<s>[INST] Why does conversion from base $b_1$ to $b_2$ give this strange result in Wolfram Alpha? I was trying to convert the $5$-ary number $44444444_5$ to base $25$ using Wolfram Alpha:
44444444 from base 5 to base 25

Curiously, I got the result $0000_{25}$. 
Clearly, $0\times25^{3}+0\times25^{2}+0\times25^{1}+0\times25^{0}$ does not equal $44444444_5$. So why am I getting this result? Is this a bug?
 [/INST] It's not a bug, and it's not $0000$, it's $oooo$. $o$ being the symbol $o$ (the one between $n$ and $p$ in the alphabet).
The letter $o$ in base $25$ stands for the twenty-fourth "digit" ( the "digits" in base $25$ are $1,2,3,4,5,6,7,8,9,a,b,c,d,e,f,g,h,i,j,k,l,m,n,o$), which means it equals $24$ in base $10$, which means $$oooo_{25} = (24 + 24\cdot 25 + 24\cdot 25^2 + 24\cdot 25^3)_{10} = 390624_{10}$$
which fits well with the fact that
$$44444444_5 = (4+4\cdot 5 + 4\cdot 5^2+4\cdot 5^3+4\cdot 5^4+4\cdot 5^5+4\cdot 5^6+4\cdot 5^7)_{10} = 390624_{10}$$

Another way of seeing this (without calculating the number) is
$$\begin{align}44444444_5 &= 4\cdot(1+5+5^2+5^3+5^4+5^5+5^6+5^7)
\\& = 4\cdot((1+5)+(5^2+5^3)+(5^4+5^5)+(5^6+5^7))
\\& = 4\cdot(1+5+5^2(1+5) + 5^4(1+5)+5^6(1+5))
\\&= 4\cdot(6+6\cdot25+6\cdot25^2+6\cdot25^3)
\\&= 24 + 24\cdot 25 + 24\cdot 25^2 + 24\cdot 25^3
\\&= oooo_{25}\end{align}$$
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