In the given figure, D, E are points on the sides AB and AC respectively of ΔABC. Also ar (ΔDBC) = ar (ΔEBC), then
A. ar (ΔADE) = \(\frac{1}{2}\)ar (ΔDBC)
B. ar (ΔADE) = \(\frac{1}{2}\)ar (ΔEBC)
C. ar (ΔABE) = ar (ΔACD)
D. DE // BC
Answer:D
In the given figure, D, E are points on the sides AB and AC respectively of ΔABC. Also ar (ΔDBC) = ar (ΔEBC), then
A. ar (ΔADE) = \(\frac{1}{2}\)ar (ΔDBC) B. ar (ΔADE) = \(\frac{1}{2}\)ar (ΔEBC) C. ar (ΔABE) = ar (ΔACD) D. DE // BC