Man benötigt also 512-MByte-RIMMs , um den maximalen Speicherausbau von 1 GByte ( Pentium-III-Chipsatz i820 ) beziehungsweise 2 GByte ( Pentium-4-Chipsatz i850 ) zu realisieren .
1	Man	Man	PRON	PIS	Case=Nom|Number=Sing|Person=3|PronType=Ind,Neg,Tot	2	nsubj	_	_
2	benötigt	benötigen	VERB	VVFIN	Mood=Ind|Number=Sing|Person=3|Tense=Pres|VerbForm=Fin	0	root	_	_
3	also	also	ADV	ADV	_	2	advmod	_	_
4	512-MByte-RIMMs	unknown	NOUN	NN	Person=3	2	obj	_	_
5	,	,	PUNCT	$,	PunctType=Comm	25	punct	_	_
6	um	um	SCONJ	KOUI	_	25	mark	_	_
7	den	den	DET	ART	Case=Acc|Gender=Masc|Number=Sing|PronType=Art	9	det	_	_
8	maximalen	maximal	ADJ	ADJA	Case=Acc|Degree=Pos|Gender=Masc|Number=Sing	9	amod	_	_
9	Speicherausbau	Ausbau	NOUN	NN	Gender=Masc|Number=Sing|Person=3	25	obj	_	_
10	von	von	ADP	APPR	AdpType=Prep|Case=Dat	12	case	_	_
11	1	1	NUM	CARD	Number=Sing|NumType=Card|Person=3	12	nummod	_	_
12	GByte	GByte	NOUN	NN	Gender=Neut|Number=Sing|Person=3	9	nmod	_	_
13	(	(	PUNCT	$(	PunctType=Brck	14	punct	_	_
14	Pentium-III-Chipsatz	Chipsatz	NOUN	NN	Gender=Masc|Number=Sing|Person=3	12	appos	_	_
15	i820	i820	X	FM	Foreign=Yes|Person=3	14	appos	_	_
16	)	)	PUNCT	$(	PunctType=Brck	14	punct	_	_
17	beziehungsweise	beziehungsweise	CCONJ	KON	_	19	cc	_	_
18	2	2	NUM	CARD	Number=Plur|NumType=Card|Person=3	19	nummod	_	_
19	GByte	GByte	NOUN	NN	Gender=Neut|Number=Plur|Person=3	14	conj	_	_
20	(	(	PUNCT	$(	PunctType=Brck	21	punct	_	_
21	Pentium-4-Chipsatz	Chipsatz	NOUN	NN	Gender=Masc|Number=Sing|Person=3	19	appos	_	_
22	i850	i850	X	FM	Foreign=Yes|Person=3	21	appos	_	_
23	)	)	PUNCT	$(	PunctType=Brck	21	punct	_	_
24	zu	zu	PART	PTKZU	PartType=Inf	25	mark	_	_
25	realisieren	realisieren	VERB	VVINF	VerbForm=Inf	2	advcl	_	_
26	.	.	PUNCT	$.	PunctType=Peri	2	punct	_	_
