A line perpendicular to the line 5x -y = 0 forms a triangle with the coordinate axes. If the area of the triangle is 5sq.units, then its equation is …………………..
A. x + 5y ± 5\(\sqrt{2}\) = 0
B. x – 5y ± 5\(\sqrt{2}\) = 0
C. 5x + y ± 5\(\sqrt{2}\) = 0
D. 5x – y ± 5\(\sqrt{2}\) = 0
Answer:A
A line perpendicular to the line 5x -y = 0 forms a triangle with the coordinate axes. If the area of the triangle is 5sq.units, then its equation is …………………..
A. x + 5y ± 5\(\sqrt{2}\) = 0 B. x – 5y ± 5\(\sqrt{2}\) = 0 C. 5x + y ± 5\(\sqrt{2}\) = 0 D. 5x – y ± 5\(\sqrt{2}\) = 0