Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at the normal incidence. At the angular position of the first diffraction minimum, the phase difference between the wavelets from the opposite edges of the slits is
A. \(\frac { π }{ 4 }\)
B. \(\frac { π }{ 2 }\)
C. 2π
D. π
Answer:C
Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at the normal incidence. At the angular position of the first diffraction minimum, the phase difference between the wavelets from the opposite edges of the slits is
A. \(\frac { π }{ 4 }\) B. \(\frac { π }{ 2 }\) C. 2π D. π