If sin (A + 2B) = \(\frac{12}{5}\) and cos (A + 4B) = 0, A > B and A + 4B ≤ 90°, then A and B is (1)
A. 30°, 45°
B. 15°, 45°
C. 60°, 15°
D. 30°, 15°
Answer:D
If sin (A + 2B) = \(\frac{12}{5}\) and cos (A + 4B) = 0, A > B and A + 4B ≤ 90°, then A and B is (1)
A. 30°, 45° B. 15°, 45° C. 60°, 15° D. 30°, 15°