VO = AOL(f) × (Vin1-Vin2) = 142 dB×(6.25-3.7) = 142×2.55 = 0.36v. 7. Express the open loop gain of the op-amp in complex form?
A. A/√ [1+(f/fo)2
B. 20log{A/√[1+(f/fo)2}
C. A/[1+j(f/fo)]
D. None of the mentioned
Answer:A
VO = AOL(f) × (Vin1-Vin2) = 142 dB×(6.25-3.7) = 142×2.55 = 0.36v. 7. Express the open loop gain of the op-amp in complex form?
A. A/√ [1+(f/fo)2 B. 20log{A/√[1+(f/fo)2} C. A/[1+j(f/fo)] D. None of the mentioned
Explanation: The open loop gain of the op-amp AOL(f) is a complex quantity and is expressed as AOL(f) = A/[1+ j(f/fo)] . The remaining equations are expressed in polar form. 8. Determine the difference between two AOL(f) at 50Hz and 500Hz frequency? (Consider the op-amp to be 741c)