Consider a circuit consisting of two capacitors C1 and C2. Let R be the resistance and L be the inductance which are connected in series. Let Q1 and Q2 be the quality factor for the two capacitors. While measuring the Q value by the Parallel Connection method, the value of the Q factor is?
A. Q = (frac{(C_1 – C_2 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2})
B. Q = (frac{(C_2 – C_1 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2})
C. Q = (frac{(C_1 – C_2 ) Q_1 Q_2}{Q_2 C_2 – Q_1 C_1})
D. Q = (frac{(C_2 – C_1 ) C_1 C_2}{Q_1 C_1 – Q_2 C_2})
Answer:B
Consider a circuit consisting of two capacitors C1 and C2. Let R be the resistance and L be the inductance which are connected in series. Let Q1 and Q2 be the quality factor for the two capacitors. While measuring the Q value by the Parallel Connection method, the value of the Q factor is?
A. Q = (frac{(C_1 – C_2 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}) B. Q = (frac{(C_2 – C_1 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}) C. Q = (frac{(C_1 – C_2 ) Q_1 Q_2}{Q_2 C_2 – Q_1 C_1}) D. Q = (frac{(C_2 – C_1 ) C_1 C_2}{Q_1 C_1 – Q_2 C_2})