<s>[INST] Finding $k$ such that $\frac{3x^2+kx-44}{x^2-121}$ simplifies to $\frac{3x-4}{x-11}$ 
If the rational expression $\frac{3x^2+kx-44}{x^2-121}$, where $k$ is an element of $\mathbb{W}$, simplifies to $\frac{3x-4}{x-11}$, then the value of $k$ must be?

my work:
$$\frac{3x^2+kx-44}{x^2-121}= \frac{3x-4}{x-11}$$
so the answer = value of $k$ is $11$.
 [/INST] hint
If $$\frac{3x^2+kx-44}{x^2-121}=\frac{3x-4}{x-11}$$
Then, with $ x=1$, we get
$$\frac{3+k-44}{1-121}=\frac{1}{10}$$
and
$$k=-12+41=29$$
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