=> f=-tanΦ/4πRC =-tan(62o)/(4π×3.3kΩ×4.7µF)= -1.88/0.1948 =-9.65Hz. 11. Determine the angle for given circuit diagram, if the frequency of input signal is 1khz
A. -45o
B. -180o
C. -270o
D. -90o
Answer:A
=> f=-tanΦ/4πRC =-tan(62o)/(4π×3.3kΩ×4.7µF)= -1.88/0.1948 =-9.65Hz. 11. Determine the angle for given circuit diagram, if the frequency of input signal is 1khz
A. -45o B. -180o C. -270o D. -90o
Explanation: Phase angle Φ=-2tan-1×(2πfRC/1) = -2tan-1×(2π×1kHz×16kΩ×0.01µF)