Therefore the higher current should be given a small compensating capacitor is used internally or outside an op-amp. 2. Find the expression for full power response.
A. fmax(Hz) =(slew rate×106)/(6.28×Vm)
B. fmax(Hz) =slew rate /(628×106×Vm)
C. fmax(Hz) =(slew rate×Vm×106)/6.28
D. fmax(Hz) =(6.28×Vm× 106)/ slew rate
Answer:A
Therefore the higher current should be given a small compensating capacitor is used internally or outside an op-amp. 2. Find the expression for full power response.
A. fmax(Hz) =(slew rate×106)/(6.28×Vm) B. fmax(Hz) =slew rate /(628×106×Vm) C. fmax(Hz) =(slew rate×Vm×106)/6.28 D. fmax(Hz) =(6.28×Vm× 106)/ slew rate
Explanation: The maximum input frequency at which an undistorted output voltage can be obtained for a peak value of Vm is given as fmax(Hz) =(slew rate×106)/(6.28×Vm)