#include&lt;stdio.h&gt;   #include&lt;string.h&gt;&nbsp;   int main&#40;&#41;   &#123;       int fd&#91;2&#93;;       int count;       char buffer&#91;6&#93;;       if&#40; pipe&#40;fd&#41; != 0&#41;           perror&#40;&quot;pipe&quot;&#41;;       memset&#40;buffer,'\0',6&#41;;       count=write&#40;fd&#91;1&#93;,&quot;Linux&quot;,6&#41;;       read&#40;fd&#91;0&#93;,buffer,6&#41;;       printf&#40;&quot;%s\n&quot;,buffer&#41;;       return 0;put   &#125;
A. this program will print the string “Linux”
B. this program will print nothing because the buffer is empty
C. segmentation fault
D. none of the mentioned
Answer:A
#include&lt;stdio.h&gt;   #include&lt;string.h&gt;&nbsp;   int main&#40;&#41;   &#123;       int fd&#91;2&#93;;       int count;       char buffer&#91;6&#93;;       if&#40; pipe&#40;fd&#41; != 0&#41;           perror&#40;&quot;pipe&quot;&#41;;       memset&#40;buffer,'\0',6&#41;;       count=write&#40;fd&#91;1&#93;,&quot;Linux&quot;,6&#41;;       read&#40;fd&#91;0&#93;,buffer,6&#41;;       printf&#40;&quot;%s\n&quot;,buffer&#41;;       return 0;put   &#125;
A. this program will print the string “Linux” B. this program will print nothing because the buffer is empty C. segmentation fault D. none of the mentioned
Explanation:The data in buffer is written by the pipe.