Find the convolution of x(t) = exp(2t)u(-t), and h(t) = u(t-3)
A. 0.5exp(2t-6)u(-t+3) + 0.5u(t-3)
B. 0.5exp(2t-3)u(-t+3) + 0.8u(t-3)
C. 0.5exp(2t-6)u(-t+3) + 0.5u(t-6)
D. 0.5exp(2t-6)u(-t+3) + 0.8u(t-3)
Answer:A
Find the convolution of x(t) = exp(2t)u(-t), and h(t) = u(t-3)
A. 0.5exp(2t-6)u(-t+3) + 0.5u(t-3) B. 0.5exp(2t-3)u(-t+3) + 0.8u(t-3) C. 0.5exp(2t-6)u(-t+3) + 0.5u(t-6) D. 0.5exp(2t-6)u(-t+3) + 0.8u(t-3)
Explanation: Divide it into 2 sectors and apply the convolution formula.