Let ‘O’ be the centre of a circle. The distance of chord AB from O is greater than the distance of chord CD from ‘O’ then
A. AB = CD
B. AB > CD
C. AB < CD
D. Diameter = AB + CD
Answer:B
Let ‘O’ be the centre of a circle. The distance of chord AB from O is greater than the distance of chord CD from ‘O’ then
A. AB = CD B. AB > CD C. AB < CD D. Diameter = AB + CD