The solution of (x + y)2 \(\frac{d y}{d x}\) = 1 is…….
A. x = tan-1(x + y) + c
B. y tan-1(\(\frac{x}{y}\)) = c
C. y = tan-1(x + y) + c
D. y + tan-1(x + y) = c
Answer:C
The solution of (x + y)2 \(\frac{d y}{d x}\) = 1 is…….
A. x = tan-1(x + y) + c B. y tan-1(\(\frac{x}{y}\)) = c C. y = tan-1(x + y) + c D. y + tan-1(x + y) = c