A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is
A. \(\frac{3}{28}\)
B. \(\frac{2}{21}\)
C. \(\frac{1}{28}\)
D. \(\frac{167}{168}\)
Answer:A
A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is
A. \(\frac{3}{28}\) B. \(\frac{2}{21}\) C. \(\frac{1}{28}\) D. \(\frac{167}{168}\)