<s>[INST] Factorize expression $(4a+3)^2-a^4$ The question is to factorize $(4a+3)^2-a^4.$
The answer I ended up with was $(4a+3-a^2)(4a+3-a^2).$ 
I got this by difference of two squares $\cdots.$
I would like to know if this is correct.
 [/INST] SIMPLE
The question was to factorize $(4a+3)^2-a^4.$
IF you use difference of two squares we will get
LET $4a+3$  be $X$ and $a^2$ be $Y$ 
the $X^2-Y^2$
WE GET
$(4a+3-a^2)(4a+3+a^2).$ 
UNDERSTOOD 
Further each of the quadratic equation can be factorised
$(x-1)(x-3)(x-/7+2)(x+/7+2)$
SO THE FINAL AWSER IS HERE
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