If tan-1 2x + tan-1 3x = \(\frac{\pi}{4}\), then x is
A. \(\frac{1}{6}\)
B. 1
C. (\(\frac{1}{6}\), -1)
D. none of these
Answer:A
If tan-1 2x + tan-1 3x = \(\frac{\pi}{4}\), then x is
A. \(\frac{1}{6}\) B. 1 C. (\(\frac{1}{6}\), -1) D. none of these