<s>[INST] Limits and infinity minus infinity I understand that we need to rationalize when we have infinity minus infinity like here
$\lim_{x\to \infty}\left(\sqrt{x^2 + 1} - \sqrt{x^2 + 2}\right)$
My question is why can I not just split the limits like this
$\lim_{x\to \infty}\left(\sqrt{x^2 + 1}\right) - \lim_{x\to \infty}\left(\sqrt{x^2 + 2}\right)$
and then
$\lim_{x\to \infty}\sqrt{x^2} * \lim_{x\to \infty}\sqrt{1 + \frac 1x}  - \lim_{x\to \infty}\sqrt{x^2} * \lim_{x\to \infty}\sqrt{1 + \frac 2x}$
which gives
$\lim_{x\to \infty}\sqrt{x^2} - \lim_{x\to \infty}\sqrt{x^2} = 0$
because $\frac 1x$ and $\frac 2x$ tend to $0$
Where am i wrong ?
 [/INST] You can not subtract
$$
\lim_{x\to\infty}(\sqrt{x^2+1}-\sqrt{x^2+2})=\lim_{x\to\infty}\sqrt{x^2+1}-\lim_{x\to\infty}\sqrt{x^2+2},
$$
because the left hand side is $\infty-\infty$ which is not definable. 
Instead, you can obtain that
$$
\sqrt{x^2+1}-\sqrt{x^2+2}=\frac{(\sqrt{x^2+1}-\sqrt{x^2+2})(\sqrt{x^2+1}+\sqrt{x^2+2})}{\sqrt{x^2+1}+\sqrt{x^2+2}}\\ =\frac{(x^2+1)-(x^2+2)}{\sqrt{x^2+1}+\sqrt{x^2+2}}=-\frac{1}{\sqrt{x^2+1}+\sqrt{x^2+2}}\to 0,
$$
where the properties of limits apply.
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