The points $(9, -5)$ and $(-3, -1)$ are the endpoints of a diameter of a circle. What is the sum of the coordinates of the center of the circle?
The center of the circle is located at the midpoint of any diameter. Thus, the center of the circle is $\left(\frac{9+(-3)}{2}, \frac{(-5)+(-1)}{2}\right) = (3, -3)$. The sum of the coordinates of the center of the circle is therefore $3 + (-3) = \boxed{0}$.