The position of a point in time ‘t’ is given by x = a + bt – ct2, y = at + bt2. Its acceleration at time ‘t’ is
A. b – c
B. b + c
C. 2b – 2c
D. \(2 \sqrt{b^{2}+c^{2}}\)
Answer:D
The position of a point in time ‘t’ is given by x = a + bt – ct2, y = at + bt2. Its acceleration at time ‘t’ is
A. b – c B. b + c C. 2b – 2c D. \(2 \sqrt{b^{2}+c^{2}}\)