There are n1 protons of frequency v1 in a beam of light. In an equally energetic beam, there are n2 protons of frequency v2 Then the correct relation is:
A. \(\frac{n_{1}}{n_{2}}\) = 1
B. \(\frac{n_{1}}{n_{2}}=\frac{\nu_{1}}{\nu_{2}}\)
C. \(\frac{n_{1}}{n_{2}}=\frac{v_{2}}{v_{1}}\)
D. \(\frac{n_{1}}{n_{2}}=\frac{v_{1}^{2}}{v_{2}^{2}}\)
Answer:C
There are n1 protons of frequency v1 in a beam of light. In an equally energetic beam, there are n2 protons of frequency v2 Then the correct relation is:
A. \(\frac{n_{1}}{n_{2}}\) = 1 B. \(\frac{n_{1}}{n_{2}}=\frac{\nu_{1}}{\nu_{2}}\) C. \(\frac{n_{1}}{n_{2}}=\frac{v_{2}}{v_{1}}\) D. \(\frac{n_{1}}{n_{2}}=\frac{v_{1}^{2}}{v_{2}^{2}}\)