If X(z) =(z+z-3)/(z+z-1), then x(n) series has:
A. Alternate 0s
B. Alternate 1s
C. Alternate 2s
D. Alternate -1s
Answer:A
If X(z) =(z+z-3)/(z+z-1), then x(n) series has:
A. Alternate 0s B. Alternate 1s C. Alternate 2s D. Alternate -1s
Explanation: Using the long division method divide from denominator. So, x(n) series has alternate zeros n =1,3,5……