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Three particles of mass 1kg, 2kg and 3kg are placed at the corners A, B and C respectively of an equilateral triangle ABC of edge 1m. How do I find the distance of their centre of mass from A?
The x-coordinate of particle B is 1/2 and the x-coordinate of particle C is -1/2.
Great. Now we can calculate the x-coordinate of the center of mass using the formula we just discussed. The sum of the products of mass and position is (1kg * 0m) + (2kg * 1/2m) + (3kg * -1/2m) = -1kgm. The total mass is 6kg, so the x-coordinate of the center of mass is -1/6m. Do you want me to calculate the y-coordinate as well?