<s>[INST] Need help with basic factoring equation I'm just trying to brush up on my factoring of quadratic equations.
$$\frac1{x+3} + \frac1{x^2 + 5x +6}$$
$$\frac1{x+3} + \frac1{(x+2)(x+3)}$$
$$\frac{(x+2)(x+3) + (x+3)}{(x+2)(x+2)(x+3)}$$
Then I'm stuck. I think you can factor out the $(x+2)(x+3)$ from top and bottom?
 [/INST] $$\begin{align}
&{1\over{x+3}}+{1\over{x^2+5x+6}}\to\\  
&{1\over{x+3}}+{1\over{(x+2)(x+3)}}\to\\
&{x+2+1\over{(x+2)(x+3)}}\to\\ 
&{x+3\over{(x+2)(x+3)}}\to\\
&1\over{x+2}
\end{align}$$
</s>