By combining two pairs of poles to form a fourth order filter section, by what factor we have reduced the number of multiplications?
A. 25%
B. 30%
C. 40%
D. 50%
Answer:A
By combining two pairs of poles to form a fourth order filter section, by what factor we have reduced the number of multiplications?
A. 25% B. 30% C. 40% D. 50%
Explanation: We have to do 3 multiplications for every second order equation. So, we have to do 6 multiplications if we combine two second order equations and we have to perform 3 multiplications by directly calculating the fourth order equation. Thus the number of multiplications are reduced by a factor of 50%.