<s>[INST] Evaluating an expression given values of symmetric polynomials Evaluate $\dfrac x{yz} + \dfrac y {xz} + \dfrac z y$
Given, $z+y+x=4, \qquad xyz=-60, \qquad xy+xz+yz=-17$
How do we do this? I found a common denominator, and substituted it for $-60$, but I am unaware of how to proceed. 
Someone already asked the question but there is no useful answer. These are the possible answers:
A.   $4/17$
B.   $−5/6$
C.   $17/60$
D.   $−33/60$
E.   $33/60$
 [/INST] \begin{align}
& \frac{x}{yz} + \frac{y}{xz} + \frac{z}{xy} = \frac{x^2 + y^2 + z^2}{xyz}
\end{align}
$x^2 + y^2 + z^2 = (x+y+z)^2 - 2(xy + xz +yz)$
so: \begin{align} \frac{x^2 + y^2 + z^2}{xyz} = \frac{(x+y+z)^2 - 2(xy + xz +yz)}{xyz} = \frac{16 - 2(-17)}{-60} = \frac{50}{-60} = -\frac{5}{6}
\end{align}
</s>