A charged particle moving with a velocity \(\vec{v}\) enters a region of uniform magnetic field \(\vec{B}\) such that the pitch of the resulting helical motion is equal to the radius of the helix. The angle between \(\vec{v}\) and \(\vec{B}\) is
A. tan-1 2π
B. sin-1 2π
C. tan-1 \(\frac{1}{2 \pi}\left(\frac{q B}{m}\right)^{2}\)
D. tan-1 2π\(2 \pi\left(\frac{q B}{m}\right)^{2}\).
Answer:A
A charged particle moving with a velocity \(\vec{v}\) enters a region of uniform magnetic field \(\vec{B}\) such that the pitch of the resulting helical motion is equal to the radius of the helix. The angle between \(\vec{v}\) and \(\vec{B}\) is
A. tan-1 2π B. sin-1 2π C. tan-1 \(\frac{1}{2 \pi}\left(\frac{q B}{m}\right)^{2}\) D. tan-1 2π\(2 \pi\left(\frac{q B}{m}\right)^{2}\).