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The electronic configuration for the oxygen atom is [math]1s^2 2s^2 2p^4[/math]. It must acquire 2 electrons to become an ion with a charge of -2 . Thus the electronic configuration for an [math]O^{2 -}[/math] ion is
Hydrogen - 1 valence electron Sulfur - 6 valence electrons Oxygen - 6 valence electrons H+H+S+O+O+O+O = 1+1+6+6+6+6+6 = 32 You get the valence electrons from the roman nâ¦umeral above each column in the periodic table.