If Sn=4Sn-1+12n, where S0=6 and S1=7, find the solution for the recurrence relation.
A. an=7(2n)−29/6n6n
B. an=6(6n)+6/7n6n
C. an=6(3n+1)−5n
D. an=nn−2/6n6n
Answer:B
If Sn=4Sn-1+12n, where S0=6 and S1=7, find the solution for the recurrence relation.
A. an=7(2n)−29/6n6n
 B. an=6(6n)+6/7n6n
 C. an=6(3n+1)−5n
 D. an=nn−2/6n6n
