The angle of depression of an object on the ground, from the top of a 25 m high tower is 30°. The distance of the object from the base of tower is
A. 25√3 m
B. 50√3 m
C. 75√3 m
D. 50 m
Answer:A
The angle of depression of an object on the ground, from the top of a 25 m high tower is 30°. The distance of the object from the base of tower is
A. 25√3 m B. 50√3 m C. 75√3 m D. 50 m
Explanation: Let AB be the tower and BC be the distance of the object (at C) from the base of the tower.