<s>[INST] Integrate $\int\frac{dx}{2x^3-6x+4}$ I need some help with the following indefinite integral
$$\int\frac{dx}{2x^3-6x+4}$$
 [/INST] Hint: $$\Large \frac{1}{2x^3-6x+4} \equiv \frac{1}{18(x+2)}-\frac{1}{18(x-1)}+\frac{1}{6(x-1)^2}$$

You can check this identity by factorising $2x^3-6x+4$ as $2(x+2)(x-1)^2.$
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