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The electronic configuration for the oxygen atom is [math]1s^2 2s^2 2p^4[/math]. It must acquire 2 electrons to become an ion with a charge of -2 . Thus the electronic configuration for an [math]O^{2 -}[/math] ion is
Best Answer: Order of electron configuration is: 1s2 2s2 2p56 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2. N has 7 electrons: 1s2 2s2 2p3. Mg has 12 electrons: 1s2 2s2 2p6 3s2.