Determination of the day of the week Correction for Leap Year gives "3". Answer, "Wednesday". Since 23 February 1676 (counting February as the second month) is, for Carroll, the same day as Gregorian 4 March 1676, he fails to arrive at the correct answer, namely "Friday," for an Old Style date that on the Gregorian calendar is the same day as 5 March 1677. Had he correctly assumed the year to begin on the 25th of March, his method would have accounted for differing year numbers - just like George Washington's birthday differs - between the two calendars. It is noteworthy that those who have republished Carroll's
Determination of the day of the week that for large years it may be possible to subtract 6300 or a multiple thereof before starting so as to reach a year which is within or closer to the table. To look up the weekday of any date for any year using the table, subtract 100 from the year, divide the difference by 100, multiply the resulting quotient (omitting fractions) by seven and divide the product by nine. Note the quotient (omitting fractions). Enter the table with the Julian year, and just before the final division add 50 and subtract the quotient noted above. Example: What is the day