<s>[INST] Condensing logarithms 
Simplify:
  $2\log_{10}\sqrt{x}+3\log_{10}x^{\frac{1}{3}}$  

I got to this: $2\log_{10}x^{\frac{1}{2}}+3\log_{10}x^{\frac{1}{3}}$.  
Now, usually you bring the exponent the the front and that would yield:  
$$\frac{1}{2}(2)\log_{10}x+\frac{1}{3}(3)\log_{10}x=\log_{10}x+\log_{10}x=2\log_{10}x$$  
And that's it?
 [/INST] $$ \frac{1}{2}(2)\log_{10}x+\frac{1}{3}(3)\log_{10}x \neq 2\log_{10}x+3\log_{10}x$$
$1/2 * 2 = 1$ so do $1/3 * 3.$
So the correct thing is
$$\frac{1}{2}(2)\log_{10}x+\frac{1}{3}(3)\log_{10}x = \log_{10}x+\log_{10}x = 2\log_{10}x$$
Bring the exponent inside the $\log$ if you like.
The other way around: bring $1/2$ into $\log_{10} \sqrt{x}$ to become $\log_{10} \sqrt{x}^2 = ??.$ 
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