<s>[INST] integrate $\int \frac{x-3}{\sqrt{1-x^2}}$ 
$$\int \frac{x-3}{\sqrt{1-x^2}} \mathrm dx$$

I know that $\int \frac{1}{1-x^2}\mathrm dx=\arcsin(\frac{x}{1})$ but how can I continue from here? 
 [/INST] Two hints:


*

*$$\frac{x-3}{\sqrt{1-x^2}} = \frac{x}{\sqrt{1-x^2}} - \frac{3}{\sqrt{1-x^2}}$$

*You had it a bit wrong: $$\int\frac{1}{\sqrt{1-x^2}} = \arcsin(x)$$

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