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How do I evaluate [math]\int \frac{\sec x}{1+\csc x} dx[/math]?
Yes, I've tried a few but I can't seem to get it. Do you have any suggestions?
One possible approach is to use the identity [math]\csc x = \frac{1}{\sin x}[/math] to rewrite the denominator as [math]\frac{1+\sin x}{\sin x}[/math]. Then, substitute [math]u = \sin x + 1[/math] and work from there.