If A and B are any two events then the probability that exactly one of them occur is
A. P(A ∪\(\bar { B }\)) + P(\(\bar { A }\) ∪B)
B. P(A ∩\(\bar { B }\)) + P(\(\bar { A }\) ∩B)
C. P(A) + P(B) – P(A ∩ B)
D. P(A) + P(B) + 2P(A ∩ B)
Answer:A
If A and B are any two events then the probability that exactly one of them occur is
A. P(A ∪\(\bar { B }\)) + P(\(\bar { A }\) ∪B) B. P(A ∩\(\bar { B }\)) + P(\(\bar { A }\) ∩B) C. P(A) + P(B) – P(A ∩ B) D. P(A) + P(B) + 2P(A ∩ B)