<s>[INST] How can I simplify $\sqrt{3^2 + 3^2\tan^2\theta}$? $$\sqrt{3^2 + 3^2\tan^2\theta}$$ 
$$ = (3)(3\tan\theta) = 9\tan\theta $$ 
I've simplified it like this but I'm not sure if that's correct. 
 [/INST] $$\begin{align} \sqrt{3^2 + 3^2\tan^2\theta} &= \sqrt{9(1+\tan^2 \theta)} \\ 
& = \sqrt 9 \cdot \sqrt {1 + \tan^2 \theta} \\ 
& = 3\sqrt{\sec^2\theta} \\
&= 3|\sec \theta| \end{align}$$
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