1912 United States presidential election in Rhode Island 1912 United States presidential election in Rhode Island The 1912 United States presidential election in Rhode Island took place on November 5, 1912, as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island was won by the Republican nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall. Wilson and Marshall defeated incumbent President William Howard Taft, and his running mate Vice President James S. Sherman and Progressive Party candidates, former President
Presidency of William Howard Taft all (22), performance with context of times (24). A 2018 poll of the American Political Science Association's Presidents and Executive Politics section ranked Taft as the 25th best president. Official Speeches Media coverage Other Presidency of William Howard Taft The presidency of William Howard Taft began on March 4, 1909, at noon Eastern Standard Time, when William Howard Taft was inaugurated as President of the United States, and ended on March 4, 1913. Taft, a Republican, was the 27th United States president. The protégé and chosen successor of incumbent President Theodore Roosevelt, he took office after easily defeating Democrat William