<s>[INST] Solve $3\sin^2 x - \cos^2 x - 2 =0$ 
Find all the angles between $0$ and $360^\circ$ that satisfy $$3\sin^2 x - \cos^2 x - 2 =0$$ 

My attempt - 
$3\sin^2 x - (1-\sin^2x) - 2 =0$
$ 3 \sin^2 x  + \sin^2 x = 3 $
$4\sin^2 x = 3 $ 
$ \sin x= \frac{\sqrt{3}}{2} $ 
I found that $x= 60,120 $ 
Why is the answer for this $60,120,240,300$ ? How do I find 240 and 300? 
 [/INST] hint: $\sin x = -\dfrac{\sqrt{3}}{2}$ would lead to the other two angles.
</s>