= -3.3×10-4×2π×1000 ×[cos2π(1000)t] =-2.07×[cos2π(1000)t]. 11. Choose the value of RF and C for a 5kHz input signal to obtain good differentiation.
A. RF=1.6×103Ω, C1= 33×10-6F
B. RF=1.6×103Ω, C1= 0.47×10-6F
C. RF=1.6×103Ω, C1= 47×10-6F
D. RF=1.6×103 Ω, C1= 10×10-6F
Answer:A
= -3.3×10-4×2π×1000 ×[cos2π(1000)t] =-2.07×[cos2π(1000)t]. 11. Choose the value of RF and C for a 5kHz input signal to obtain good differentiation.
A. RF=1.6×103Ω, C1= 33×10-6F B. RF=1.6×103Ω, C1= 0.47×10-6F C. RF=1.6×103Ω, C1= 47×10-6F D. RF=1.6×103 Ω, C1= 10×10-6F
Explanation: For a good differentiation, the time period of the input signal must be larger than or equal to RF C1 i.e. T ≥ RF×C1