5 g of an optically active compound was dissolved in 2mL of solvent at 250C. The solution was kept in a cell of length 10 cm and observed rotation was +100 . What is the specific rotation of its enantiomer?
A. -400
B. +400
C. -100
D. +100
Answer:B
5 g of an optically active compound was dissolved in 2mL of solvent at 250C. The solution was kept in a cell of length 10 cm and observed rotation was +100 . What is the specific rotation of its enantiomer?
A. -400 B. +400 C. -100 D. +100
Explanation: [α] = α/lC = +100/(1*0.5/2) = +400.