If 6 men and 8 boys can complete a task in 10 days while 26 men and 48 boys can complete the same in 2 days, 15 men and 20 boys will complete the task in the following time:
A. 4 days
B. 5 days
C. 6 days
D. 7 days
Answer:A
If 6 men and 8 boys can complete a task in 10 days while 26 men and 48 boys can complete the same in 2 days, 15 men and 20 boys will complete the task in the following time:
A. 4 days B. 5 days C. 6 days D. 7 days
Explanation: Let one day's labour for one man be x and one day's work for one boy be y.6x + 8y = 1/10, and 26x + 48y = 1/2, respectively.We obtain x = 1/100 and y = 1/200 when we solve these two equations.1 day's work (15 men + 20 boys) = 15/100 + 20/200 = 1/4.The task may be completed in four days by 15 men and 20 boys.