Electricity and magnetism
Magnetism 4 Part 2 of the proton through a magnetic field problem
⇐ Use this menu to view and help create subtitles for this video in many different languages. You'll probably want to hide YouTube's captions if using these subtitles.
- In the last video we figured out that if we had a proton
- coming into the right at a velocity of 6 times 10 to the
- seventh meters per second.
- So the magnitude of the velocity is 1/5
- the speed of light.
- And if it were to cross this magnetic field, we used this
- formula to figure out that the magnitude of the force on this
- proton would be 4.8 times 10 to the negative 12 newtons.
- And then the direction, we used our right hand rule
- because it's a cross product.
- And we figured out that it would be perpendicular-- well,
- it has to be perpendicular to both, because we're taking the
- cross product-- and right when it enters, the net force will
- be downwards.
- But then think about what happens.
- If you have a downward force right there, then the particle
- will be deflected downward a little bit, so its velocity
- vector will then look something like that.
- But it's still in the magnetic field, right?
- And not only is it still in the magnetic field, but since
- the particle is still moving within the plane of your video
- screen, it's still completely perpendicular to
- the magnetic field.
- And so the magnitude of the force on the moving particle
- won't change, just the direction will.
- Because if we do the right hand rule here, but if we just
- move our hand down a little bit, if we tilt it down, then
- our thumb's going to be pointing in this direction.
- And that just keeps happening.
- It gets deflected that way a little bit.
- So the magnitude of the velocity doesn't ever change.
- It always stays perpendicular to the magnetic field because
- it's always staying in this plane.
- But the orientation does change within the plane.
- And because of that, because the orientation of the
- velocity changes, the orientation
- of the force changes.
- So when the velocity is here, the force is perpendicular.
- So it acts as kind of a centripetal force, and so the
- particle will start moving in a circle.
- So let's see if we can break out our toolkit from what
- we've learned before in classical mechanics, and
- figure out what the radius of that circle is.
- And that might seem more daunting than it really is.
- Well, what do we know about centripetal forces and
- radiuses of circles, et cetera?
- So, what is the formula for centripetal force?
- And we proved it many, many videos ago, early in the
- physics playlist. Well, centripetal acceleration is
- the magnitude of the velocity vector squared over the radius
- of the circle.
- And since this is acceleration, if we want to
- know the centripetal force, it's just the mass times
- So it's the mass of the particle, or the object in
- question, times the magnitude of its velocity squared
- divided by the radius of the circle.
- In this case, this is the radius of the circle.
- And that's what we're going to try to solve for.
- And what do we know about the centripetal force?
- What is causing the centripetal force?
- Well, it's the magnetic field and we've figured that out.
- This is going to be equal to this, which we figured out is
- going to be equal to-- at least the magnitudes-- the
- magnitude of this is equal to the magnitude of this.
- And that magnitude is 4.8 times 10 to
- the minus 12 newtons.
- And so the radius is going to be-- let's see, if we flip
- both sides of this equation, we get radius over mass
- velocity squared is equal to 1 over 4.8 times 10
- to the minus 12.
- I could just figure out what that number is, but I won't
- worry about that now.
- Then we can multiply both sides times this mv squared.
- And we get that the radius of the circle is going to be
- equal to the mass of the proton times the magnitude of
- its velocity squared divided by the force from
- the magnetic field.
- The centripetal force.
- 4.8 times 10 to the minus 12 newtons.
- And the radius should be in meters, since everything is
- kind of in the standard SI units.
- And let's see if we can figure this out.
- Get our calculator.
- And this is where that constant function is useful
- again, because what is the mass of a proton?
- Well, that's something that I
- personally don't have memorized.
- But if we go into the built-in constants on the
- TI-85-- let's see more.
- Mass of a proton.
- This is mass of an electron.
- This is mass of a proton.
- So mass of a proton-- that's what we care about-- times the
- magnitude of the velocity squared.
- What was the velocity?
- It was 6 times 10 to the seventh meters per second.
- So times 6 times 10 to the seventh
- meters per second squared.
- And all of that divided by the magnitude of
- the centripetal force.
- Which is the force that's being generated by the
- magnetic field.
- That's 4.8 times 10 to the negative 12.
- Divided by 4.8 E minus 12.
- Let's see.
- Hopefully we don't get something funky.
- There we go.
- That's actually a pretty neat number.
- 1.25 meters.
- That's actually a number that we can imagine.
- So if you have a proton going in this direction at 1/5 the
- speed of light through a-- what'd I say it was?
- It was a 0.5 tesla magnetic field, where the vectors are
- pointing out of the video.
- We have just shown that this proton will go in a circle of
- radius 1.25 meters.
- Which is neat because it's a number that I
- can actually visualize.
- And so this whole business of magnetic fields making charged
- particles go into circles, this is one of the few times
- that I can actually say has a direct application into things
- that you've seen.
- Namely, your TV.
