#include &lt;iostream&gt;    using namespace std;    int main&#40;&#41;    &#123;        int x;        int *p;        x = 5;        p = &amp;x;        cout &lt;&lt; *p;        return 0;    &#125;
A. 5
B. 10
C. memory address
D. none of the mentioned
Answer:A
#include &lt;iostream&gt;    using namespace std;    int main&#40;&#41;    &#123;        int x;        int *p;        x = 5;        p = &amp;x;        cout &lt;&lt; *p;        return 0;    &#125;
A. 5 B. 10 C. memory address D. none of the mentioned
Explanation:In this program, we are copying the memory location of x into p and then printing the value in the address.