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If we assume that the density of the solution is almost equal to that of pure water (1 kg/L), then we find that 1 L of solution will weigh 1 kg. If 1 kg of solution contains 0.0001 M of sucrose , then it is 0.0001 m in sucrose, so the molarity and molality are almost the same. I think they are numerically the same to several decimal places.
1 Molality is given the symbol m. 2  molality = moles of solute &divide mass of solvent in kilograms. & 3 nbsp &nbsp m = n(solute) &divide mass(solvent). 4  A solution containing 3 moles of solute per kilogram of solvent for example, is said to be 3-molal or 3m. molality = moles of solute &divide mass of solvent in kilograms. & 2 nbsp &nbsp m = n(solute) &divide mass(solvent). 3  A solution containing 3 moles of solute per kilogram of solvent for example, is said to be 3-molal or 3m.