How many three-digit numbers can be made using the digits 2, 3, 5, 6, 7, and 9, all of which are divisible by five and have no repeats?
A. 5
B. 10
C. 15
D. 20
Answer:D
How many three-digit numbers can be made using the digits 2, 3, 5, 6, 7, and 9, all of which are divisible by five and have no repeats?
A. 5 B. 10 C. 15 D. 20
Explanation: We must have 5 in the unit position because each required value is divisible by 5. So there's only one way to go about it.Any of the remaining 5 numbers can now occupy the tens slot (2, 3, 6, 7, 9). There are five different methods to fill the tens position.Any of the remaining four digits can now be used to fill the hundreds position. So there are four options for filling it.(1 x 5 x 4) = 20 is the required number of numbers.