Explanation: The output of the frequency doubler contains a dc term and wave of double frequency. The dc term can be easily removed by using a 1µF coupling capacitor between load and output terminal of the doubler circuit. 5. Find the voltage range at which the multiplier can be used as a squarer circuit?
A. 0 – Vin
B. Vref – Vin
C. 0 – Vref
D. All of the mentioned
Answer:A
Explanation: The output of the frequency doubler contains a dc term and wave of double frequency. The dc term can be easily removed by using a 1µF coupling capacitor between load and output terminal of the doubler circuit. 5. Find the voltage range at which the multiplier can be used as a squarer circuit?
A. 0 – Vin B. Vref – Vin C. 0 – Vref D. All of the mentioned
Explanation: The basic multiplier can be used to square any positive or negative number provided the number can be represented by a voltage between 0 to Vref. 6. Calculate the output voltage of a squarer circuit, if it input voltage is 3.5v. Assume Vref = 9.67v.