The scalar product \(\overrightarrow{\mathrm{A}}\).\(\overrightarrow{\mathrm{B}}\)is equal to-
A. \(\overrightarrow{\mathrm{A}}\) +\(\overrightarrow{\mathrm{B}}\)
B. \(\overrightarrow{\mathrm{A}}\). \(\overrightarrow{\mathrm{B}}\)
C. AB sin θ
D. (\(\overrightarrow{\mathrm{A}}\) x \(\overrightarrow{\mathrm{B}}\)
Answer:B
The scalar product \(\overrightarrow{\mathrm{A}}\).\(\overrightarrow{\mathrm{B}}\)is equal to-
A. \(\overrightarrow{\mathrm{A}}\) +\(\overrightarrow{\mathrm{B}}\) B. \(\overrightarrow{\mathrm{A}}\). \(\overrightarrow{\mathrm{B}}\) C. AB sin θ D. (\(\overrightarrow{\mathrm{A}}\) x \(\overrightarrow{\mathrm{B}}\)