<s>[INST] Simplifying $\sqrt{4+2\sqrt{3}}+\sqrt{4-2\sqrt{3}}$ How do I simplify $\sqrt{(4+2\sqrt{3})}+\sqrt{(4-2\sqrt{3})}$?
I've tried to make it $x$ and square both sides but I got something extremely complicated and it didn't look right.  
I got $2\sqrt{3}$ on wolframalpha, but I'm not sure how is it possible?
Help would be appreciated!  Thanks!
 [/INST] \begin{align}
&\ \ \ \sqrt{4+2\sqrt{3}}+\sqrt{4-2\sqrt{3}}
\\
\\
&=\sqrt{(\sqrt{3}+1)^2}+\sqrt{(\sqrt{3}-1)^2}\
\\
\\
&=\sqrt{3}+1+\sqrt{3}-1
\\
\\
&=\boxed{2\sqrt{3}}
\end{align}
</s>