Let the function f be defined such that f(= x2 - c, where c is a constant. If f(-2) = 6, what is the value of c ?
A. -10
B. -2
C. 0
D. 2
Answer:B
Let the function f be defined such that f(= x2 - c, where c is a constant. If f(-2) = 6, what is the value of c ?
A. -10 B. -2 C. 0 D. 2
Explanation: B Start by plugging in what you know into the function given. If f(x) = x2 - c, and f(-2) = 6, then plug in -2 for x in the function: f(-2) = (-2)2 - c. Solve and replace f(-2) with 6: 6 = 4 - c; 2 = -c; and c = -2. If you picked (A), you forgot that (-2)2 is positive 4.