Zn|ZnSO4(0.01M)||CuSO4(1.0 M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the following, which one is the relationship between E1 and E2? (Given, RT/F = 0.059)
A. E1 < E2
B. E1 > E2
C. E1 = E2 E1
D. E1 = E2
Answer:B
Zn|ZnSO4(0.01M)||CuSO4(1.0 M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the following, which one is the relationship between E1 and E2? (Given, RT/F = 0.059)
A. E1 < E2 B. E1 > E2 C. E1 = E2 E1 D. E1 = E2