<s>[INST] Here are two fractions, $\frac{2}{3}$,$\frac{7}{8}$, which of these fractions are closer to $\frac{3}{4}$? I've been throwing this question around my family. No one has a clue, therefore can someone help?
I'm pretty sure this will be easy to do 
 [/INST] The distance between real numbers $x$ and $y$ is $|x-y|$. So the distance from $\frac{2}{3}$ to $\frac{3}{4}$ is
\begin{align*}
\Big|\frac{2}{3}-\frac{3}{4}\Big|=\Big|\frac{8}{12}-\frac{9}{12}\Big|=\frac{1}{12}.
\end{align*}
And the distance from $\frac{7}{8}$ to $\frac{3}{4}$ is
\begin{align*}
\Big|\frac{7}{8}-\frac{3}{4}\Big|=\Big|\frac{7}{8}-\frac{6}{8}\Big|=\frac{1}{8}.
\end{align*}
Since $\frac{1}{12}<\frac{1}{8}$, then $\frac{2}{3}$ is closer to $\frac{3}{4}$ than $\frac{7}{8}$ is.
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