I have found a way to assign NAN to a variable, thanks to the library
source code.  Is this better than the code I just posted?  Looks pretty
platform-specific, and we may be better with my earlier code to just use
num, which I have committed to the CURRENT tree.

The strange thing is that isnan(0/0) generates a floating-pointer error
and stops the program, but this does not.  Strange.

---------------------------------------------------------------------------
	
	#include <stdio.h>
	#include <math.h>
	
	main()
	{
		double x;
		x = 3;
		
		if (isnan((x-x)/(x-x)))
			printf("nan\n");
		else
			printf("not nan\n");
	}

-- 
  Bruce Momjian                        |  http://www.op.net/~candle
  maillist@candle.pha.pa.us            |  (610) 853-3000
  +  If your life is a hard drive,     |  830 Blythe Avenue
  +  Christ can be your backup.        |  Drexel Hill, Pennsylvania 19026

Thu, 31 Dec 1998 23:23:48 -0500 (EST)
Bruce Momjian <maillist@candle.pha.pa.us>
NAN code