#!/bin/sh   echo &quot;Just call the function&quot;   san_function   san_function&#40;&#41; &#123;      echo &quot;This is a function&quot;   &#125;   exit 0
A. only first string will print without any error
B. only second string will print without any error
C. both strings will print
D. none of the mentioned
Answer:A
#!/bin/sh   echo &quot;Just call the function&quot;   san_function   san_function&#40;&#41; &#123;      echo &quot;This is a function&quot;   &#125;   exit 0
A. only first string will print without any error B. only second string will print without any error C. both strings will print D. none of the mentioned
Explanation:Function must be defined prior to call. Hence only first string will print and program will generate an error also.