The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is v, at 480 K it becomes
A. 4v
B. 2v
C. \(\frac{v}{2}\)
D. \(\frac{v}{4}\)
Answer:B
The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is v, at 480 K it becomes
A. 4v B. 2v C. \(\frac{v}{2}\) D. \(\frac{v}{4}\)