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If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
The formula for molality is m = moles of solute / kilograms of solvent. In problem solving involving molality, we sometimes need to use additional formulas to get to the final answer. One formula we need to be aware of is the formula for density, which is d = m / v, where d is density, m is mass and v is volume.