<s>[INST] Solve system equation $\left\{ \begin{array}{l} xy - x - y = 1\\ 4{x^3} - 12{x^2} + 9x = - {y^3} + 6y + 7 \end{array} \right.$ Solve system equation : $$\left\{ \begin{array}{l}  xy - x - y = 1\\  4{x^3} - 12{x^2} + 9x =  - {y^3} + 6y + 7  \end{array} \right. ,\quad (x,y\in\mathbb{R}).$$
My solution begin with : Set $z=x-1$ we have : $$\left\{ \begin{array}{l}  yz=z+2\\  4z^3-3z+y^3-6y-6=0  \end{array} \right.\Leftrightarrow \left\{ \begin{array}{l}  yz=z+2\\  4z^3-3y^2z+y^3=0  \end{array} \right.$$
I want to have a difference solution.
 [/INST] Using the straightforward approach, I find $x=\frac {y+1}{y-1} $ from the first equation and substitute it in the second one $$\frac {{y}^{6}-3\,{y}^{5}-3\,{y}^{4}+11\,{y}^{3}-6\,{y}^{2}+32}{
 \left( y-1 \right) ^{3}}=0.
 $$  The keypoint is the next step $$y^6-3y^5-3y^4+11y^3-6y^2+32 =(y^2-y+2)(y^2-y-4)^2.$$ The rest is quite simple: $$ \left \{ y=\frac 1 2 \pm \frac {\sqrt{7}i } 2, x= \frac {\frac 1 2 \pm \frac {\sqrt{7}i } 2 +1} {\frac 1 2 \pm \frac {\sqrt{7}i } 2 -1}\right \} $$ or $$\left\{ x=5/4-1/4\,\sqrt {17},y=1/2-1/2\,\sqrt {17} \right\}  $$ or $$ \left\{ x=5/4+1/4\,\sqrt {17},y=1/2+1/2\,\sqrt {17} \right\} .$$ 
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