cycles/second are generated and cycles per second is referred to as frequency f of the EMF wave. Here in this question n=1