<s>[INST] Can I get a little integral help? Find the integral $$\int_0^3 \sqrt {y+1}\, dy$$
 [/INST] $$\int_0^{3} \sqrt{y+1} dy = \int_0^{3} (y+1)^{\frac{1}{2}}d (y + 1) = \frac{2}{3} \int_0^{3} \frac{3}{2}(y+1)^{\frac{1}{2}}d (y + 1) = \left. \frac{2}{3}(y+1)^{\frac{3}{2}} \right|_0^3 = \frac{2}{3} 4 ^{\frac{3}{2}} - \frac{2}{3}1^{\frac{3}{2}} = \frac{16}{3} - \frac{2}{3} = \frac{14}{3}$$
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