\(\frac{\tan ^{2} \theta}{\sec \theta+1}\) = sec θ is equal to
A. – 1
B. 1
C. 0
D. none of these
Answer:A
\(\frac{\tan ^{2} \theta}{\sec \theta+1}\) = sec θ is equal to
A. – 1 B. 1 C. 0 D. none of these