<s>[INST] Non-Symmetric Algebraic inequality 
Let $a,b,c$ be positive real numbers. Prove that : $$\frac{ab}{3a+b}+\frac{bc}{2c+b}+\frac{ac}{c+2a}\le \frac{2a+20b+27c}{49}$$

 [/INST] Let $a=6x$, $b=3y$ and $c=2z$.
Hence, we need to prove that
$$\frac{xy}{6x+y}+\frac{yz}{3y+4z}+\frac{zx}{z+6x}\leq\frac{2x+10y+9z}{49},$$
which is true by AM-GM.
Indeed,
$$\frac{xy}{6x+y}+\frac{yz}{3y+4z}+\frac{zx}{z+6x}\leq\frac{x+6y}{49}+\frac{4y+3z}{49}+\frac{6z+x}{49}=\frac{2x+10y+9z}{49}.$$
Done!
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