text: Q:
  
  Unix cut command to extract string from left side post 2nd dilimiter from right
  
  how can the cut command return value left to 2nd last delimiter starting from the right side.
  $ echo 'qwertyuiop.abcdefgh.1234567890.txt' | cut -d '.' -f 1,2
  qwertyuiop.abcdefgh
  $ echo 'qwertyuiop.1234567890.txt' | cut -d '.' -f 1,2
  qwertyuiop.1234567890
  $ 
  
  expected output for both 
  
  qwertyuiop.abcdefgh
  qwertyuiop
  
  A:
  
  You can reverse your string with the rev command and then cut from the third field to the end, reversing at the end.
  $ echo 'qwertyuiop.abcdefgh.1234567890.txt' | rev | cut -d '.' -f 3- | rev
  qwertyuiop.abcdefgh
  $ echo 'qwertyuiop.1234567890.txt' | rev | cut -d '.' -f 3- | rev
  qwertyuiop
  
  