=> CT =1/(4×RT×fo) =1/(4×5kΩ×25kHz) = 2×10-9 =2nF. 8. What is the advantage of using filter?
A. High noise immunity
B. Reduce the bandwidth of PLL
C. Provides dynamic range of frequencies
D. None of the mentioned
Answer:A
=> CT =1/(4×RT×fo) =1/(4×5kΩ×25kHz) = 2×10-9 =2nF. 8. What is the advantage of using filter?
A. High noise immunity B. Reduce the bandwidth of PLL C. Provides dynamic range of frequencies D. None of the mentioned
Explanation: The charge on the filter capacitor gives a short time memory to the PLL. So, even if the signal becomes less than the noise for a few cycles, the dc voltage on the capacitor continues to shift the frequency of VCO, till it picks up the signal again. This produces high noise immunity. 9. Which filter is used in VCO?