The smallest number that leaves a remnant of 3 when divided by 5, 6, 7, and 8, but no remainder when divided by 9, is:
A. 1677
B. 1683
C. 2523
D. 3363
Answer:B
The smallest number that leaves a remnant of 3 when divided by 5, 6, 7, and 8, but no remainder when divided by 9, is:
A. 1677 B. 1683 C. 2523 D. 3363
Explanation: 5, 6, 7, 8 = 840 L.C.M.The number must be in the format 840k + 3.k = 2 is the smallest number of k for which (840k + 3) is divisible by 9.(840 x 2 + 3) = 1683 is the required number.