<s>[INST] Simplifying $\frac{2^{n + 4} + 2^{n + 2} + 2^{n - 1}}{2^{n - 2} + 2^{n - 1}}$ I'm stuck in the follow equation:
$$\dfrac{2^{n + 4} + 2^{n + 2} + 2^{n - 1}}{2^{n - 2} + 2^{n - 1}}$$
As all the bases are equal, I got $\dfrac{3n + 5}{2n - 3}$
Where I've to go now ?
Thanks
EDIT:
Then, my initial idea was totally wrong, starting again, in the right way I got:
$$\dfrac{2^n(2^4 + 2^2 + 2^{-1})}{2^n(2^{-2} + 2^{-1})}$$
but it's still wrong, I didn't get the right idea on the divisions you have shown to me in the answers.
 [/INST] You’ve nothing to solve. My guess is that you’re supposed to simplify the fraction:
$$\begin{align*}
\dfrac{2^{n + 4} + 2^{n + 2} + 2^{n - 1}}{2^{n - 2} + 2^{n - 1}}&=\frac{2^{n-1}(2^5+2^3+1)}{2^{n-2}(1+2)}\\
&=\frac{2^{n-1}}{2^{n-2}}\cdot\frac{32+8+1}{3}\;,
\end{align*}$$
and you should have no trouble finishing it.
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