=>|VO/Vin|=2/4.123= =0.4851 = 20log(0.4851) = -6.28dB. 9. How is the higher order filters formed?
A. Using first order filter
B. Using second order filter
C. Connecting first and second order filter in series
D. Connecting first and second order filter in parallel
Answer:A
=>|VO/Vin|=2/4.123= =0.4851 = 20log(0.4851) = -6.28dB. 9. How is the higher order filters formed?
A. Using first order filter B. Using second order filter C. Connecting first and second order filter in series D. Connecting first and second order filter in parallel