The fact that (232 + 1) is totally divisible by a whole number is assumed. This number is totally divisible by which of the following numbers
A. (2 TO HE POWER 16+ 1)
B. (2 TO THE POWER 16 - 1)
C. (7 x 22 TO THE POWER 3 )
D. (2 TO THE POWER 96 + 1)
Answer:D
The fact that (232 + 1) is totally divisible by a whole number is assumed. This number is totally divisible by which of the following numbers
A. (2 TO HE POWER 16+ 1) B. (2 TO THE POWER 16 - 1) C. (7 x 22 TO THE POWER 3 ) D. (2 TO THE POWER 96 + 1)
Explanation: Let x = 2TO THE POWER 32. Then (x + 1) = (2 TO THE POWER 32 + 1)..Allow the natural number N to be totally divisible by (x + 1). Then,(2 TO THE POWER 96 + 1) = [(2TO THE POWER 32)CUBE+ 1] = (xCUBE + 1) = (x + 1)(x SQUARE - x + 1), which is divisible by N.