2. a style of dance music marked by some of the features of jazz.
The graph of y = 2x+1 is a straight line. 1  When x increases, y increases twice as fast, hence 2x. 2  When x is 0, y is already 1.  So: y = 2x + 1.
We have to choose what is the equation of the function on the graph. We know the parent function: f(x) = log(2) x ( log base 2 ). The new function should be in the form: f(x) = log(2) ( x - a ) + b. The new vertical asymptote is : x = -3, So: a = -3. Now we have: f (x) = log(2)( x + 3 ) + b. After that we will substitute the values of coordinates of the point ( - 5 , - 2 ) which belong to this function. - 5 = log(2) ( - 2 + 3 ) + b. - 5 = log (2) 1 + b ; - 5 = 0 + b; b = - 5. Answer: The equation of the function shown in the graph is: A ) f (x) = log(2) ( x + 3 ) - 5 .