#include &lt;stdio.h&gt;    #define foo(x, y) x / y + x    int main&#40;&#41;    &#123;        int i = -6, j = 3;        printf&#40;&quot;%d\n&quot;,foo&#40;i + j, 3&#41;&#41;;        return 0;    &#125;
A. Divided by zero exception
B. Compile time error
C. -8
D. -4
Answer:A
#include &lt;stdio.h&gt;    #define foo(x, y) x / y + x    int main&#40;&#41;    &#123;        int i = -6, j = 3;        printf&#40;&quot;%d\n&quot;,foo&#40;i + j, 3&#41;&#41;;        return 0;    &#125;
A. Divided by zero exception B. Compile time error C. -8 D. -4