If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is:
A. T = 2π\(\sqrt{\frac{m_{i} l}{m_{g} g}}\)
B. T = 2π\(\sqrt{\frac{m_{g} l}{m_{i} g}}\)
C. T = 2π\(\frac{m_{g}}{m_{i}} \sqrt{\frac{l}{g}}\)
D. T = 2π\(\frac{m_{i}}{m_{g}} \sqrt{\frac{l}{g}}\)
Answer:A
If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is:
A. T = 2π\(\sqrt{\frac{m_{i} l}{m_{g} g}}\) B. T = 2π\(\sqrt{\frac{m_{g} l}{m_{i} g}}\) C. T = 2π\(\frac{m_{g}}{m_{i}} \sqrt{\frac{l}{g}}\) D. T = 2π\(\frac{m_{i}}{m_{g}} \sqrt{\frac{l}{g}}\)