<s>[INST] solve for $x$: $(x^4-13x^2+36)^4+|x^2+x-6|+\sqrt{x^3-7x+6}=0$ There is an equation that I think it is complicated ,a little!
$$(x^4-13x^2+36)^4+|x^2+x-6|+\sqrt{x^3-7x+6}=0$$
Actually we must solve for $x$ here.
I want you to hint me how can I simplify the equation and solve it.
 [/INST] Hint:
The first expression is biquadratic and
$$x^4-13x^2+36=(x^2-4)(x^2-25).$$
The second is quadratic,
$$x^2+x-6=(x-2)(x+3).$$
The third is cubic and by inspection $x=1$ is a root. So
$$x^3-7x+6=(x-1)(x^2+x-6)=(x-1)(x-2)(x+3).$$
Now you need to find the common roots.
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