Clock angle problem through 360° in 60 minutes or 6° per minute. where: where: The time is 5:24. The angle in degrees of the hour hand is: The angle in degrees of the minute hand is: The angle between the hands can be found using the following formula: where If the angle is greater than 180 degrees then subtract it from 360 degrees. The time is 2:20. The time is 10:16. The hour and minute hands are superimposed only when their angle is the same. 10:54., and 12:00. Clock angle problem Clock angle problems are a type of mathematical problem which involve finding
Angle trisection and the mark on the line is labeled . This ensures that . A radius is drawn to make it obvious that line segments , , and all have equal length. Now, triangles and are isosceles, thus (by Fact 3 above) each has two equal angles. Hypothesis: Given is a straight line, and , , and all have equal length, Conclusion: angle . Proof: Clearing, , or , and the theorem is proved. Again, this construction stepped outside the framework of allowed constructions by using a marked straightedge. Thomas Hutcheson published an article in the Mathematics Teacher that used a