Ques. A woman with two genes for haemophilia and one gene for colour blindness on one of the ‘X’ chromosomes marries a normal man. How will the progeny be?
A. 50% haemophilic colour-blind sons and 50% normal sons.
B. 50% haemophilic daughters (carrier) and 50% colour blind daughters (carrier).
C. All sons and daughters haemophilic and colourblind.
D. Haemophilic and colour-blind daughters.
Answer:B
Ques. A woman with two genes for haemophilia and one gene for colour blindness on one of the ‘X’ chromosomes marries a normal man. How will the progeny be?
A. 50% haemophilic colour-blind sons and 50% normal sons. B. 50% haemophilic daughters (carrier) and 50% colour blind daughters (carrier). C. All sons and daughters haemophilic and colourblind. D. Haemophilic and colour-blind daughters.