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What is the derivative with respect to x [math]\frac{x}{y} + \frac{y}{x} =1 [/math]?
What is the derivative with respect to x [math]\frac{x}{y} + \frac{y}{x} =1 [/math]?
To find the derivative of [math]\frac{x}{y} + \frac{y}{x} =1[/math] with respect to x, we need to use implicit differentiation. First, we'll differentiate both sides of the equation with respect to x, and then solve for dy/dx.