The clearance volumetric efficiency is equal to
A. 1 + C + C(p2/p1)^(1/n)
B. 1 – C – C(p2/p1)^(1/n)
C. 1 – C + C(p2/p1)^(1/n)
D. 1 + C – C(p2/p1)^(1/n)
Answer:D
The clearance volumetric efficiency is equal to
A. 1 + C + C(p2/p1)^(1/n) B. 1 – C – C(p2/p1)^(1/n) C. 1 – C + C(p2/p1)^(1/n) D. 1 + C – C(p2/p1)^(1/n)