&lt;?phpfunction fun&#40;$x,$y&#41;&#123;    $x = 4;    $y = 3;    $z = $x + $y / $y + $x;    echo &quot;$z&quot;;&#125;fun&#40;3, 4&#41;; ?&gt;
A. 7
B. 9
C. 0
D. Error
Answer:A
&lt;?phpfunction fun&#40;$x,$y&#41;&#123;    $x = 4;    $y = 3;    $z = $x + $y / $y + $x;    echo &quot;$z&quot;;&#125;fun&#40;3, 4&#41;; ?&gt;
A. 7 B. 9 C. 0 D. Error
Explanation: Value 3, 4 is passed to the function but that is lost because x and y are initialised to 4 and 3 inside the function. Therefore we get the given result.