A simple pendulum has a time period T1. When its point of suspension is moved vertically upwards according as y = k t2, where y is vertical distance covered and k = 1 ms−2, its time period becomes T2. Then T12/T22 is (g=10ms-2)
A. 5/6
B. 11/10
C. 6/5
D. 5/6
Answer:C
A simple pendulum has a time period T1. When its point of suspension is moved vertically upwards according as y = k t2, where y is vertical distance covered and k = 1 ms−2, its time period becomes T2. Then T12/T22 is (g=10ms-2)
A. 5/6 B. 11/10 C. 6/5 D. 5/6