If the equation a(y + z) = x, b(z + = y, c(x + y) = z have non-trivial solutions then the value of \(\frac{1}{1+a}+\frac{1}{1+b}+\frac{1}{1+c}\) is
A. 1
B. 2
C. -1
D. -2
Answer:B
If the equation a(y + z) = x, b(z + = y, c(x + y) = z have non-trivial solutions then the value of \(\frac{1}{1+a}+\frac{1}{1+b}+\frac{1}{1+c}\) is
A. 1 B. 2 C. -1 D. -2