Armed robbers steal thousands from Grass Valley auto store Nevada County citizen marijuana group gives final thoughts to supervisors Placer County: Three juveniles at-large in alleged felony assault investigation
If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
This is how to do it: First, you have to get the molarity of the solution. Recall that Molarity = mol solute / L solution The unit of molarity is M, which stands for mol/L. You have to convert 0.274 g NaCl to moles by dividing the amount by its molar mass.0.274 g NaCl * 1 mol NaCl / 58.5 g NaCl = 0.00468 mol NaCl Then convert the volume to Liters. 10 mL is equal to 0.01 L. Get the molarity.ecall that Molarity = mol solute / L solution The unit of molarity is M, which stands for mol/L. You have to convert 0.274 g NaCl to moles by dividing the amount by its molar mass. 0.274 g NaCl * 1 mol NaCl / 58.5 g NaCl = 0.00468 mol NaCl Then convert the volume to Liters. 10 mL is equal to 0.01 L. Get the molarity.