<s>[INST] Differentiating $x^2 \sqrt{2x+5}-6$ How do I differentiate this function: f(x)= $x^2  \sqrt{2x+5}-6$
I had: I had $2x\sqrt{2x+5} + x^2  \dfrac{1}{2\sqrt{2x+5}}$ but the correction model said it was I had $2x\sqrt{2x+5} + x^2  \dfrac{2}{2\sqrt{2x+5}}$
 [/INST] Using the chain rule where $\cfrac {df}{dx} = \cfrac {dg}{du} \cfrac {du}{dx} $ if $f(x) = g(u(x))$ and the product rule where $\cfrac {d}{dx} (uv) = v\cfrac {du}{dx} + u\cfrac {dv}{dx} $
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