The boiling point of water (100°becomes 100.25°C, if 3 grams of a nonvolatile solute is dissolved in 200 ml of water. The molecular weight of solute is (Kb for water is 0.6 K Kg mol-1)
A. 12.2 g mol-1
B. 15.4 g mol
C. 17.3 g mol-1
D. 20.4 g mol
Answer:C
The boiling point of water (100°becomes 100.25°C, if 3 grams of a nonvolatile solute is dissolved in 200 ml of water. The molecular weight of solute is (Kb for water is 0.6 K Kg mol-1)
A. 12.2 g mol-1 B. 15.4 g mol C. 17.3 g mol-1 D. 20.4 g mol