Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is
A. 14.4 Z/V Å
B. 14.4 V/Z Å
C. 1.44 Z/V Å
D. 1.44 V/Z Å
Answer:A
Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is
A. 14.4 Z/V Å B. 14.4 V/Z Å C. 1.44 Z/V Å D. 1.44 V/Z Å