Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (Ib > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then,
A. LB > LA
B. LA > LB
C. LA = \(\frac{L_{B}}{2}\)
D. LA = 2LB
Answer:A
Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (Ib > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then,
A. LB > LA B. LA > LB C. LA = \(\frac{L_{B}}{2}\) D. LA = 2LB