If f(= (ax2 – b)3, then the function g such that f{g(x)} = g{f(x)} is given by
A. \(g(x)=\left(\frac{b-x^{1 / 3}}{a}\right)^{1 / 2}\)
B. \(g(x)=\frac{1}{\left(a x^{2}+b\right)^{3}}\)
C. \(g(x)=\left(a x^{2}+b\right)^{1 / 3}\)
D. \(g(x)=\left(\frac{x^{1 / 3}+b}{a}\right)^{1 / 2}\)
Answer:D
If f(= (ax2 – b)3, then the function g such that f{g(x)} = g{f(x)} is given by
A. \(g(x)=\left(\frac{b-x^{1 / 3}}{a}\right)^{1 / 2}\) B. \(g(x)=\frac{1}{\left(a x^{2}+b\right)^{3}}\) C. \(g(x)=\left(a x^{2}+b\right)^{1 / 3}\) D. \(g(x)=\left(\frac{x^{1 / 3}+b}{a}\right)^{1 / 2}\)