<s>[INST] Solve $\int\frac{8x+9}{(2x+1)^3}\,dx$. Do I split  $\displaystyle\int\frac{8x+9}{(2x+1)^3}\,dx$  into partial fractions? Or do I use $(2x+1)^{-3}$ by itself? Not sure what to do. Please advice. 
The answer given is $\dfrac{-16x+13}{4(2x+1)^2} +C$
 [/INST] Hint
$$\frac{8x+9}{(2x+1)^3} = \frac{4(2x+1)}{(2x+1)^3}+\frac5{(2x+1)^3} = \frac{4}{(2x+1)^2}+\frac5{(2x+1)^3}$$
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