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How do I solve √ [5+2(√6)]?
Yes, please.
The formula is (-b ± sqrt(b^2 - 4ac))/2a. In this case, a = 2, b = 5, and c = 12. So when you plug those values into the formula, you get 3 + √6 and 3 - √6. However, 3 - √6 is not a valid solution since the expression inside the square root has to be positive. Therefore, the answer is 3 + √6.