In the case $g(x)=x$, this reduces to the familiar formula for the derivative of $f(x)$ with respect to $x$, $$\lim_{h\to0}{f(x+h)-f(x)\over h}$$ In the case where $g(x)$ is a constant, the denominator $g(x+h)-g(x)$ is identically zero, so the limit n'existe pas.hat I would like to understand is: Why does (derivative with respect to x) make sense but $(\text{derivative with respect to} (\lambda x \to 2))$ and. $(\text{derivative with respect to} (\lambda x \to \ln(x)) $ do not seem to make any sense to me.
Purdue University's programs in engineering, education and business have also been ranked among the best in the country in U.S.News & World Report's 2016 graduate school rankings. Engineering: Purdue's College of Engineering was ranked No. 6 in the country, and Purdue lands at #4 on the list of the Best Online Graduate Engineering Programs.
Purdue President Mitch Daniels said some of the difference is made up by out-of-state and international students, who pay nearly $29,000 and $31,000, respectively, per year for tuition. That's compared to $10,002 paid by Indiana residents.