#include &lt;iostream&gt;     #include &lt;limits&gt;    using namespace std;    int main&#40; &#41;    &#123;        cout &lt;&lt; numeric_limits&lt;float&gt; :: digits10 &lt;&lt; endl;        cout &lt;&lt; numeric_limits&lt;double&gt; :: digits10 &lt;&lt; endl;        float f = 99999999;        cout.precision &#40; 10 &#41;;        cout &lt;&lt; f &lt;&lt; endl;    &#125;
A. 6
B. 15
C. 100000000
D. All of the mentioned
Answer:A
#include &lt;iostream&gt;     #include &lt;limits&gt;    using namespace std;    int main&#40; &#41;    &#123;        cout &lt;&lt; numeric_limits&lt;float&gt; :: digits10 &lt;&lt; endl;        cout &lt;&lt; numeric_limits&lt;double&gt; :: digits10 &lt;&lt; endl;        float f = 99999999;        cout.precision &#40; 10 &#41;;        cout &lt;&lt; f &lt;&lt; endl;    &#125;
A. 6 B. 15 C. 100000000 D. All of the mentioned
Explanation:In this program, We are finding the number of decimal points that the type can represent without loss of precision.