If Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(△AOD) = ar(△BOC). Then ABCD is a:
A. Parallelogram
B. Rectangle
C. Square
D. Trapezium
Answer:D
If Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(△AOD) = ar(△BOC). Then ABCD is a:
A. Parallelogram B. Rectangle C. Square D. Trapezium
Explanation: ar(△AOD) = ar(△BOC)