<s>[INST] Why does $\frac{(x^2 + x-6)}{x-2} = \frac{(x+3)(x-2)}{x-2}$? I'm not the best at algebra and would be grateful if someone could explain how you can get from, 
$$\frac{x^2 + x-6}{x-2}$$
to,
$$\frac{(x+3)(x-2)}{x-2}$$
 [/INST] Try working backwards. Notice that the denominator does not change, so let's focus on the numerator:
$$(x+3)(x-2) = x\cdot x-2x+3x-2\cdot 3 \,\,\,\,\,\,\text{FOIL}.$$
If we look at like terms (meaning equal powers of $x$), we see that we have two pieces that have $x$ that we can simplify: $-2x+3x = (-2+3)x = x.$ As for the other bits, we have $x\cdot x$ which we can simplify to $x^2$ and also $2\cdot 3 = 6$. This gives us
$$(x+3)(x-2) = x^2+x-6.$$
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