I(t) = Vs * √ (L/* sin Ωt. 4. For the circuit shown below, the capacitor is initially charged to a voltage of Vo with the upper plate positive. After the switch (shown in green) is closed, the current through the load
A. increases from zero to Vo/R
B. decreases from Vo/R to zero
C. increases from zero to Vo/C
D. decreases from Vo/C to zero
Answer:A
I(t) = Vs * √ (L/* sin Ωt. 4. For the circuit shown below, the capacitor is initially charged to a voltage of Vo with the upper plate positive. After the switch (shown in green) is closed, the current through the load
A. increases from zero to Vo/R B. decreases from Vo/R to zero C. increases from zero to Vo/C D. decreases from Vo/C to zero
Explanation: The capacitor acts as a source. At instant switch is closed the current is maximum and than discharges till zero value through the load R.