<s>[INST] Finding $k$ such that $\frac{3x^2+kx-44}{x^2-121}$ simplifies to $\frac{3x-4}{x-11}$ 
If the rational expression $\frac{3x^2+kx-44}{x^2-121}$, where $k$ is an element of $\mathbb{W}$, simplifies to $\frac{3x-4}{x-11}$, then the value of $k$ must be?

my work:
$$\frac{3x^2+kx-44}{x^2-121}= \frac{3x-4}{x-11}$$
so the answer = value of $k$ is $11$.
 [/INST] Notice $x^2-121=(x+11)(x-11)$. Then we have
$$
3x^2+kx-44=(3x-4)(x+11)=3x^2+29x-44.
$$
So $k=29$
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