The solution of the differential equation \(\frac{d y}{d x}=\frac{1+y^{2}}{1+x^{2}}\) is
A. y = tan-1 x
B. y – x = k(1 + xy)
C. x = tan-1 y
D. tan(xy) = k
Answer:B
The solution of the differential equation \(\frac{d y}{d x}=\frac{1+y^{2}}{1+x^{2}}\) is
A. y = tan-1 x B. y – x = k(1 + xy) C. x = tan-1 y D. tan(xy) = k