#include&lt;stdio.h&gt;   #include&lt;stdlib.h&gt;   #include&lt;fcntl.h&gt;&nbsp;   int main&#40;&#41;   &#123;       int fd, new_fd;       char *buff;       buff = &#40;char *&#41;malloc&#40;sizeof&#40;char&#41;*8&#41;;       fd = open&#40;&quot;san.c&quot;,O_RDONLY&#41;;       new_fd = dup&#40;fd&#41;;       close&#40;fd&#41;;       read&#40;new_fd,buff,8&#41;;       printf&#40;&quot;%s\n&quot;,buff&#41;;   &#125;
A. this program will not print anything
B. this program will print “#include”
C. this program will give the segmentation fault
D. this program will give the syntax error
Answer:A
#include&lt;stdio.h&gt;   #include&lt;stdlib.h&gt;   #include&lt;fcntl.h&gt;&nbsp;   int main&#40;&#41;   &#123;       int fd, new_fd;       char *buff;       buff = &#40;char *&#41;malloc&#40;sizeof&#40;char&#41;*8&#41;;       fd = open&#40;&quot;san.c&quot;,O_RDONLY&#41;;       new_fd = dup&#40;fd&#41;;       close&#40;fd&#41;;       read&#40;new_fd,buff,8&#41;;       printf&#40;&quot;%s\n&quot;,buff&#41;;   &#125;
A. this program will not print anything B. this program will print “#include” C. this program will give the segmentation fault D. this program will give the syntax error
Explanation:The “dup” system creates the a copy of the file descriptor.