A ≅ 102.92dB; fo1 =6Hz ; fo2 =2.34MHz .
A. 140000/[1+ j(f/6)]x[1+ j(f/2.34)]
B. 140000/[1+ j(f/6)]x[1+ j(f/234)]
C. 140000/[1+ j(f/6)]x[1+ j(f/23400)]
D. 140000/[1+ j(f/6)]x[1+ j(f/2340000)]
Answer:A
A ≅ 102.92dB; fo1 =6Hz ; fo2 =2.34MHz .
A. 140000/[1+ j(f/6)]x[1+ j(f/2.34)] B. 140000/[1+ j(f/6)]x[1+ j(f/234)] C. 140000/[1+ j(f/6)]x[1+ j(f/23400)] D. 140000/[1+ j(f/6)]x[1+ j(f/2340000)]
Explanation: Gain of op-amp at 0Hz, A = 10102.92/20