Then AOL(f) dB= 20log(200000-20log[√1+(0/5)2)] = 106dB. Where A =20,000 ≅ 106dB. 11. What happen when the frequency increases?
A. AOL(f) continues to drop
B. A increases
C. fo –> 0Hz
D. None of the mentioned
Answer:A
Then AOL(f) dB= 20log(200000-20log[√1+(0/5)2)] = 106dB. Where A =20,000 ≅ 106dB. 11. What happen when the frequency increases?
A. AOL(f) continues to drop B. A increases C. fo –> 0Hz D. None of the mentioned
Explanation: The open loop voltage gain as a function of frequency is given as AOL(f) = A/ [√ 1+ (f/fo)] at frequency above fo, the denominator value increases, causing the gain, AOL(f) to decrease. Thus, as frequency increases, the gain AOL(f) continuous to drop. 12. What will be the absolute value of phase shift, if the frequency keeps increasing?