The voltage across the capacitor will be a triangular wave form. 5. What will be the frequency of output waveform of a square wave generator if R2 = 1.16 R1?
A. fo = (1/2RC)
B. fo = (ln/2RC)
C. fo = (ln /2 ×√RC)
D. fo = (ln/√(2 RC))
Answer:A
The voltage across the capacitor will be a triangular wave form. 5. What will be the frequency of output waveform of a square wave generator if R2 = 1.16 R1?
A. fo = (1/2RC) B. fo = (ln/2RC) C. fo = (ln /2 ×√RC) D. fo = (ln/√(2 RC))
Explanation: When R2= 1.16 R1, then fo = 1/2RC× ln[ (2R1+ R2) / R2] = 1/2RC ×ln [(2R1 + 1.161R1 )/ (1.161R1)] = 1/( 2RC×ln2.700)= 1/2RC. 6. What could be the possible output waveform for a free running multivibrator whose op-amp has a supply voltage of ±5v operating at 5khz?