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Method. 1) Work out the concentration in grams per dm3. 1 litre = 1 dm3 = 1000 cm3. 10Â·6 g of sod ium carbonate in 200 cm3 is equivalent to 10Â·6 x (1000 Ã· 200) g of sod ium carbonate in 1000 cm = 53 g per dm3. 2) Convert grams per dm3 into mol / dm3.To convert mass into moles use moles = mass Ã· RFM. RFM of ammonium nitrate (NH4NO3) is (1 x 14) + (4 x 1) + (1 x 14) + (3 x 16) = 80. moles = 120 Ã· 80 = 1Â·5. So, 120 g of ammonium nitrate dissolved in 1 litre of water = 1Â·5 mol / dm3. Example 2.) Convert grams per dm3 into mol / dm3. To convert mass into moles use moles = mass Ã· RFM. RFM of sod ium carbonate (Na2CO3) is (2 x 23) + (1 x 12) + (3 x 16) = 106. moles = 53 Ã· 106 = 0Â·5. So, 10Â·6 g of sod ium carbonate in 200 cm3 of water = 0Â·5 mol / dm3.
Remember that 1 dm3 = 1 000 cm3 so the volume is also 12 000 cm3. The equation can be rearranged to find the number of moles, if the volume of gas at rtp is known: number of moles = volume of gas at rtp Ã· 24. Calculate the number of moles of hydrogen that occupy 6 dm3 at rtp. number of moles = 6 Ã· 24 = 0.25 mol.