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The sum of the first [math]n[/math] odd natural number is [math]n^2[/math], but what is the sum of first [math]n[/math] natural even number?
That's interesting. Do you have any more mathematical formulas that you can share with me?
Yes, there is a formula for the sum of the cubes of the first [math]n[/math] natural numbers which is [math]\left(\frac{n(n+1)}{2}\right)^2[/math].