In the Ellingham diagram, for the formation of carbon monoxide
A. \(\left( \frac { \triangle { S }^{ 0 } }{ \triangle T } \right) \)is negative
B. \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is positive
C. \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is negative
D. initially \(\left( \frac { \triangle T }{ \triangle { G }^{ 0 } } \right) \)is positive, after 700°C, \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is negative
Answer:C
In the Ellingham diagram, for the formation of carbon monoxide
A. \(\left( \frac { \triangle { S }^{ 0 } }{ \triangle T } \right) \)is negative B. \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is positive C. \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is negative D. initially \(\left( \frac { \triangle T }{ \triangle { G }^{ 0 } } \right) \)is positive, after 700°C, \(\left( \frac { \triangle { G }^{ 0 } }{ \triangle T } \right) \)is negative