\(\int \frac{d x}{e^{x}+e^{x}}\) x is equal to
A. tan-1 (ex) + C
B. tan-1 (e-x) + C
C. log (ex – e-x) + C
D. log (ex + e-x) + C
Answer:A
\(\int \frac{d x}{e^{x}+e^{x}}\) x is equal to
A. tan-1 (ex) + C B. tan-1 (e-x) + C C. log (ex – e-x) + C D. log (ex + e-x) + C