The shortest distance between the lines x = y + 2 = 6z – 6 and x + 1 = 2y = -12z is
A. \(\frac{1}{2}\)
B. 2
C. 1
D. \(\frac{3}{2}\)
Answer:B
The shortest distance between the lines x = y + 2 = 6z – 6 and x + 1 = 2y = -12z is
A. \(\frac{1}{2}\) B. 2 C. 1 D. \(\frac{3}{2}\)