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Method. 1) Work out the concentration in grams per dm3. 1 litre = 1 dm3 = 1000 cm3. 10Â·6 g of sod ium carbonate in 200 cm3 is equivalent to 10Â·6 x (1000 Ã· 200) g of sod ium carbonate in 1000 cm = 53 g per dm3. 2) Convert grams per dm3 into mol / dm3.To convert mass into moles use moles = mass Ã· RFM. RFM of ammonium nitrate (NH4NO3) is (1 x 14) + (4 x 1) + (1 x 14) + (3 x 16) = 80. moles = 120 Ã· 80 = 1Â·5. So, 120 g of ammonium nitrate dissolved in 1 litre of water = 1Â·5 mol / dm3. Example 2.) Convert grams per dm3 into mol / dm3. To convert mass into moles use moles = mass Ã· RFM. RFM of sod ium carbonate (Na2CO3) is (2 x 23) + (1 x 12) + (3 x 16) = 106. moles = 53 Ã· 106 = 0Â·5. So, 10Â·6 g of sod ium carbonate in 200 cm3 of water = 0Â·5 mol / dm3.
Calculate the molarity, M, of the following solutions: 1.5 moles of NaC2H3O2 dissolved in 750 ml of solution. 3.00 moles of H2SO4 dissolved in 1250 ml of solution. 66 grams of NaC2H3O2 dissolved in 500 ml of solution.olarity (M), molality (m) and the Colligative properties. The molarity of a solution is the number of moles of solute per liter of solution. The symbol for molarity is M. Thus a 3.0 molar solution of nitric acid, abbreviated 3.0 M HNO3, contains 3.0 moles of HNO3 per liter of solution.