Best Answer: Ok, since the kinetic energy of a mass travelling at a constant velocity v is KE=(1/2)mv^2 we can see what happens when we double v. KE(v)=(1/2)mv^2. KE(2v)=(1/2)m(2v)^2. KE(2v)=(1/2)m(4)v^2. KE(2v)=4(1/2)v^2.
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