<s>[INST] How to determine $x$ and $y$ intercepts for $y = 4(x - 2)^2(x + 2)^3$ I need help to determine $x$ and $y$ intercepts for 
$$
y = 4(x - 2)^2(x + 2)^3
$$
I guess my first question is, do I need to get the equation into 
$$
ax^3 + bx^2 + cx + d 
$$
form before starting?
 [/INST] The x-intercepts can be calculated like this:
$$ y = 4(x - 2)^2(x + 2)^3 $$
$$ y = 0$$
$$ a \cdot b \cdot c = 0 \rightarrow a = 0 \vee b=0 \vee c=0 $$
$$ 4 = 0 \vee (x-2)^2 = 0 \vee (x+2)^3 = 0$$
$$ None \vee x = 2 \vee x \ -2$$
The y-intercept can be found by substituting $0$ for $x$ in $4(x - 2)^2(x + 2)^3$.
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