If A and B are 2 events such that P(A) > 0 and P (b) ≠ 1, then \(P(\bar{A} / \bar{B})=\)
A. 1 – P(A|B)
B. \(1-P(A / \bar{B})\)
C. \(\frac{1-P(A \cup B)}{P(B)}\)
D. \(\frac{1(\bar{A})}{P(B)}\)
Answer:B
If A and B are 2 events such that P(A) > 0 and P (b) ≠ 1, then \(P(\bar{A} / \bar{B})=\)
A. 1 – P(A|B) B. \(1-P(A / \bar{B})\) C. \(\frac{1-P(A \cup B)}{P(B)}\) D. \(\frac{1(\bar{A})}{P(B)}\)