The scalar product \(\overrightarrow{\mathrm{A}}\). \(\overrightarrow{\mathrm{B}}\) is equal to-
A. \(\overrightarrow{\mathrm{A}}\) + \(\overrightarrow{\mathrm{B}}\)
B. AB sin θ
C. AB cos θ
D. \(\overrightarrow{\mathrm{A}}\) + \(\overrightarrow{\mathrm{B}}\)
Answer:C
The scalar product \(\overrightarrow{\mathrm{A}}\). \(\overrightarrow{\mathrm{B}}\) is equal to-
A. \(\overrightarrow{\mathrm{A}}\) + \(\overrightarrow{\mathrm{B}}\) B. AB sin θ C. AB cos θ D. \(\overrightarrow{\mathrm{A}}\) + \(\overrightarrow{\mathrm{B}}\)