As stated previously, the coefficients of ("x" + 1)"n" are the nth row of the triangle. Now the coefficients of ("x" − 1)"n" are the same, except that the sign alternates from +1 to −1 and back again. After suitable normalization, the same pattern of numbers occurs in the Fourier transform of sin("x")"n"+1/"x". More precisely: if "n" is even, take the real part of the transform, and if "n" is odd, take the imaginary part. Then the result is a step function, whose values (suitably normalized) are given by the "n"th row of the triangle with alternating signs. For example, the values of the step function that results from: