1912 United States presidential election in Rhode Island 1912 United States presidential election in Rhode Island The 1912 United States presidential election in Rhode Island took place on November 5, 1912, as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island was won by the Republican nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall. Wilson and Marshall defeated incumbent President William Howard Taft, and his running mate Vice President James S. Sherman and Progressive Party candidates, former President
1912 United States presidential election 1912 United States presidential election The United States presidential election of 1912 was the 32nd quadrennial presidential election, held on Tuesday, November 5, 1912. Democratic Governor Woodrow Wilson of New Jersey unseated incumbent Republican President William Howard Taft and defeated former President Theodore Roosevelt, who ran as the Progressive Party ("Bull Moose") nominee. Roosevelt remains the only third party presidential candidate in U.S. history to finish better than third in the popular or electoral vote. Roosevelt had served as president from 1901 to 1909, and Taft had won the 1908 Republican presidential nomination with Roosevelt's support. Displeased with Taft's actions