A radioactive nucleus (initial mass number A and atomic number Z) emits 2α and 2 positrons. The ratio of number of neutrons to that of proton in the final nucleus will be
A. \(\frac { A-Z-4 }{ Z-2 }\)
B. \(\frac { A-Z-2 }{ Z 6 }\)
C. \(\frac { A-Z-4 }{ Z-6 }\)
D. \(\frac { A-Z-12 }{ Z-4 }\)
Answer:B
A radioactive nucleus (initial mass number A and atomic number Z) emits 2α and 2 positrons. The ratio of number of neutrons to that of proton in the final nucleus will be
A. \(\frac { A-Z-4 }{ Z-2 }\) B. \(\frac { A-Z-2 }{ Z 6 }\) C. \(\frac { A-Z-4 }{ Z-6 }\) D. \(\frac { A-Z-12 }{ Z-4 }\)