Pulsar star. The neutron star retains most of its angular momentum, and since it has only a tiny fraction of its progenitor's radius (and therefore its moment of inertia is sharply reduced), it is formed with very high rotation speed. A beam of radiation is emitted along the magnetic axis of the pulsar, which spins along with the rotation of the neutron star. The magnetic axis of the pulsar determines the direction of the electromagnetic beam, with the magnetic axis not necessarily being the same as its rotational axis. This misalignment causes the beam to be seen once for every rotation
Direct integration of a beam load having an effect on the beam is the 75 kN load applied by the pin, applied at x=0, giving Integrating the internal shear, Assuming an EI value of 1 kNformula_15mformula_15m (for simplicity, real EI values for structural members such as steel are normally greater by powers of ten) Because of the vertical supports at each end of the beam, the displacement (formula_19) at x = 0 and x = 15m is zero. Substituting (x = 0, v(0) = 0) and (x = 15m, v(15m) = 0), we can solve for constants formula_20=-1406.25 and formula_21=0, yielding For the given EI