When light of wavelength A falls on the cathode of a photocell, the kinetic energy of the most energetic photoelectrons emitted is £. If light of wavelength λ/2 is used, what can be said about the new value E’?
A. E’ = E/2
B. E’ = E
C. E’ = 2E
D. E’ > 2E.
Answer:D
When light of wavelength A falls on the cathode of a photocell, the kinetic energy of the most energetic photoelectrons emitted is £. If light of wavelength λ/2 is used, what can be said about the new value E’?
A. E’ = E/2 B. E’ = E C. E’ = 2E D. E’ > 2E.