If A and B are the sides of triangle, then area of triangle –
A. \(\frac{1}{2}|\overrightarrow{\mathrm{A}} \cdot \overrightarrow{\mathrm{B}}|\)
B. \(\frac{1}{2}|\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{B}}|\)
C. AB sin θ
D. AB cos θ
Answer:B
If A and B are the sides of triangle, then area of triangle –
A. \(\frac{1}{2}|\overrightarrow{\mathrm{A}} \cdot \overrightarrow{\mathrm{B}}|\) B. \(\frac{1}{2}|\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{B}}|\) C. AB sin θ D. AB cos θ