<s>[INST] Solve the inequality $x^2 - 3 > 0$ For the inequality $x^2 - 3 > 0$, we have 
\begin{align} x^2 - 3 & = (x+\sqrt 3)(x- \sqrt 3) > 0 \end{align}
Therefore,
\begin{align} x > -\sqrt 3 \end{align}
and
\begin{align} x > \sqrt 3 \end{align}
But, this is clearly wrong as we should get $x < -\sqrt 3$ and $x > \sqrt 3$ as the two intervals. What have I done wrong?
 [/INST] HINT
Remember $ab > 0$ if $a,b > 0$ or $a,b < 0$
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