If the system of equations 2x + 3y + 5 = 0, x + ky + 5 = 0, kx – 12y – 14 = 0 has non-trivial solution, then the value of k is
A. -2, \(\frac{12}{5}\)
B. -1, \(\frac{1}{5}\)
C. -6, \(\frac{17}{5}\)
D. 6, \(-\frac{12}{5}\)
Answer:C
If the system of equations 2x + 3y + 5 = 0, x + ky + 5 = 0, kx – 12y – 14 = 0 has non-trivial solution, then the value of k is
A. -2, \(\frac{12}{5}\) B. -1, \(\frac{1}{5}\) C. -6, \(\frac{17}{5}\) D. 6, \(-\frac{12}{5}\)