If a and P are current gains in common- base and common-emitter configuration of a transistor, then p is equal to:
A. \(\frac{1}{\alpha}\)
B. \(\frac{\alpha}{1+\alpha}\)
C. \(\frac{\alpha}{1-\alpha}\)
D. α – \(\frac{1}{\alpha}\)
Answer:C
If a and P are current gains in common- base and common-emitter configuration of a transistor, then p is equal to:
A. \(\frac{1}{\alpha}\) B. \(\frac{\alpha}{1+\alpha}\) C. \(\frac{\alpha}{1-\alpha}\) D. α – \(\frac{1}{\alpha}\)