(The example is simple because the polynomial is monic ("a""n" = 1). For non-monic polynomials the set of possible roots will include some fractions but only a finite number of them since "a""n" and "a"0 have only a finite number of integer divisors each.) In any case, for monic polynomials, every rational root is an integer and so every integer root is just a divisor of the constant term ("a"0). It can be shown that to remain true for non-monic polynomials: "to find the integer roots of any polynomials with integer coefficients, checking the divisors of the constant term suffices".