How does compiler convert “::operator new” implicitly?
A. ::operator new( sizeof( type ) )
B. ::operator new( sizeof( ) )
C. new operator :: type sizeof( type )
D. new sizeof( type ) operator
Answer:A
How does compiler convert “::operator new” implicitly?
A. ::operator new( sizeof( type ) ) B. ::operator new( sizeof( ) ) C. new operator :: type sizeof( type ) D. new sizeof( type ) operator