<s>[INST] Factorisation and hence ... Factorise $2x^2 + 8x + 6$ completely . Hence express 286 as the product of three prime factors .
Workings -
$2x^2 + 8x + 6
= 2(x^2 + 4x + 3)
=2(x+3)(x+1)$
How do I use my answer above to express 286 as the product of three prime factors ? 
Thanks in advance ...
 [/INST] You are right- $2x^2+8x+6=2(x+3)(x+1)$
Now, $2x^2+8x+6=286$ will give you $x=10$ 
So, $286=2(x+3)(x+1)=2\times 13 \times 11$
The prime factors are $2,13,11$
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