<s>[INST] How to Plot $\sqrt{\frac{a^2+(b-1)^2}{a^2+(b+1)^2}}=2$ How to plot this complex division?
$$
\sqrt{\frac{a^2+(b-1)^2}{a^2+(b+1)^2}}=2
$$
 [/INST] The plot of $\sqrt{\frac{a^2+(b-1)^2}{a^2+(b+1)^2}}=2$ is the following:

Work out $a^2+(b-1)^2$ and $a^2+(b+1)^2$. This will give: 
$$\frac{a^2+(b-1)^2}{a^2+(b+1)^2} = \frac{1-4b}{a^2+b^2+2 b+1}$$
This would make it easier to solve.
</s>