If there are 32 segments, each of size 1Kb, then the logical address should have :
A. 13 bits
B. 14 bits
C. 15 bits
D. 16 bits
Answer:A
If there are 32 segments, each of size 1Kb, then the logical address should have :
A. 13 bits B. 14 bits C. 15 bits D. 16 bits
Explanation: To specify a particular segment, 5 bits are required. To select a particular byte after selecting a page, 10 more bits are required. Hence 15 bits are required.