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If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
Boy, does it! The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution. This is probably easiest to explain with examples. Example #1: Suppose we had 1.00 mole of sucrose (it's about 342.3 grams) and proceeded to mix it into some water.It would dissolve and make sugar water.oy, does it! The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution. This is probably easiest to explain with examples. Example #1: Suppose we had 1.00 mole of sucrose (it's about 342.3 grams) and proceeded to mix it into some water.