In the given figure, ABCD is a trapezium in which AB || CD such that AB = a cm and CD = b cm. If F and E are the mid points of BC and AD respectively, then ar(ABFE)/ar(EFCD) is equal to: [NCERT Exemplar Problems]
A. \(\frac{a}{b}\)
B. \(\frac{(3 a+b)}{(a+3 b)}\)
C. \(\frac{(a+3 b)}{(3 a+b)}\)
D. \(\frac{(2 a+b)}{(3 a+b)}\)
Answer:B
In the given figure, ABCD is a trapezium in which AB || CD such that AB = a cm and CD = b cm. If F and E are the mid points of BC and AD respectively, then ar(ABFE)/ar(EFCD) is equal to: [NCERT Exemplar Problems]
A. \(\frac{a}{b}\) B. \(\frac{(3 a+b)}{(a+3 b)}\) C. \(\frac{(a+3 b)}{(3 a+b)}\) D. \(\frac{(2 a+b)}{(3 a+b)}\)