Solution of LPP to minimize z = 2x + 3y subjected to x ≥ 0, y ≥ 0, 1 ≤ x + 2y ≤ 10 is
A. x = 0, y = \(\frac{1}{2}\)
B. x = \(\frac{1}{2}\), y = 0
C. x = 1, y = -2
D. x = y = \(\frac{1}{2}\)
Answer:A
Solution of LPP to minimize z = 2x + 3y subjected to x ≥ 0, y ≥ 0, 1 ≤ x + 2y ≤ 10 is
A. x = 0, y = \(\frac{1}{2}\) B. x = \(\frac{1}{2}\), y = 0 C. x = 1, y = -2 D. x = y = \(\frac{1}{2}\)