<s>[INST] Making sure I'm not doing something wrong I'm solving a matrix equation: $$2(A-B+X) = 3(X-A)$$
Where $A = \left( \begin{matrix} 1&2 \\ 3&4 \end{matrix} \right)$ and $B = \left( \begin{matrix} -1&0 \\ 1&1 \end{matrix} \right) $
So far I've done: $$2(A-B+x) = 3(X - A)$$ $$\Rightarrow 2 \left( \begin{matrix} 1&2 \\ 3&4 \end{matrix} - \begin{matrix} -1&0 \\ 1&1 \end{matrix} + X \right) = 3 \left( X - \begin{matrix} 1&2 \\ 3&4 \end{matrix} \right)$$
$$ \Rightarrow 2 \left( \begin{matrix} 2&2 \\ 2&3 \end{matrix} + X \right) = 3X - \begin{matrix} 3&6 \\ 9&12 \end{matrix}$$
$$\Rightarrow \begin{matrix} 4&4 \\ 4&6 \end{matrix} + 2X = 3X - \begin{matrix} 3&6 \\ 9&12 \end{matrix}$$
But I'm not sure if I can put it on this form, asssuming the 2 matrices form the matrix $C$ when added:
$$C + 2X = 3X$$ 
Because I remember something about watching out for positioning when subtracting two matrices..
Some help needed with the next step.
 [/INST] It might be more clear if you don't write out the elements until necessary.
$$2(A-B+X) = 3(X-A) \\
2A-2B+2X = 3X-3A \\
5A-2B = X$$
Matrices add and subtract normally; that is, $A+A = 2A, 10Q-8Q = 2Q, 3X-2X = X,$ etc.
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