Explanation: Break frequency of the op-amp is given as fo = 1/(2πRoC)= 1/ (2π×10kΩ×0.1µF) = 1/ (6.28×10-3) = 159.2Hz. 3. The open loop voltage gain as a function of frequency is defined as
A. AOL(f) = VO/Vin
B. AOL(f) = VO/Vid
C. AOL(f) = VO/Vf
D. All of the above mentioned
Answer:A
Explanation: Break frequency of the op-amp is given as fo = 1/(2πRoC)= 1/ (2π×10kΩ×0.1µF) = 1/ (6.28×10-3) = 159.2Hz. 3. The open loop voltage gain as a function of frequency is defined as
A. AOL(f) = VO/Vin B. AOL(f) = VO/Vid C. AOL(f) = VO/Vf D. All of the above mentioned
Explanation: The open loop voltage gain as a function of frequency is defined as ratio of output voltage to the difference of input voltages. 4. Which among the following factor remain fixed for an op-amp?