The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X such that the acceleration of the planet X is n times greater than the Earth is
A. 0.9n
B. 0.9/n m
C. 0.9n2m
D. 0.9/n2
Answer:A
The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X such that the acceleration of the planet X is n times greater than the Earth is
A. 0.9n B. 0.9/n m C. 0.9n2m D. 0.9/n2