\(2 \mathrm{CH}_{3}-\mathrm{CHO} \frac{\text { dil. base or acid }}{300 \mathrm{~K}} \mathrm{~A} \underset{\text { dehydration }}{\text { dehy }} \mathrm{B}+\mathrm{H}_{2} \mathrm{O}\)
A. CH3-CH(OH)-CH2-CHO
B. CH3-CH2-CH(OH)-CHO
C. CH3-CH = CH-CHO
D. CH3-CO-CH3
Answer:C
\(2 \mathrm{CH}_{3}-\mathrm{CHO} \frac{\text { dil. base or acid }}{300 \mathrm{~K}} \mathrm{~A} \underset{\text { dehydration }}{\text { dehy }} \mathrm{B}+\mathrm{H}_{2} \mathrm{O}\)
A. CH3-CH(OH)-CH2-CHO B. CH3-CH2-CH(OH)-CHO C. CH3-CH = CH-CHO D. CH3-CO-CH3