Explanation: The diode S.C’s the load in the positive half cycle. 10. For the circuit shown in the figure below, V8 is AC voltage source with peak value Vm. The waveform of the load voltage at the resistor is
A. zero in the positive half & peak value of –(Vm) negative half
B. zero in the negative half & peak value of –(Vm-V1) in the positive half
C. zero in the positive half & peak value of –(Vm+V1) negative half
D. zero in the positive half & peak value of –(Vm-V1) negative half
Answer:A
Explanation: The diode S.C’s the load in the positive half cycle. 10. For the circuit shown in the figure below, V8 is AC voltage source with peak value Vm. The waveform of the load voltage at the resistor is
A. zero in the positive half & peak value of –(Vm) negative half B. zero in the negative half & peak value of –(Vm-V1) in the positive half C. zero in the positive half & peak value of –(Vm+V1) negative half D. zero in the positive half & peak value of –(Vm-V1) negative half
Explanation: Diode is reversed biased in the positive half cycle. In the negative half cycle, apply KVL to get the value of peak voltage at the load. Sanfoundry Global Education & Learning Series – Power Electronics.