If n is a natural number, (6n2 + 6n) must be divisible by:
A. 6 only
B. 6 and 12 both
C. 12 only
D. by 18 only
Answer:B
If n is a natural number, (6n2 + 6n) must be divisible by:
A. 6 only B. 6 and 12 both C. 12 only D. by 18 only
Explanation: Because n(n + 1) is always even, (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12.