When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:
A. \(\frac{1}{2}\)Mgl
B. \(\frac{1}{2}\)MgL
C. Mgl
D. MgL
Answer:A
When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:
A. \(\frac{1}{2}\)Mgl B. \(\frac{1}{2}\)MgL C. Mgl D. MgL