<s>[INST] Why does $\frac{(x^2 + x-6)}{x-2} = \frac{(x+3)(x-2)}{x-2}$? I'm not the best at algebra and would be grateful if someone could explain how you can get from, 
$$\frac{x^2 + x-6}{x-2}$$
to,
$$\frac{(x+3)(x-2)}{x-2}$$
 [/INST] All that was done was factoring the numerator. Notice that
$$
x^2+x-6=(x+3)(x-2)
$$
because $(x+3)(x-2)=x^2-2x+3x-6=x^2+x-6$. Then it follows that
$$
\frac{x^2+x+6}{x-2}=\frac{(x+3)(x-2)}{x-2}
$$
</s>