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How can I understand [math]dy/dx[/math]?
Can you give me an example of using the chain rule to find [math]dy/dx[/math]?
Sure, if you have a function y = sin(x^2), then you can use the chain rule to find [math]dy/dx[/math]. First, let u = x^2, then y = sin(u). Using the chain rule, we have [math]dy/dx[/math] = [math]dy/du[/math] * [math]du/dx[/math] = cos(u) * 2x = 2x cos(x^2).