#include &lt;iostream&gt;    using namespace std;    struct sec &#123;        int a;        char b;    &#125;;    int main&#40;&#41;    &#123;        struct sec s =&#123;25,50&#125;;        struct sec *ps =&#40;struct sec *&#41;&amp;s;        cout &lt;&lt; ps-&gt;a &lt;&lt; ps-&gt;b;        return 0;    &#125;
A. 252
B. 253
C. 254
D. 262
Answer:A
#include &lt;iostream&gt;    using namespace std;    struct sec &#123;        int a;        char b;    &#125;;    int main&#40;&#41;    &#123;        struct sec s =&#123;25,50&#125;;        struct sec *ps =&#40;struct sec *&#41;&amp;s;        cout &lt;&lt; ps-&gt;a &lt;&lt; ps-&gt;b;        return 0;    &#125;
A. 252 B. 253 C. 254 D. 262
Explanation:In this program, We are dividing the values of a and b, printing it.