In an A.C circuit the applied emf e = E0 sin (ωt + π/2) leads the current I = I0 sin (ωt – π/2) by:
A. π/2
B. π/4
C. π
D. 0
Answer:C
In an A.C circuit the applied emf e = E0 sin (ωt + π/2) leads the current I = I0 sin (ωt – π/2) by:
A. π/2 B. π/4 C. π D. 0