1912 United States presidential election in Rhode Island 1912 United States presidential election in Rhode Island The 1912 United States presidential election in Rhode Island took place on November 5, 1912, as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island was won by the Republican nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall. Wilson and Marshall defeated incumbent President William Howard Taft, and his running mate Vice President James S. Sherman and Progressive Party candidates, former President
William Howard Taft the issue. In the end, Taft won by a comfortable margin. Taft defeated Bryan by 321 electoral votes to 162; however, he garnered just 51.6 percent of the popular vote. Nellie Taft said regarding the campaign, "There was nothing to criticize, except his not knowing or caring about the way the game of politics is played." Longtime White House usher Ike Hoover recalled that Taft came often to see Roosevelt during the campaign, but seldom between the election and Inauguration Day, March 4, 1909. Taft was sworn in as president on March 4, 1909. Due to a winter storm that