The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on the surface of planet X such that the acceleration of the planet X is n times greater than the Earth
A. 0.9 n
B. \(\frac{0.9}{n} \mathrm{m}\)
C. 0.9 n2m
D. \(\frac{0.9}{n^{2}}\)
Answer:A
The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on the surface of planet X such that the acceleration of the planet X is n times greater than the Earth
A. 0.9 n B. \(\frac{0.9}{n} \mathrm{m}\) C. 0.9 n2m D. \(\frac{0.9}{n^{2}}\)