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Given that alpha and beta are roots of the equation 3x^2-5=0 form the equation whose roots are 2alpha-1/beta, 2alpha-/alpha?
Given that alpha and beta are roots of the equation 3x^2-5=0, can you help me form the equation whose roots are 2alpha-1/beta, 2alpha-beta/alpha?
Sure, let me work that out. The equation whose roots are 2alpha-1/beta and 2alpha-beta/alpha is (3(beta(2alpha-1)-alpha(2alpha-beta)))x^2+(5beta(2alpha-beta))/(alpha(beta-2alpha))=0