- Or at least the old-school TVs. The non-plasma or LCD
- TVs, your cathode ray TVs, take advantage of this.
- Where you essentially have a beam of
- not protons but electrons.
- And a magnet-- if you take apart a TV, which I don't
- think you should do, because you're more likely to hurt
- yourself because there's a vacuum in there that can
- implode, and all that-- but essentially, you have a magnet
- that deflects this electron beam and does it really fast
- so it scans your entire screen of different intensities, and
- that's what forms the image.
- I won't go into that detail.
- Maybe one day I'll do a whole video on how TVs work.
- So that's one application of a magnetic field causing a beam
- of charged particles to curve.
- And then the other application, and this is
- actually one where it's actually useful to make the
- particle go in a circle, is these cyclotrons that you read
- about, where they take these protons and they make them go
- in circles really, really fast, and then
- they smash them together.
- Well, have you ever wondered, how do they even make a proton
- go in a circle?
- It's not like you could hold it and guide
- it around in a circle.
- Well, that's what they do.
- They pass it through an appropriate strength magnetic
- field, and it curves the path of the proton so that it can
- keep going through the same field over and over again.
- And then they can actually use those electric fields.
- I don't claim to have any expertise in this, but then
- they can keep speeding it up using the same devices,
- because it keeps passing through the
- same part of the collider.
- And then once it collides, you've
- probably seen those pictures.
- You know, that you spend billions of dollars on
- supercolliders, and you end up with these pictures.
- And somehow these physicists are able to take these
- pictures and say, oh, this is some new particle because of
- the way it moved.
- Well, what they're actually talking about is these are
- moving at relativistic speeds.
- And since they're at relativistic speeds as they
- move at different velocities, their mass is
- changing, and all that.
- But the basic idea is what we just learned.
- They move in circles.
- They move in circles because they're going through a
- magnetic field.
- But their radiuses are different because their
- charges and their velocities are going to be different.
- And actually some will move to the left and some
- will move to the right.
- And that might be because they're positive or negative,
- and then the radius will be dependent on their masses.
- Anyway, I don't want to confuse you.
- But I just wanted to show you that we actually are touching
- on some physics that a physicist would
- actually care about.
- Now with that said, what would have happened if this wasn't a
- proton but if this was an electron moving at this
- velocity at 6 times 10 to the seventh meters per second
- through a 0.5 tesla magnetic field
- popping out of this video.
- What would have happened?
- Well, this formula would have still been safe.
- The magnitude of the force is the charge-- but it wouldn't
- have been the charge of a proton, it would have been the
- charge of an electron, times 6 times 10 to the seventh meters
- per second times 0.5 teslas.
- So what's the difference between the charge of a proton
- and the charge of an electron?
- Well, the charge of an electron is negative.
- So if this was an electron, then the net force would
- actually end up being a negative number.
- So what does that mean?
- Well, when we used the right hand rule with the proton
- example, we said that the-- at least when the proton is
- moving in this direction-- that the net
- force would be downwards.
- But now, all of a sudden, if we reverse the charge, if we
- say we have a negative charge-- the same magnitude
- but it's negative, because it's an
- electron-- what happens?
- The force is now in this direction, using the right
- hand rule, but it is a negative.
- So really it's going to be a positive force of the same
- magnitude in this direction.
- So if we have a proton, it'll go in a
- circle in this direction.
- It'll go like this.
- But if we have an electron, it'll go in a circle of the
- other direction.
- Now let me ask a question.
- Is that circle going to be a tighter
- circle or a wider circle?
- Well, the mass of an electron is a lot smaller than the mass
- of a proton.
- And we had the radius is equal to the mass times the velocity
- squared divided by the centripetal force.
- So this mass is smaller and the radius
- is going to be smaller.
- So the electron's path would actually move up and it would
- be a smaller radius.
- Actually proportional to the difference in their radiuses
- is the difference in their masses, actually.
- But that would be the path of the electron.
- Anyway, I thought you'd be interested in that, as well.
- I have run out of time.
- I will see you in the next video.
Be specific, and indicate a time in the video:
At 5:31, how is the moon large enough to block the sun? Isn't the sun way larger?
Have something that's not a question about this content?
This discussion area is not meant for answering homework questions.
Share a tip
When naming a variable, it is okay to use most letters, but some are reserved, like 'e', which represents the value 2.7831...
Have something that's not a tip or feedback about this content?
This discussion area is not meant for answering homework questions.
Discuss the site
For general discussions about Khan Academy, visit our Reddit discussion page.
Flag inappropriate posts
Here are posts to avoid making. If you do encounter them, flag them for attention from our Guardians.
- disrespectful or offensive
- an advertisement
- low quality
- not about the video topic
- soliciting votes or seeking badges
- a homework question
- a duplicate answer
- repeatedly making the same post
- a tip or feedback in Questions
- a question in Tips & Feedback
- an answer that should be its own question
about the site