<s>[INST] Finding the distribution law Throwing a cube twice,
let $X$ be the sum of the two throws

Find the distribution law

My attempt
$$
\begin{array}{c|lcr}
 &2&3&4&5&6&7&8&9&10&11&12 \\
\hline
\text{P}_\text{X}(x) & 1/12 & 1/12 & 1/12&1/12&1/12&1/12&1/12&1/12&1/12&1/12&1/12 \\
\end{array}
$$
But shouldn't the sum be $1$? Currently the sum is $11/12$
 [/INST] \begin{array}{c|lcr}
 &2&3&4&5&6&7&8&9&10&11&12 \\
\hline
\text{P}_\text{X}(x) & 1/36 & 2/36 & 3/36&4/36&5/36&6/36&5/36&4/36&3/36&2/36&1/36 \\
\end{array}
Now the sum is $1$.
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