Total number of electrons present in 1.7 g of ammonia is
A. 6.022 × 1023
B. \(\frac{6.022 \times 10^{22}}{1.7}\)
C. \(\frac{6.022 \times 10^{24}}{1.7}\)
D. \(\frac{6.022 \times 10^{23}}{1.7}\)
Answer:A
Total number of electrons present in 1.7 g of ammonia is
A. 6.022 × 1023 B. \(\frac{6.022 \times 10^{22}}{1.7}\) C. \(\frac{6.022 \times 10^{24}}{1.7}\) D. \(\frac{6.022 \times 10^{23}}{1.7}\)