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A student multiplied a number by 3/5 instead of 5/3.what is the percentage error?
How do you apply that formula in this situation?
In this situation, let's assume that the exact value is the result of multiplying the number by 5/3 and the approximate value is the result of multiplying the number by 3/5. So the percentage error would be [(5/3 - 3/5) / 5/3] x 100%.