A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is –
A. \(\frac{L}{4}\)
B. \(\frac{L}{2}\)
C. L
D. 2L
Answer:A
A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is –
A. \(\frac{L}{4}\) B. \(\frac{L}{2}\) C. L D. 2L