There are two red, three green, and two blue balls in each bag. At random, two balls are selected. What are the chances that none of the balls drawn will be blue?
A. 10/21
B. 11/21
C. 2/7
D. 5/7
Answer:A
There are two red, three green, and two blue balls in each bag. At random, two balls are selected. What are the chances that none of the balls drawn will be blue?
A. 10/21 B. 11/21 C. 2/7 D. 5/7
Explanation: Total number of balls = (7 + 2 + 3 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 +....)Assume that S is the sample space.Then, n(S) = Number of ways to pull two balls from a set of seven = 7C2 = (7 x 6)/ (2 x 1),Let E stand for the event of drawing two balls, none of which are blue.n(E) is the number of different methods to draw two balls from a set of (2 + 3) balls.5C2 = (5 x 4)/ = 5C2 = (5 x 4)/ = 5C2 = (5 x (2 x 1),P(E) = n(E)/n(S) = 10/21.