<s>[INST] How to solve for $y$ in $x = \frac{\sqrt[3]{9y-5}}{\sqrt[3]{11}}$ I am trying to solve the following for $y$ but am lost. I tried to multiply by $\sqrt[3]{121}/\sqrt[3]{121}$ but don't think that is how to do it.
$$x = \frac{\sqrt[3]{9y-5}}{\sqrt[3]{11}}$$
 [/INST] $$x = \frac{\sqrt[3]{9y-5}}{\sqrt[3]{11}}$$
Cube both sides.
$$x^3=\frac{9y-5}{11}$$
Multiply both sides by $11$.
$$11x^3=9y-5$$
Add $5$ to both sides.
$$11x^3+5=9y$$
Divide both sides by $9$.
$$y=\frac{11x^3+5}{9}$$
Very easy.
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