∫ \(\frac { secx }{ \sqrt { cos2x } } \) dx = …………………..
A. tan-1(sin x) + c
B. 2 sin-1(tan x) + c
C. tan-1(cos x) + c
D. sin-1 (tan x) + c
Answer:D
∫ \(\frac { secx }{ \sqrt { cos2x } } \) dx = …………………..
A. tan-1(sin x) + c B. 2 sin-1(tan x) + c C. tan-1(cos x) + c D. sin-1 (tan x) + c