From the material produced by melting three smaller cubes with sides of 3, 4, and 5 cm, a big cube is generated. What is the ratio of the smaller cubes' total surface areas to the giant cube's total surface area?
A. 2 : 1
B. 3 : 2
C. 25 : 18
D. 27 : 20
Answer:C
From the material produced by melting three smaller cubes with sides of 3, 4, and 5 cm, a big cube is generated. What is the ratio of the smaller cubes' total surface areas to the giant cube's total surface area?
A. 2 : 1 B. 3 : 2 C. 25 : 18 D. 27 : 20
Explanation: 33 + 43 + 53) = 216 cm3 is the volume of the big cube.Let the big cube's edge be a.As a result, a3 = 216 a = 6 cm.6 x (32 + 42 + 52)/6 x 62 = 50 /36= 25 : 18 is the required ratio.