The area of a parallelogram whose base is ‘b’ units, height is ‘h’ units (in sq. units)
A. bh
B. \(\frac{1}{2}\)bh
C. \(\frac{1}{2}\) × d1 × d2
D. \(\frac{1}{2}\) × h (a + b)
Answer:A
The area of a parallelogram whose base is ‘b’ units, height is ‘h’ units (in sq. units)
A. bh B. \(\frac{1}{2}\)bh C. \(\frac{1}{2}\) × d1 × d2 D. \(\frac{1}{2}\) × h (a + b)