UV radiation of energy 6.2 eV falls on molybdenum surface whose photoelectric work function is 4.2 eV. The kinetic energy of the fastest photoelectrons is
A. 3.2 × 10-19 J
B. 3.52 × 10-19 J
C. 6.72 × 10-19 J
D. 9.92 × 10-19 J.
Answer:A
UV radiation of energy 6.2 eV falls on molybdenum surface whose photoelectric work function is 4.2 eV. The kinetic energy of the fastest photoelectrons is
A. 3.2 × 10-19 J B. 3.52 × 10-19 J C. 6.72 × 10-19 J D. 9.92 × 10-19 J.