Using Gibb’s free energy change, ∆G0 = 57.34 KJ mol-1, for the reaction, X2Y(g) \(\rightleftharpoons\) 2X+ + Y2-(aq), calculate the solubility product of X2Y in water at 300K (R = 8.3 J K-1 Mol-1) ……………….
A. 10-10
B. 10-12
C. 10-14
D. can not be calculated from the given data
Answer:A
Using Gibb’s free energy change, ∆G0 = 57.34 KJ mol-1, for the reaction, X2Y(g) \(\rightleftharpoons\) 2X+ + Y2-(aq), calculate the solubility product of X2Y in water at 300K (R = 8.3 J K-1 Mol-1) ……………….
A. 10-10 B. 10-12 C. 10-14 D. can not be calculated from the given data