Two items are chosen from a lot containing twelve items of which four are defective. Then the probability that atleast one of the item is defective is …………………..
A. \(\frac{19}{33}\)
B. \(\frac{17}{33}\)
C. \(\frac{23}{33}\)
D. \(\frac{13}{34}\)
Answer:A
Two items are chosen from a lot containing twelve items of which four are defective. Then the probability that atleast one of the item is defective is …………………..
A. \(\frac{19}{33}\) B. \(\frac{17}{33}\) C. \(\frac{23}{33}\) D. \(\frac{13}{34}\)