Explanation: We know, Te= 1/8 Im2(Ld-Lq)sin2δ+1/2 IfImMmaxsinδ, rotor is not excited implies If=0, and thus Te= 1/8 Im2(Ld-Lq)sin2δ = Asin2δ 13. The self and mutual inductances of a doubly excited magnetic system are Ls=0.6+0.20cos2θr H and Lr=0.75+0.30cos2θr H and Msr=0.8cosθr H. For a stationary rotor at an angular position of θr=60°,what is the magnitude of torque when the currents is=20A DC and ir=10A DC?
A. -233.88N-m
B. +233.88N-m
C. -467.76N-m
D. +467.76N-m
Answer:A
Explanation: We know, Te= 1/8 Im2(Ld-Lq)sin2δ+1/2 IfImMmaxsinδ, rotor is not excited implies If=0, and thus Te= 1/8 Im2(Ld-Lq)sin2δ = Asin2δ 13. The self and mutual inductances of a doubly excited magnetic system are Ls=0.6+0.20cos2θr H and Lr=0.75+0.30cos2θr H and Msr=0.8cosθr H. For a stationary rotor at an angular position of θr=60°,what is the magnitude of torque when the currents is=20A DC and ir=10A DC?
A. -233.88N-m B. +233.88N-m C. -467.76N-m D. +467.76N-m
Explanation: For θr=60°; Ls, Lr, Msr and their derivatives with respect to θr have the following values: