Maxwell’s modified Ampere’s Law is
A. \(\oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0}\left(\mathrm{I}_{\mathrm{c}}+\mathrm{I}_{\mathrm{d}}\right)\)
B. \(\oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0} \mathrm{I}_{\mathrm{c}}\)
C. \(\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0} \mathrm{I}_{\mathrm{c}}\)
D. \(\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0}\left(\mathrm{I}_{\mathrm{c}}+\mathrm{I}_{\mathrm{d}}\right)\)
Answer:D
Maxwell’s modified Ampere’s Law is
A. \(\oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0}\left(\mathrm{I}_{\mathrm{c}}+\mathrm{I}_{\mathrm{d}}\right)\) B. \(\oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0} \mathrm{I}_{\mathrm{c}}\) C. \(\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0} \mathrm{I}_{\mathrm{c}}\) D. \(\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{d} s}=\mu_{0}\left(\mathrm{I}_{\mathrm{c}}+\mathrm{I}_{\mathrm{d}}\right)\)