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For fluorine it is 2 s 2, 2 p 5, for chlorine 3 s 2, 3 p 5 for bromine 4 s 2, 4 p 5, and for iodine it is 5 s 2, 5 p 5. In short, all the halogens have 7 electrons at the outermost quantum level or 5 electrons in the outermost p orbitals.
Best Answer: Boron has 3 electrons Each fluorine has 7 electrons 3(7) + 1(3) = 24 Draw the structure with boron in the middle and three fluorines with single bonds. Each bond = 2 electrons. Then put electron pairs around the fluorine atoms to satisfy their octet rules.