<s>[INST] Solve the following equation I need help to solve the following equation. 
$13x=4x^2$
My attempt: 
$13x=4x^2$
$4x^2-13x=0$
$\frac{4x^2-13x}{4}=0$
$x^2-\frac{13x}{4}+0=0$
$x=-\frac{-13}{2} \begin{matrix} + \\ - \end{matrix} \sqrt{(\frac{-13}{2})^2}$
this results to $x1 = 8.125$ $x2 = -4.875$
The correct result is $x1 = 0$ $x2 = 3.25$
Where did I go wrong with this?
Thanks!!
 [/INST] $13x=x^2$
If $x\neq 0$ we can divide both sides by $x$ to obtain:
$\frac{13x}{x}=\frac{4x^2}{x}\Rightarrow 13=4x$
Then we divide both sides by $4$ to obtain:
$x = \frac{13}{4}$.
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