\(\frac{x}{3}+\frac{y}{4}=\frac{1}{24}\) in the form of ax + by + c = 0 is
A. 3x + 4y = 2
B. 4x + 3y = 2
C. 8x + 6y + 1 = 0
D. 8x + 6y – 1 = 0
Answer:D
\(\frac{x}{3}+\frac{y}{4}=\frac{1}{24}\) in the form of ax + by + c = 0 is
A. 3x + 4y = 2 B. 4x + 3y = 2 C. 8x + 6y + 1 = 0 D. 8x + 6y – 1 = 0