\(\overline{\mathrm{XY}}\) is the perpendicular bisector of \(\overline{\mathrm{PQ}}\). Then ∆POX = ∆QOX by
A. S.A.S
B. A.S.A
C. S.S.S
D. A.A.A.
Answer:A
\(\overline{\mathrm{XY}}\) is the perpendicular bisector of \(\overline{\mathrm{PQ}}\). Then ∆POX = ∆QOX by
A. S.A.S B. A.S.A C. S.S.S D. A.A.A.