Explanation: The diode acts as an ideal diode, since the voltage across the ON diode is divided by the open loop gain of the op-amp. As the input voltage starts increasing in the positive direction, the output of the op-amp also increases positively till the diode become forward biased. 10. How to minimize the response time and increase the operating frequency range of the op-amp?
A. Positive halfwave rectifier with two diodes
B. Positive halfwave rectifier with one diode
C. Negative halfwave rectifier with two diodes
D. Negative halfwave rectifier with one diode
Answer:A
Explanation: The diode acts as an ideal diode, since the voltage across the ON diode is divided by the open loop gain of the op-amp. As the input voltage starts increasing in the positive direction, the output of the op-amp also increases positively till the diode become forward biased. 10. How to minimize the response time and increase the operating frequency range of the op-amp?
A. Positive halfwave rectifier with two diodes B. Positive halfwave rectifier with one diode C. Negative halfwave rectifier with two diodes D. Negative halfwave rectifier with one diode
Explanation: Negative halfwave rectifier circuit with two diodes are used so that the output of the op-amp does not saturate. Thus, minimizes the response time and increases the operating frequency range. 11. Why a voltage follower stage is connected at the output of the negative small signal half wave rectifier?