#include &lt;stdio.h&gt;#define foo(m, n) m * n = 10int main&#40;&#41;&#123;    printf&#40;&quot;in main\n&quot;&#41;;&#125;
A. In main
B. Compilation error as lvalue is required for the expression m*n=10
C. Preprocessor error as lvalue is required for the expression m*n=10
D. None of the mentioned
Answer:A
#include &lt;stdio.h&gt;#define foo(m, n) m * n = 10int main&#40;&#41;&#123;    printf&#40;&quot;in main\n&quot;&#41;;&#125;
A. In main B. Compilation error as lvalue is required for the expression m*n=10 C. Preprocessor error as lvalue is required for the expression m*n=10 D. None of the mentioned
Explanation:Preprocessor just replaces whatever is given compiler then checks for error at the replaced part of the code. Here it is not replaced anywhere.