Armed robbers steal thousands from Grass Valley auto store Nevada County citizen marijuana group gives final thoughts to supervisors Placer County: Three juveniles at-large in alleged felony assault investigation
If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
It is one liter of solution not one liter of water.. Be careful on this, especially when you get to molality. The most typical molarity problem looks like this: What is the molarity of whatever grams of whatever substance dissolved in whatever mL of solution. To solve it, you convert grams to moles, then divide by the volume, like this: The two steps just mentioned can be combined into one equation.