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So O2 has zero of heat of formation (or enthalpy of formation). The enthalpy of a reaction is defined like this: H = Hproducts-H reactants. The enthalpy of reaction in this case, is the same as the heat of combustion. Hproducts is obtained summing the heats of formation.
(c) The heat of combustion of propane is -2,220.1 kJ/mol. Calculate the heat of formation, ïHfï°, of propane given that ïHfï° of H2O(l) = -285.3 kJ/mol and ïHfï° of CO2(g) = -393.5 kJ/mol.(d) Assuming that all of the heat evolved in burning 60.0 grams of propane is transferred to 8000 grams of water (specific heat = 4.18 J/g.alculate the heat of formation, ïHfï°, of propane given that ïHfï° of H2O(l) = -285.3 kJ/mol and ïHfï° of CO2(g) = -393.5 kJ/mol. (d) Assuming that all of the heat evolved in burning 60.0 grams of propane is transferred to 8000 grams of water (specific heat = 4.18 J/g.