<s>[INST] solve for $x$ and $y$ in the following equation $x^2 +y^2 -3=3xy$ and $2x^2 +y^2 =6$ Solve for $x$ and $y$ in the following equations: $x^2 +y^2 -3=3xy$ and $2x^2 +y^2 =6$. I made $y^2$ the subject of the formula in eqn 2.
This gives $y^2 = 6 -2x^2$.
I substitute this into the first eqn.
This gives $x^2+3xy -3$. There's where am stuck.
 Can someone pull me out.
 [/INST] multiplying the first equation by $-1$ and adding to the second we get
$$x^2+3xy=3$$ thus $$y=\frac{3-x^2}{3x}$$ if $$x\ne 0$$ and you can eliminate $y$
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