=> RF = √3/9.4×10-3 = 212.26Ω and R1 = 212.26Ω/10 = 21.2Ω. 4. Why a resistor is shunted across the feedback capacitor in the practical integrator?
A. To reduce operating frequency
B. To enhance low frequency gain
C. To enhance error voltage
D. To reduce error voltage
Answer:A
=> RF = √3/9.4×10-3 = 212.26Ω and R1 = 212.26Ω/10 = 21.2Ω. 4. Why a resistor is shunted across the feedback capacitor in the practical integrator?
A. To reduce operating frequency B. To enhance low frequency gain C. To enhance error voltage D. To reduce error voltage
Explanation: The input current charging the feedback capacitor produces error voltage at the output of the integrator. Therefore, to reduce error voltages a resistor (RF) is connected across the feedback capacitor. Hence, RF minimizes the variation in the output voltage. 5. Find the application in which integrator is used?