For the circuit shown in the figure below, Vs is the ac voltage source with peak value Vm. The waveform of the load voltage at the resistor will have
A. zero value in the positive half cycle and a peak value of –(Vm) in the negative half cycle
B. zero value in the negative half cycle and a peak value of –(Vm-V1) in the positive half cycle
C. zero value in the positive half cycle and a peak value of –(Vm+V1) in the negative half cycle
D. zero value in the positive half cycle and a peak value of –(Vm-V1) in the negative half
Answer:A
For the circuit shown in the figure below, Vs is the ac voltage source with peak value Vm. The waveform of the load voltage at the resistor will have
A. zero value in the positive half cycle and a peak value of –(Vm) in the negative half cycle B. zero value in the negative half cycle and a peak value of –(Vm-V1) in the positive half cycle C. zero value in the positive half cycle and a peak value of –(Vm+V1) in the negative half cycle D. zero value in the positive half cycle and a peak value of –(Vm-V1) in the negative half
Explanation: Diode is reversed biased in the positive half cycle. In the negative half cycle, apply KVL to get the value of peak voltage at the load. 3. For the circuit shown below,