Ampere’s circuital law states that
A. the surface integral of magnetic field over the open surface is equal to μ0 times the total current passing through the surface.
B. the surface integral of magnetic field over the open surface is equal to μ0 times the total current passing near the surface.
C. the line integral of magnetic field along the boundary of the open surface is equal to μ0 times the total current passing near the surface.
D. the line integral of magnetic field along the boundary of the open surface is equal to μ0 times the total current passing through the surface.
Answer:D
Ampere’s circuital law states that
A. the surface integral of magnetic field over the open surface is equal to μ0 times the total current passing through the surface. B. the surface integral of magnetic field over the open surface is equal to μ0 times the total current passing near the surface. C. the line integral of magnetic field along the boundary of the open surface is equal to μ0 times the total current passing near the surface. D. the line integral of magnetic field along the boundary of the open surface is equal to μ0 times the total current passing through the surface.