Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Then, the probability that there is atleast one defective egg is
A. \(1-\frac{7^{10}}{10^{10}}\)
B. \(1+\frac{7^{10}}{10^{10}}\)
C. \(1+\frac{9^{10}}{10^{10}}\)
D. \(1-\frac{9^{10}}{10^{10}}\)
Answer:D
Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Then, the probability that there is atleast one defective egg is
A. \(1-\frac{7^{10}}{10^{10}}\) B. \(1+\frac{7^{10}}{10^{10}}\) C. \(1+\frac{9^{10}}{10^{10}}\) D. \(1-\frac{9^{10}}{10^{10}}\)