How many NOT gates are required to implement the Boolean expression: X = AB’C + A’BC?
A. 2
B. 3
C. 4
D. 5
Answer:A
How many NOT gates are required to implement the Boolean expression: X = AB’C + A’BC?
A. 2 B. 3 C. 4 D. 5
Explanation: Since in the given expression two inputs are complemented. So, we require two NOT gate at the input. A NOT gate is a basic gate which accepts a single input and produces a single output, which is the inverted version of the input.