11 21 readSystem Call NAMEread-read from a file descriptorSYNOPSISint read(int fd, void *buf, int count);DESCRIPTIONread() attempts to read up to count bytes from file descriptor fdinto the buffer starting at buf.If count is zero, read() returns zero and has no other results.
If you're talking about the actual time it takes to physically run a 5k (and not how long it would take to train for one), it's about 30 minutes. 5k is around 3.1 miles, so if â¦ you average 10 minutes per mile, it's 30 minutes total.3 people found this useful.f you're talking about the actual time it takes to physically run a 5k (and not how long it would take to train for one), it's about 30 minutes. 5k is around 3.1 miles, so if â¦ you average 10 minutes per mile, it's 30 minutes total. 3 people found this useful.
So, if you could run a mile in m minutes, and the â¦ time you could run 5 miles was x, you would just take the proportion: 1 mile = 5 miles m x Let's assume m is 8.5 min. 1 mile = 5 miles 8.5 min. x min.1 times x is 1x 8.5 times 5 is 42.5 1x divided by one is x 42.5 divided by 1 is 42.5 Therefore, 42 minutes 30 seconds is the average time it takes someone to run five miles.nswer   If you could do it in an hour that would be good. 55 minutes is better. '       ANSWER:   Let's say that the average person will probably run a s â¦ peed of 6 mph, or one mile every 10 minutes.