<s>[INST] Find the indicated derivative Find the indicated derivative
$\frac {d}{dt}$ $\frac {(6t-5)^6}{t+9}$ 
I'm stuck after getting to this part
$\frac {(6t-5)^6-36(6t-5)^5(t+9)}{(t+9)^2}$
How do they get to the answer
$\frac {(6t-5)^5(30t+329)}{(t+9)^2}$
 [/INST] $${ \left[ \frac { (6t-5)^{ 6 } }{ t+9 }  \right]  }^{ \prime  }=\frac { 36{ \left( 6t-5 \right)  }^{ 5 }\left( t+9 \right) -(6t-5)^{ 6 } }{ { \left( t+9 \right)  }^{ 2 } } =\frac { { \left( 6t-5 \right)  }^{ 5 }\left[ 36\left( t+9 \right) -\left( 6t-5 \right)  \right]  }{ { \left( t+9 \right)  }^{ 2 } } =\frac { { \left( 6t-5 \right)  }^{ 5 }\left[ 30t+329 \right]  }{ { \left( t+9 \right)  }^{ 2 } } $$
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