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What is [math]\sqrt {2+\sqrt {2+\sqrt {2+\sqrt {2+...\infty}}}}[/math] ?
Yes, please.
Let x be equal to [math]\sqrt {2+\sqrt {2+\sqrt {2+\sqrt {2+...\infty}}}}[/math]. Then, x^2 = 2 + x. Solving for x gives us x = 1 + sqrt(2).