<s>[INST] Find real solutions of polynomial How with you find the solutions to the following:
$\sqrt{3x+10}-\sqrt{x+2}=2$
This is what I tried so far:
$(\sqrt{3x+10}-\sqrt{x+2})^2=2$
$(3x+10)+(x+2)-2\sqrt{(x+2)(3x+10)}=2$
$2x+5-\sqrt{3x^2+16x+20}=0$
No I do not know where to go from here...
 [/INST] Hint:
$2x+5-\sqrt{3x^2+16x+20}=0\iff2x+5=\sqrt{3x^2+16x+20} \Longrightarrow\\(2x+5)^2=3x^2+16x+20.$
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