<s>[INST] Given $(m-2)x^2-4x+3=3-x^2+2nx$, compute the value of $m$ 
Given $$(m-2)x^2-4x+3=3-x^2+2nx$$ Compute the value of $m$.

$$(m-2)x^2-4x+3=3-x^2+2nx
\\mx^2+(-4m-4)x+7=-x^2+2nx+3
\\m=-1, n=0$$
The answer is $m=1,n=-2$, please tell me where did I go wrong 
 [/INST] Hint:
The coefficient of $x^2$ on the left of the equal sign is $(m-2)$ and on the right it is $-1$
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