<s>[INST] $\sqrt[5]{2^4\sqrt[3]{16}} = ? $ $$\sqrt[5]{2^4\sqrt[3]{16}} = ? $$
Rewriting this and we have
$$\sqrt[5\cdot 3]{2^{4\cdot 3}4}$$
$$\sqrt[15]{2^{12}2^2}$$
Finally we get
$$\sqrt[15]{2^{12}2^2} = \sqrt[15]{2^{14}} = 2^{\frac{15}{14}}$$
Am I right?
 [/INST] $$\sqrt[5]{2^4\sqrt[3]{16}} = (2^4)^{1/5}(16^{1/3})^{1/5}=2^{4/5}(2^4)^{1/15}=2^{4/5}2^{4/15}=2^{16/15}$$
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