In the case $g(x)=x$, this reduces to the familiar formula for the derivative of $f(x)$ with respect to $x$, $$\lim_{h\to0}{f(x+h)-f(x)\over h}$$ In the case where $g(x)$ is a constant, the denominator $g(x+h)-g(x)$ is identically zero, so the limit n'existe pas.hat I would like to understand is: Why does (derivative with respect to x) make sense but $(\text{derivative with respect to} (\lambda x \to 2))$ and. $(\text{derivative with respect to} (\lambda x \to \ln(x)) $ do not seem to make any sense to me.
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GED test scores and an official copy of the. high school transcript (if applicable) Purdue University International Undergraduate Admissions, West Lafayette, IN 1939 likes Â· 5.Final high school transcripts are.igh School Transcripts High school students who apply to Purdue must provide an official high school transcript, which should include coursework and grades. High School Transcripts High school students who apply to Purdue must provide an official high school transcript, which should include coursework and grades.