The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probablity of 2 successes is
A. \(\frac{128}{256}\)
B. \(\frac{219}{256}\)
C. \(\frac{37}{256}\)
D. \(\frac{28}{256}\)
Answer:D
The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probablity of 2 successes is
A. \(\frac{128}{256}\) B. \(\frac{219}{256}\) C. \(\frac{37}{256}\) D. \(\frac{28}{256}\)