As an example, consider a Norton source (current "IA", parallel resistance "RA") driving a resistor load "RL". Because of current division (also referred to as "loading") the current delivered to the load is only "IA RA / ( RL + RA )". However, if the Norton source drives a unity gain buffer such as that in Figure 1 (bottom, with unity gain), the current input to the amplifier is "IA", with "no current division" because the amplifier input resistance is zero. At the output the dependent current source delivers current "βi IA = IA" to the load, again without current division because the output resistance of the buffer is infinite. A Norton equivalent circuit of the combined original Norton source "and" the buffer is an ideal current source "IA" with infinite Norton resistance.