#include &lt;stdio.h&gt;    int main&#40;&#41;    &#123;        short i;        for &#40;i = 1; i &gt;= 0; i++&#41;            printf&#40;&quot;%d\n&quot;, i&#41;;&nbsp;    &#125;
A. The control won’t fall into the for loop
B. Numbers will be displayed until the signed limit of short and throw a runtime error
C. Numbers will be displayed until the signed limit of short and program will successfully terminate
D. This program will get into an infinite loop and keep printing numbers with no errors
Answer:A
#include &lt;stdio.h&gt;    int main&#40;&#41;    &#123;        short i;        for &#40;i = 1; i &gt;= 0; i++&#41;            printf&#40;&quot;%d\n&quot;, i&#41;;&nbsp;    &#125;
A. The control won’t fall into the for loop B. Numbers will be displayed until the signed limit of short and throw a runtime error C. Numbers will be displayed until the signed limit of short and program will successfully terminate D. This program will get into an infinite loop and keep printing numbers with no errors