If 100.48 = x, 100.70 = y, and xz = y2, the value of z is approximately:
A. 1.45
B. 1.88
C. 2.9
D. 3.7
Answer:C
If 100.48 = x, 100.70 = y, and xz = y2, the value of z is approximately:
A. 1.45 B. 1.88 C. 2.9 D. 3.7
Explanation: 10(0.48z) = 10(2 x 0.70) = 101.40 xz = y2,1.40 = 0.48z,z = 140/48 = 35/12 = 2.9 z = 140/48 = 35/12 = 2.9 z = 140/48 = (approx.).