The ascending order of \(\frac{-3}{5}, \frac{-2}{5}, \frac{-1}{5}\) is :
A. \(\frac{-1}{5}<\frac{3}{5}<\frac{2}{5}\)
B. \(\frac{-3}{5}<\frac{-2}{5}<\frac{-1}{5}\)
C. \(\frac{-3}{5}<\frac{-1}{5}<\frac{-2}{5}\)
D. \(\frac{-2}{5}<\frac{-3}{5}<\frac{-1}{5}\)
Answer:B
The ascending order of \(\frac{-3}{5}, \frac{-2}{5}, \frac{-1}{5}\) is :
A. \(\frac{-1}{5}<\frac{3}{5}<\frac{2}{5}\) B. \(\frac{-3}{5}<\frac{-2}{5}<\frac{-1}{5}\) C. \(\frac{-3}{5}<\frac{-1}{5}<\frac{-2}{5}\) D. \(\frac{-2}{5}<\frac{-3}{5}<\frac{-1}{5}\)