= 20log(1/150µV/=20log(106/150) =20log(6666.67)= 76.48dB. 4. When does the op-amp perform better?
A. Low value of SVRR in µV/V
B. High value if SVRR in µV/V
C. Low value of SVRR in dB
D. High value of SVRR in dB
Answer:A
= 20log(1/150µV/=20log(106/150) =20log(6666.67)= 76.48dB. 4. When does the op-amp perform better?
A. Low value of SVRR in µV/V B. High value if SVRR in µV/V C. Low value of SVRR in dB D. High value of SVRR in dB
Explanation: The total value of SVRR in µV/V should be zero. The lower the value of SVRR in µV/V, the better will be the op-amp performance. 5. Write the equation for change in the output offset voltage?