When divided by 6, 9, 15, and 18, the least multiple of 7 that leaves a residual of 4 is:
A. 74
B. 94
C. 184
D. 364
Answer:D
When divided by 6, 9, 15, and 18, the least multiple of 7 that leaves a residual of 4 is:
A. 74 B. 94 C. 184 D. 364
Explanation: The L.C.M. for the numbers 6, 9, 15, and 18 equals 90.Allow 90k + 4 to be the needed number, which is a multiple of 7.k = 4 is the smallest number of k for which (90k + 4) is divisible by 7.(90 x 4) + 4 Equals 364, which is the required number.