#include &lt;iostream&gt;    #include &lt;iterator&gt;    #include &lt;list&gt;    using namespace std;    int main &#40;&#41;     &#123;        list&lt;int&gt; firstlist, secondlist;        for &#40;int i = 1; i &lt;= 2; i++&#41;        &#123;              firstlist.push_back&#40;i&#41;;             secondlist.push_back&#40;i * 10&#41;; 	&#125;        list&lt;int&gt; :: iterator it;        it = firstlist.begin&#40;&#41;;         advance &#40;it, 3&#41;;        copy &#40;secondlist.begin&#40;&#41;, secondlist.end&#40;&#41;, inserter&#40;firstlist, it&#41;&#41;;        for &#40; it = firstlist.begin&#40;&#41;; it != firstlist.end&#40;&#41;; ++it &#41;            cout &lt;&lt; *it &lt;&lt; &quot; &quot;;        return 0;    &#125;
A. 10 20 1 2
B. 10 20
C. 1 2
D. 1 10
Answer:A
#include &lt;iostream&gt;    #include &lt;iterator&gt;    #include &lt;list&gt;    using namespace std;    int main &#40;&#41;     &#123;        list&lt;int&gt; firstlist, secondlist;        for &#40;int i = 1; i &lt;= 2; i++&#41;        &#123;              firstlist.push_back&#40;i&#41;;             secondlist.push_back&#40;i * 10&#41;; 	&#125;        list&lt;int&gt; :: iterator it;        it = firstlist.begin&#40;&#41;;         advance &#40;it, 3&#41;;        copy &#40;secondlist.begin&#40;&#41;, secondlist.end&#40;&#41;, inserter&#40;firstlist, it&#41;&#41;;        for &#40; it = firstlist.begin&#40;&#41;; it != firstlist.end&#40;&#41;; ++it &#41;            cout &lt;&lt; *it &lt;&lt; &quot; &quot;;        return 0;    &#125;
A. 10 20 1 2 B. 10 20 C. 1 2 D. 1 10
Explanation:In this iterator, We are copying the first list into second and printing it.