Question : The shortest wavelength in Balmer’s series for Hydrogen atom is ...A... and this is obtained by substituting ...B ... in Balmer’s formula. Here, A and B refer to
A. 656.3 nm, n : 3
B. 486.1 nm, n : 4
C. 410.2 nm, n : 5
D. 364.6 nm, n :
Answer:D
Question : The shortest wavelength in Balmer’s series for Hydrogen atom is ...A... and this is obtained by substituting ...B ... in Balmer’s formula. Here, A and B refer to
A. 656.3 nm, n : 3 B. 486.1 nm, n : 4 C. 410.2 nm, n : 5 D. 364.6 nm, n :