Moment of inertia of a thin uniform ring about an axis passing through the center of gravity and perpendicular to the plane is –
A. MR2
B. 2 MR2
C. \(\frac { 1 }{ 2 }\)MR2
D. \(\frac { 3 }{ 2 }\)MR2
Answer:A
Moment of inertia of a thin uniform ring about an axis passing through the center of gravity and perpendicular to the plane is –
A. MR2 B. 2 MR2 C. \(\frac { 1 }{ 2 }\)MR2 D. \(\frac { 3 }{ 2 }\)MR2