If y = tan-1x,then \(\frac{d^{2} y}{d x^{2}}\) is: (1)
A. \(\frac{-2 x}{\left(1+x^{2}\right)^{2}}\)
B. \(\frac{-2 x}{1+x^{2}}\)
C. \(\frac{-1}{1+x^{2}}\)
D. \(\frac{1}{1+x^{2}}\)
Answer:A
If y = tan-1x,then \(\frac{d^{2} y}{d x^{2}}\) is: (1)
A. \(\frac{-2 x}{\left(1+x^{2}\right)^{2}}\) B. \(\frac{-2 x}{1+x^{2}}\) C. \(\frac{-1}{1+x^{2}}\) D. \(\frac{1}{1+x^{2}}\)