A shoots 5 shots versus B's 3, but A only kills once every three shots, whilst B kills once every two shots. A has killed when B has missed 27 times:
A. 30 birds
B. 60 birds
C. 72 birds
D. 90 birds
Answer:A
A shoots 5 shots versus B's 3, but A only kills once every three shots, whilst B kills once every two shots. A has killed when B has missed 27 times:
A. 30 birds B. 60 birds C. 72 birds D. 90 birds
Explanation: Let's say there are x total shots. Then,A fires 5/8 x 8 shots, whereas B fires 3/8 x 8 shots. A = 1/3 of 5/8 x = 5/24 x Killing shots,B's missed shots = 1/2 of 3/8 x = 3/16 x,x = 27 x 16/3 = 144, or x = 27 x 16/3 = 144.A =5x/24=5/24 x 144 = 30 birds killed.