If x = \(\frac { 1-t^{ 2 } }{ 1+t^{ 2 } } \) and y = \(\frac { 2t }{ 1+t^{ 2 } } \) then \(\frac{dy}{dx}\) = ………………..
A. \(\frac{y}{x}\)
B. \(\frac{-y}{x}\)
C. –\(\frac{x}{y}\)
D. \(\frac{x}{y}\)
Answer:C
If x = \(\frac { 1-t^{ 2 } }{ 1+t^{ 2 } } \) and y = \(\frac { 2t }{ 1+t^{ 2 } } \) then \(\frac{dy}{dx}\) = ………………..
A. \(\frac{y}{x}\) B. \(\frac{-y}{x}\) C. –\(\frac{x}{y}\) D. \(\frac{x}{y}\)