Explanation: In the negative half, only D2 is active. Hence use KVL, Vo = 6 + 0.7 Volts. 7. Consider the diode to be an ideal one and Vo = Vr + Vdc during positive half cycle. Thus, during the negative half cycle
A. Vo = Vr
B. Vo = 0
C. Vo = Vdc+Vr
D. Vo = Vdc
Answer:A
Explanation: In the negative half, only D2 is active. Hence use KVL, Vo = 6 + 0.7 Volts. 7. Consider the diode to be an ideal one and Vo = Vr + Vdc during positive half cycle. Thus, during the negative half cycle
A. Vo = Vr B. Vo = 0 C. Vo = Vdc+Vr D. Vo = Vdc
Explanation: During the negative half diode is not conducting hence Vr (voltage across the resistor) = 0. Vo = Vdc. 8. When a diode is connected in series with an AC source & R load, the conduction time per cycle is