#include &lt;iostream&gt;    using namespace std;    int main&#40;&#41;    &#123;        int a = 5;        float b;        cout &lt;&lt; sizeof&#40;++a + b&#41;;        cout &lt;&lt; a;        return 0;    &#125;
A. 2 6
B. 4 6
C. 2 5
D. 4 5
Answer:A
#include &lt;iostream&gt;    using namespace std;    int main&#40;&#41;    &#123;        int a = 5;        float b;        cout &lt;&lt; sizeof&#40;++a + b&#41;;        cout &lt;&lt; a;        return 0;    &#125;
A. 2 6 B. 4 6 C. 2 5 D. 4 5
Explanation:The a as a integer will be converted to float while calculating the size. The value of any variable doesn’t modify inside sizeof operator. Hence value of variable a will remain 5.