<p><b>四氯化鏷</b>是無機化合物，是一種鏷鹵化物，由鏷和氯組成，具有放射性，化學式為PaCl<sub>4</sub>，是黃綠色晶體，為四方晶系結構的晶體。它可由五氯化鏷的還原反應或二氧化鏷氯化得到：</p>
<dl><dd><span><span><math xmlns="http://www.w3.org/1998/Math/MathML" alttext="{\displaystyle {\ce {2 PaCl5 + H2 -&gt; 2 PaCl4 + 2 HCl}}}">
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            <mtext>PaCl</mtext>
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    <annotation encoding="application/x-tex">{\displaystyle {\ce {2 PaCl5 + H2 -&gt; 2 PaCl4 + 2 HCl}}}</annotation>
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<dd><span><span><math xmlns="http://www.w3.org/1998/Math/MathML" alttext="{\displaystyle {\ce {3 PaCl5 + Al -&gt; 3 PaCl4 + AlCl3}}}">
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            <mtext>PaCl</mtext>
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    <annotation encoding="application/x-tex">{\displaystyle {\ce {3 PaCl5 + Al -&gt; 3 PaCl4 + AlCl3}}}</annotation>
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<dd><span><span><math xmlns="http://www.w3.org/1998/Math/MathML" alttext="{\displaystyle {\ce {PaO2 + 2 CCl4 -&gt; PaCl4 + 2 COCl2}}}">
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    <annotation encoding="application/x-tex">{\displaystyle {\ce {PaO2 + 2 CCl4 -&gt; PaCl4 + 2 COCl2}}}</annotation>
  </semantics></math></span></span></dd></dl><h2><span id=".E5.8F.83.E8.80.83.E6.96.87.E7.8D.BB"></span><span id="參考文獻">參考文獻</span></h2>

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**四氯化鏷**是無機化合物，是一種鏷鹵化物，由鏷和氯組成，具有放射性，化學式為 PaCl4，是黃綠色晶體，為四方晶系結構的晶體。它可由五氯化鏷的還原反應或二氧化鏷氯化得到：

　
: ${\ce {2 PaCl5 + H2 -> 2 PaCl4 + 2 HCl}}$

　
: ${\ce {3 PaCl5 + Al -> 3 PaCl4 + AlCl3}}$

　
: ${\ce {PaO2 + 2 CCl4 -> PaCl4 + 2 COCl2}}$

## 參考文獻
13867-41-9