1912 United States presidential election in Rhode Island 1912 United States presidential election in Rhode Island The 1912 United States presidential election in Rhode Island took place on November 5, 1912, as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island was won by the Republican nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall. Wilson and Marshall defeated incumbent President William Howard Taft, and his running mate Vice President James S. Sherman and Progressive Party candidates, former President
1912 United States presidential election in Mississippi one of the states in the 1912 United States presidential election where the sitting U.S. president William Howard Taft came in fourth place due to the hatred of the Republican Party in the south. 1912 United States presidential election in Mississippi The 1912 United States presidential election in Mississippi took place on November 5, 1912, as part of the 1912 United States presidential election. Mississippi voters chose seven representatives, or electors, to the Electoral College, who voted for president and vice president. Mississippi was won by the Princeton University President Woodrow Wilson (D–Virginia), running with governor of Indiana Thomas R.