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How do I integrate [math]\int \frac{dx}{sin^2x+tan^2x}[/math]?
Could you help me with integrating [math]\int \frac{dx}{sin^2x+tan^2x}[/math]?
Sure! Let me first simplify the expression. [math]\frac{1}{sin^2(x)+tan^2(x)}=\frac{1}{sin^2(x)+\frac{sin^2(x)}{cos^2(x)}}=\frac{cos^2(x)}{sin^2(x)(1+cos^2(x))}.[/math]