=> CT =1/(4×RT×fo) =1/(4×5kΩ×25kHz) = 2×10-9 =2nF. 8. What is the advantage of using filter?
A. High noise immunity
B. Reduce the bandwidth of PLL
C. Provides dynamic range of frequencies
D. None of the mentioned
Answer:A
=> CT =1/(4×RT×fo) =1/(4×5kΩ×25kHz) = 2×10-9 =2nF. 8. What is the advantage of using filter?
A. High noise immunity B. Reduce the bandwidth of PLL C. Provides dynamic range of frequencies D. None of the mentioned