<s>[INST] Using antiderivative to calculate complex integral $$\int_{1}^{3}(z-2)^3 dz $$
I get the following -
$$\frac{1}{4}[(3-2)^3 - (1-2)^3] = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$$
However the answer sheet I have just show it reduced to $\frac{1}{4} - \frac{1}{4} = 0$
Cant see how they are getting a - instead of a +...what am I missing?
 [/INST] You should increase the power by 1 first to get:
$\frac{1}{4}[(3-2)^4 - (1-2)^4] = \frac{1}{4} - \frac{1}{4} = 0$
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