<s>[INST] Solving for $x$ from given equation Sorry for the trivial question. I was wondering if there was an easy way to solve this equation.
The equation is:
$$(x-1)(x-2)(x+3)(x-6)+36=0$$
I know this can be solved the traditional way, where after multiplying all terms, we could factorize the entire thing, but I ended up with a really messy equation. Is there a simpler method I'm missing?
Thanks for any help :-)
 [/INST] \begin{align*}
(x-1)(x-2)(x+3)(x-6)+36&=0\\
(x^2-3x+2)(x^2-3x-18)+36&=0\\
(x^2-3x)^2-16(x^2-3x)&=0\\
(x^2-3x)(x^2-3x-16)&=0\\
x&=0, 3\textrm{ or }\frac{3\pm\sqrt{73}}{2}
\end{align*}
</s>