How does refractive index (μ) of a material vary with respect to wavelength (λ). (A and B are constants).
A. μ = A + \(\frac { B }{ { \lambda }^{ 2 } } \)
B. μ = A + Bλ2
C. μ = A + \(\frac { B }{ λ }\)
D. μ = A + Bλ
Answer:A
How does refractive index (μ) of a material vary with respect to wavelength (λ). (A and B are constants).
A. μ = A + \(\frac { B }{ { \lambda }^{ 2 } } \) B. μ = A + Bλ2 C. μ = A + \(\frac { B }{ λ }\) D. μ = A + Bλ