The derivative of f(tan w.r.t. g(sec at x = \(\frac{\pi}{4}\), where f'(1) = 2 and g'(√2) = 4, is
A. \(\frac{1}{\sqrt{2}}\)
B. √2
C. 1
D. 0
Answer:A
The derivative of f(tan w.r.t. g(sec at x = \(\frac{\pi}{4}\), where f'(1) = 2 and g'(√2) = 4, is
A. \(\frac{1}{\sqrt{2}}\) B. √2 C. 1 D. 0