In a beryllium atom, if a0 be the radius of the first orbit, then the radius of the second orbit will be:
A. na0
B. a0
C. n2a0
D. \(\frac{a_{0}}{n^{2}}\)
Answer:C
In a beryllium atom, if a0 be the radius of the first orbit, then the radius of the second orbit will be:
A. na0 B. a0 C. n2a0 D. \(\frac{a_{0}}{n^{2}}\)