<s>[INST] Divisibility 1,2,3,4,5,6,7,8,9,&10 Tried:
Seems the ten-digit number ends with $240$ or $640$ or $840$ (Is not true, there are more ways the number could end)
$8325971640,$
$8365971240,$
$8317956240,$
$8291357640,$
$8325971640,$
$8235971640,$
$1357689240,$
$1283579640,$
$1783659240,$
$1563729840,$
$1763529840,$
$1653729840,$
$7165239840,$
$7195236840,$
$2165937840,$
$9283579640$
 [/INST] The number which are divisible by $8$ is also divisible by $2$ and $4$.
The number which are divisible by $9$ is also divisible by $3$.
The number of which is divisible by $6$ is also divisible by $2$ and $3$.
The number which are divisible by $10$ is also divisible by $2$ and $5$.
Also also the number we expect is divisible by $11$ and $7$.
So the number is in the form $=P×2^{3i}×3^{2j}×5^k×7^m×11^n$, 
Where $i$, $j$, $k$, $m$, & $n$ are positive any positive integer and $P$ is any positive integer integer.Using this condition we will produce a required ten digit number. 
</s>