<s>[INST] Find the indicated derivative Find the indicated derivative
$\frac {d}{dt}$ $\frac {(6t-5)^6}{t+9}$ 
I'm stuck after getting to this part
$\frac {(6t-5)^6-36(6t-5)^5(t+9)}{(t+9)^2}$
How do they get to the answer
$\frac {(6t-5)^5(30t+329)}{(t+9)^2}$
 [/INST] \begin{align*}
\frac{d}{dt}\left(\frac{(6t-5)^6}{t+9} \right) & = \frac{6((6t-5)^5.6)(t+9)-(6t-5)^6}{(t+9)^2}\\
& = \frac{(6t-5)^5(36(t+9)-6t+5)}{(t+9)^2}\\
& = \frac{(6t-5)^5(30t+329)}{(t+9)^2}
\end{align*}
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