In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is:
A. \(\frac{1}{2}\)
B. 2
C. –\(\frac{1}{2}\)
D. -2
Answer:C
In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is:
A. \(\frac{1}{2}\) B. 2 C. –\(\frac{1}{2}\) D. -2