<s>[INST] Solving for $x$ in $x + \frac{s}{s^2+4} = \frac{2x}{s^2+4}$ How would I go about solving for $x$ in this equation?
$$x + \frac{s}{s^2+4} = \frac{2x}{s^2+4}$$
 [/INST] $$x+\frac{s}{s^2+4}=\frac{2x}{s^2+4}$$
$$\frac{s^2x+4x+s}{s^2+4}=\frac{2x}{s^2+4}$$
For real $s$, $s^2+4\ne0$. Hence,
$$s^2x+4x+s=2x$$
$$x(s^2+2)+s=0$$
$$x=-\frac{s}{s^2+2}$$
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