∫\(\frac { \sqrt { tanx } }{ sin2x } \) dx is ………………
A. \(\sqrt{tanx}\) + c
B. 2\(\sqrt{tanx}\) + c
C. \(\frac{1}{2}\) \(\sqrt{tanx}\) + c
D. \(\frac{1}{4}\) \(\sqrt{tanx}\) + c
Answer:A
∫\(\frac { \sqrt { tanx } }{ sin2x } \) dx is ………………
A. \(\sqrt{tanx}\) + c B. 2\(\sqrt{tanx}\) + c C. \(\frac{1}{2}\) \(\sqrt{tanx}\) + c D. \(\frac{1}{4}\) \(\sqrt{tanx}\) + c