<s>[INST] Find out the no of digits in product between some prime. How many digits are  there in?
$2^{17}*3^{2}*5^{14}*7$.  help me.
 [/INST] As André Nicolas has pointed out in the comments, 
$$2^{17}\times 5^{14} = 2^3\times 2^{14}\times 5^{14} = 2^3\times 10^{14} = 8\times 10^{14}.$$
Therefore, 
$$2^{17}\times 3^2\times 5^{14}\times 7 = 3^2\times 7\times 8\times 10^{14} = 504\times 10^{14} = 5.04\times 10^{16}.$$
So $2^{17}\times 3^2\times 5^{14}\times 7$ has $17$ digits.
</s>