<s>[INST] Solving $\sqrt{(x-2)^2 + (y-1)^2} = \sqrt 2$ What is the answer of this:
$\sqrt{(x-2)^2 + (y-1)^2} = \sqrt 2$
 [/INST] $\textbf{Hint}$ : First, try to relate this to the pythagorean theorem. Also note.
$\sqrt{(x - 2)^2 + (y - 1)^2} = \sqrt{2}$
$(x - 2)^2 + (y - 1)^2 = 2$
Think about circles. 
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