Explanation: The time period of VCO is given as T=2×△t =(2×0.25×Vcc ×CT)/i =(0.5 V×cc×CT)/i = (Vcc×CT)/(2×i). 4. Determine the value of current flow in VCO, when the NE566 VCO external timing resistor RT =250Ω and the modulating input voltage Vc=3.25V.(Assume Vcc=+5v).
A. 3mA
B. 12mA
C. 7mA
D. 10mA
Answer:A
Explanation: The time period of VCO is given as T=2×△t =(2×0.25×Vcc ×CT)/i =(0.5 V×cc×CT)/i = (Vcc×CT)/(2×i). 4. Determine the value of current flow in VCO, when the NE566 VCO external timing resistor RT =250Ω and the modulating input voltage Vc=3.25V.(Assume Vcc=+5v).
A. 3mA B. 12mA C. 7mA D. 10mA
Explanation: Current flowing in VCO, i =(Vcc– Vc)/ RT = (5V-3.25V)/250 = 1.75/250