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A stone is projected vertically upwards with speed 17.5m/s. The length of time for which it is at least 6.6m above its starting position is D/7 seconds. What is the value of D?
Can you help me solve a physics problem? A stone is projected vertically upwards with speed 17.5m/s. The length of time for which it is at least 6.6m above its starting position is D/7 seconds. What is the value of D?
Sure! Let me calculate that for you. Using the formula: h = u*t + (1/2)*a*t^2, where h is the height, u is the initial velocity, a is the acceleration, and t is the time, we can find the time it takes for the stone to reach a height of 6.6m above its starting position.