Cu2+/Cu(s) = + 0.34; I2(s)/I– = + 0.54
A. Cu will reduce Br–
B. Cu will reduce Ag
C. Cu will reduce I–
D. Cu will reduce Br2
Answer:C
Cu2+/Cu(s) = + 0.34; I2(s)/I– = + 0.54
A. Cu will reduce Br– B. Cu will reduce Ag C. Cu will reduce I– D. Cu will reduce Br2