<s>[INST] Trouble understanding this Equality of Complex number question. I have this question here 
$$(3-2j)(x+yj)=4+j^9$$
I know that $a + bj$ and $x + yj$ are equal when $a = x$ and $b = y$.
This question is confusing me because I have had three different answers but they are all wrong. 
What feels like my closest attempt was:
$$(3-2j)(x+yj)=4+j^9.$$
$x + yj = (-3+2j)(4-j)$
$= -12 + 3j + 8j -2j^2$
$= -12 + 11j -2(-1)$
$= -12 + 11j + 2$
$= -10 + 11j \:\: \Rightarrow$
$x = -10$
$y = 11$
But the answer is supposed to be
$x = 10/13$ 
$y = 11/13$
I am just looking for some guidance on how to properly solve this and figure out where I went wrong. 
Thank you!
 [/INST] \begin{align*}(3-2i)(x+yi)=4+i^9&\Longleftrightarrow x+yi=\frac{4+i}{3-2i}\\&\Longleftrightarrow x+yi=\frac{(4+i)(3+2i)}{(3-2i)(3+2i)}\\&\Longleftrightarrow x+yi=\frac{10+11i}{13}=\frac{10}{13}+\frac{11}{13}i\\&\Longleftrightarrow x=\frac{10}{13}\text{ and }y=\frac{11}{13}\end{align*}
</s>