Clock angle problem through 360° in 60 minutes or 6° per minute. where: where: The time is 5:24. The angle in degrees of the hour hand is: The angle in degrees of the minute hand is: The angle between the hands can be found using the following formula: where If the angle is greater than 180 degrees then subtract it from 360 degrees. The time is 2:20. The time is 10:16. The hour and minute hands are superimposed only when their angle is the same. 10:54., and 12:00. Clock angle problem Clock angle problems are a type of mathematical problem which involve finding
Helix angle the helix angle. The efficiency can be plotted versus the helix angle for a constant friction, as shown in the adjacent diagram. The maximum efficiency is a helix angle between 40 and 45 degrees, however a reasonable efficiency is achieved above 15°. Due to difficulties in forming the thread, helix angle greater than 30° are rarely used. Moreover, above 30° the friction angle becomes smaller than the helix angle and the nut is no longer self-locking and the mechanical advantage disappears. In helical and worm gears, the helix angle denotes the standard pitch circle unless otherwise specified. Application of the