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If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
Answers. Best Answer: Molarity is moles/L, molar mass if g/mol, and there are 1000 mL in a L. To get g/mL, follow these steps Molarity (moles/L) x molar mass (g/mole) x (1 L/1000 mL) Do that for each of your test tubes and you will have the answers you need. Source(s):